SOLUTION: find four consecutive odd integers such that the sum of the first and fourth is 55 greater than the opposite of the third

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Question 137749: find four consecutive odd integers such that the sum of the first and fourth is 55 greater than the opposite of the third
Answer by solver91311(24713) About Me  (Show Source):
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First odd integer: x
2nd odd integer: x + 2
3rd odd integer: x + 4
4th odd integer: x + 6

Sum of the 1st and the 4th: x + (x + 6) = 2x + 6

Opposite of the 3rd: -(x + 4)

The sum of the 1st and 4th (2x + 6) is (=) 55 greater than (+55) the opposite of the 3rd (-(x+4)), so: 2x%2B6=-%28x%2B4%29%2B55

Solve that equation for x to give you the first one, and the others follow.