SOLUTION: Please help me with the setup of this formula: Find four consecutive odd integers such that the product of -3 and the sum of the first and fourth is 30 less than 10 times the oppo

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Please help me with the setup of this formula: Find four consecutive odd integers such that the product of -3 and the sum of the first and fourth is 30 less than 10 times the oppo      Log On


   

Question 136050: Please help me with the setup of this formula: Find four consecutive odd integers such that the product of -3 and the sum of the first and fourth is 30 less than 10 times the opposite of the third.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Four consecutive odd numbers, x, (x+2), (x+4), (x+6)
:
Write an equation for what it says here:
Find four consecutive odd integers such that the product of -3 and the sum of the first and fourth is 30 less than 10 times the opposite of the third.
:
opposite just means you change the sign of the number
:
-3(x+(x+6)) = 10(-(x+4)) - 30
:
-3(2x+6) = 10(-x - 4) - 30
:
-6x - 18 = -10x - 40 - 30
:
-6x + 10x = - 40 - 30 + 18
:
4x = -52
x = %28-52%29%2F4
x = -13
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the four numbers: -13, -11, -9, -7
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Check solution in the given statement
"the product of -3 and the sum of the first and fourth is 30 less than 10 times the opposite of the third."
-3(-13 -7) = 10(9) - 30
-3(-20) = 90 - 30
+60 = + 60; confirms our solution