SOLUTION: Find two consecutive integers such that 3 times the first integer plus 2 times the second integer is equal to 107.

SOLUTION: Find two consecutive integers such that 3 times the first integer plus 2 times the second integer is equal to 107.

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Question 135408: Find two consecutive integers such that 3 times the first integer plus 2 times the second integer is equal to 107.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET X= THE FIRST INTEGER
LET X+1=THE NEXT NUMBER
3X+2(X+1)=107
3X+2X+2=107
5X=107-2
X=105
X=105/5
X=21 IS THE FIRST INTEGER.
21+1=22 IS THE NEXT NUMBER.
PROOF
3*21+2*22=107
63+44=107
107=107

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