SOLUTION: The second of three numbers is one less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The second of three numbers is one less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers      Log On


   



Question 1198539: The second of three numbers is one less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let the first number be x
if the second number is one less than the first, the second number is
x-1
if the third number is 5 less than twice the second, the third number is 2%28x-1%29-5=2x+-+7
if the third number exceeds the first number by 12, the third number is x%2B12
then
2x+-+7=x%2B12
2x+-+x=7%2B12
x=19
x-1=19-1=18
x%2B12=19%2B12=31
the three numbers are:
19
18
31