Question 1155803: The sum of 39 consecutive number is 1170, what is the largest of these 39 number could be? Found 3 solutions by greenestamps, josmiceli, MathTherapy:Answer by greenestamps(13203) (Show Source):
The sum of 39 consecutive integers is 1170, what is the largest of these 39 integers?
(If the sum of 39 consecutive integers is 1170, then there is only one integer that the largest one can be.)
The sum of the 39 integers is 1170; the average is 1170/39 = 30.
In a set of consecutive integers, the one in the middle is the average.
In a set of 39 consecutive integers, there is a middle number, with 19 larger integers and 19 smaller. So the smallest of the 39 integers is 30-19 = 11 and the largest is 30+19 = 49.
You can put this solution on YOUR website! Let be the first of the 39 consecutive numbers is the 39th of the consecutive numbers
1 through are the numbers preceding the 39
consecutive numbers
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The sum of the numbers is:
The sum of the 1 through numbers is:
Let the sum of the 39 consecutive numbers be
and
49 is the largest number
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check:
OK
Definitely get a 2nd opinion if needed
Being consecutive numbers, this is an A.P.
With the equation for the sum of an A.P. series being: , we get:
1st term, or
nth term of an A.P.: ------ Substituting 39 for n, 11 for , and 1 for d
Last/Largest term/number, or
