SOLUTION: Find 4 consecutive even integers such that the product of -2 and the sum of the 1st and the 4th is 20 less than the opposite of the 3rd.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find 4 consecutive even integers such that the product of -2 and the sum of the 1st and the 4th is 20 less than the opposite of the 3rd.      Log On


   

Question 1123696: Find 4 consecutive even integers such that the product of -2 and the sum of the 1st and the 4th is 20 less than the opposite of the 3rd.
Found 3 solutions by josgarithmetic, JessLynnLancaster24, ikleyn:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%2C+x%2B2%2C+x%2B4%2C+x%2B6%29

-2%28x%2Bx%2B6%29=-%28x%2B4%29-20------the basic equation corresponding to the description.


-
-2%282x%2B6%29=-x-4-20
2%282x%2B6%29=x%2B24
4x%2B12=x%2B24
3x=12
highlight_green%28x=4%29--------the first even integer

Answer by JessLynnLancaster24(2) About Me  (Show Source):
You can put this solution on YOUR website!
-2(x + x + 6) = -(x + 4) - 20
-2x + -2x + 6 = -x - 4 - 20
-4x + 6 = -x - -16
+x +x
-3x + 6 = -16
- 6 -6
-3x = -22
divide both sides by -3
x = 7.33

Answer by ikleyn(52793) About Me  (Show Source):
You can put this solution on YOUR website!
.

Be aware.   The solution by  @JessLynnLancaster24  is totally wrong and contains a lot of errors,
demonstrating extremely low level in Math.

This forum is not the place for such solutions and such  "tutors".