SOLUTION: I have a question that says find 2 consecutive even integers such that their sum is equal to the difference of 3 times the larger and 2 times the smaller.

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Question 1102046: I have a question that says find 2 consecutive even integers such that their sum is equal to the difference of 3 times the larger and 2 times the smaller.
Found 2 solutions by algebrahouse.com, josgarithmetic:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
x = first consecutive even integer
x + 2 = second consecutive even integer {even integers are separated by 2}

x + x + 2 = 3(x + 2) - 2x {their sum equals difference of 3 times larger and 2 times smaller}
2x + 2 = 3x + 6 - 2x {combined like terms and used distributive property}
2x + 2 = x + 6 {combined like terms}
x = 4 {subtracted x and 2 from each side}
x + 2 = 6 {substituted 4, in for x, into x + 2}

4 and 6 are the two consecutive even integers

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Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
n-1 and n+1, assumed consecutive even integers

%28n-1%29%2B%28n%2B1%29=3%28n%2B1%29-2%28n-1%29
Simplify and solve this, and then evaluate the two integers.