SOLUTION: find three consecutive integers. such that 4 times of first integer is 18 more than the sum of the second and third integer

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Question 1096400: find three consecutive integers. such that 4 times of first integer is 18 more than the sum of the second and third integer
Answer by Alan3354(69443) About Me  (Show Source):
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find three consecutive integers. such that 4 times of first integer is 18 more than the sum of the second and third integer
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4n = (n+1) + (n+2) + 18
4n = 2n + 21
2n = 21
No such integers.