SOLUTION: find three consecutive odd integers such that 19 more than the first is 67 less than three times the last

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Question 1095209: find three consecutive odd integers such that 19 more than the first is 67 less than three times the last
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2Cn%2B2%2Cn%2B4%29

n%2B19=3%28n%2B4%29-67
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n%2B19=3n%2B12-67
19=2n%2B12-67
2n=19-12%2B67
2n=74
highlight%28n=37%29 

 the numbers:  37, 39, 41