SOLUTION: Write an equation to represent this relationship among the intergers.
The lengths in feet of three pieces of copper tubing are consecutive multiples of 4. If each piece of tubing
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The lengths in feet of three pieces of copper tubing are consecutive multiples of 4. If each piece of tubing
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Question 1093515: Write an equation to represent this relationship among the intergers.
The lengths in feet of three pieces of copper tubing are consecutive multiples of 4. If each piece of tubing were 5 ft shorter, the sum of their lengths would be 45 ft. Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website!
Write an equation to represent this relationship among the intergers.
The lengths in feet of three pieces of copper tubing are consecutive multiples of 4. If each piece of tubing were 5 ft shorter, the sum of their lengths would be 45 ft.
Let the shortest piece be S
Then the other 2 are: S + 4, and S + 8
The equation you're looking for is: S - 5 + S + 4 - 5 + S + 8 - 5 = 45
Reducing this, we get: 3S - 3 = 45 <======= This is the equation you need.
IGNORE the NONSENSE the other person posted as he has no clue.
You can put this solution on YOUR website! .
Write an equation to represent this relationship among the intergers.
The lengths in feet of three pieces
of copper tubing are consecutive multiples of 4. If each piece of tubing were 5 ft shorter, the sum of their lengths would be 45 ft.
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I am not an expert in English (which is my second language),
but it seems to me that the last phrase MUST be
Had each piece of tubing be 5 ft shorter, the sum of their lengths would be 45 ft.
And YES: The solution by @josgarithmetic is W R O N G.
It is C O N C E P T U A L L Y W R O N G (from the very beginning to the end).