SOLUTION: The Product of two consecutive integers is 8 more than twice their sum. Find the integers.

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Question 107116This question is from textbook Begining Algebra
: The Product of two consecutive integers is 8 more than twice their sum. Find the integers. This question is from textbook Begining Algebra

Found 2 solutions by checkley75, elima:
Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website!
x(x+1)=8+2(x+x+1)
x^2+x=8+4x+2
x^2+x-4x-8-2=0
x^2-3x-10=0
(x-5)(x+2)=0
x-5=0
x=5 answer
x+2=0
x=-2 answer.
proof
5*6=8+2(5+6)
30=8+22
30=30
-2(-2+1)=8+2(-2-1)
-2*-1=8+2*-3
2=8-6
2=2

Answer by elima(1433) (Show Source):
You can put this solution on YOUR website!
The Product of two consecutive integers is 8 more than twice their sum. Find the integers.
x(x+1)=8+2(x+x+1)

(x-5)(x+2)=0
x-5=0; x+2=0
x=5; x=-2
Consecutive numbers are 5 and 6
:)