Question 1053795: Find three consecutive odd intergers such that the sum of the smaller two is three times the largest increased by seven
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Let the three consecutive odd integers be x, x+2, and x+4
x+x+2 = 3(x+4)+7
2x+2 = 3x+12+7
2x+2 = 3x+19
-x = 17
x = -17 this is the smallest number
Next is -17+2 = -15
Next is -15+2 = -13
Keep in mind that the further you go into negative territory the smaller the number is, so -100 is smaller than -0.01
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Check:
Our numbers are: -17, -15, -13
the sum of the smaller two is 3 times the largest +7
-17+-15 = 32 this is the sum of the smaller two
-13(3)+7 = 32 this is the largest of the numbers times 3 +7
as you see the answer in both cases is 32, so this answer is correct.
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