SOLUTION: three consecutive even integers are such that if the second is added to twice the first the result is 18 more than the third. find these integers

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Question 1046809: three consecutive even integers are such that if the second is added to twice the first the result is 18 more than the third. find these integers
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive even integers be:
+n+, +n%2B2++, and +n+%2B+4+
---------------------------------
+n+%2B+2+%2B+2n+=+n+%2B+4+%2B+18+
+3n+%2B+2+=+n+%2B+22+
+2n+=+20+
+n+=+10+
and
+n+%2B+2+=+12+
+n+%2B+4+=+14+
The consecutive even integers are:
10, 12, and 14
-------------------
+n+%2B+2+%2B+2n+=+n+%2B+4+%2B+18+
+10+%2B+2+%2B+2%2A10+=+10+%2B+4+%2B+18+
+12+%2B+20+=+14+%2B+18+
+32+=+32+
OK