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<H2>Students studying foreign languages</H2> <H3>Problem 1</H3>A survey of 100 students asked if they studied a foreign language. The result showed: Spanish, 28; German, 30; French, 42; Spanish and German, 8; Spanish and French,10; German and French 5; all three languages,3. What is the probability that a randomly selected student studied no foreign language? <B>Solution</B> <pre> Let S be the subset of the 100 students studied Spanish, and let |S| be the cardinality of the subset S. We are given |S| = 28. Let G be the subset of the 100 students studied German, and let |G| be the cardinality of the subset G. We are given |G| = 30. Let F be the subset of the 100 students studied French, and let |F| be the cardinality of the subset F. We are given |F| = 42. Let SG be the subset of the 100 students studied Spanish and German. It is the intersection of the sets S and G. And let |SG| be the cardinality of the subset SG. We are given |SG| = 8. Let SF be the subset of the 100 students studied Spanish and French. It is the intersection of the sets S and F. And let |SF| be the cardinality of the subset SF. We are given |SF| = 10. Let GF be the subset of the 100 students studied German and French. It is the intersection of the sets G and F. And let |GF| be the cardinality of the subset GF. We are given |GF| = 5. Finally, let SGF be the subset of the 100 students studied Spanish, German and French. It is the intersection of the sets S, G and F. And let |SGF| be the cardinality of the subset SGF. We are given |GF| = 3. Now, the number of students among of 100 surveyed who studied at least one of these three languages was N = |S| + |G| +|F| - |SG| - |SF| - |GF| + |SGF| = 28 + 30 + 42 - 8 - 10 - 5 + 3 = 80. Thus 80 students of 100 learned at least one language. The rest of 100, 100-80 = 20, do not study these languages. Therefore, the probability that a randomly selected student studied no foreign language is {{{20/100}}} = {{{1/5}}}. <U>Answer</U>. The probability that a randomly selected student studied no foreign language is {{{1/5}}}. </pre> The formula we used is well known in the elementary set theory. Its proof is very straightforward and simple. See, for example, the lesson - <A HREF=https://www.algebra.com/algebra/homework/word/misc/Advanced-probs-counting-elements-in-sub-sets-of-a-given-finite-set.lesson>Advanced problems on counting elements in sub-sets of a given finite set</A> in this site. 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