Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1200601: The Mississauga Valley Bridge Club has 15 members: 10 women and 5 men. A committee of 6 people is selected from the club.
a) What is the probability that the committee contains no women?
b) What is the probability that the committee contains exactly 2 women?
c) What is the probability that the committee contains at least 3 women?
Click here to see answer by GingerAle(43)  |
Question 1201115: A casino offers the following game: You bet on the outcome of a fair die. If correct, the casino returns 5 times your bet to you. Otherwise they return 0.
You have $10. You decide to play the game using the following strategy. Starting from a $d bet (where d is a positive integer less than 5), you double your bet on each play of the game, stopping only when you cannot double your previous bet, or you have at least $20. Find the probability that you leave this game with at least $20, for each value of d = 1, 2, 3, 4.
Click here to see answer by GingerAle(43) |
Question 1204322: The expected number of defective parts produced on an assembly line per shift is 50 with a standard deviation of 8. Use Chebyshev's inequality to find the minimum probability that the number of defective parts on a particular shift will be between 22 and 78. (Round your answer to four decimal places.)
Click here to see answer by GingerAle(43) |
Question 1200743: A received m good and n bad text messages, one of which was randomly deleted, and one good message was added before sending all to B. B also randomly deleted one message and added one good message before sending all to C. What is the probability that C will receive fewer bad messages than A? What is the probability that C will receive fewer bad messages than A, given that B randomly deleted and added one bad message? ([m, n] = [14, 6])
Click here to see answer by GingerAle(43) |
Question 1201118: A casino offers the following game: You bet on the outcome of a fair die. If correct, the casino returns 5 times your bet to you. Otherwise they return 0.
You have $10. You decide to play the game using the following strategy. Starting from a $d bet (where d is a positive integer less than 5), you double your bet on each play of the game, stopping only when you cannot double your previous bet, or you have at least $20. Find the probability that you leave this game with at least $20, for each value of d = 1, 2, 3, 4.
Click here to see answer by GingerAle(43) |
Question 1200603: A distribution of values is normal with a mean of 40 and a standard deviation of 98.
Find P39, which is the score separating the bottom 39% from the top 61%.
P39 =
Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.the same aptitude, but use different scales.
Click here to see answer by GingerAle(43) |
Question 1200597: Untitled
Feb 24, 2023
6. An engineering Company advertises a job in three news papers A,B,C.if it is
known that these papers attract undergraduate engineering readerships in the
proportions 2:3:1. The probabiity that an engineerig undergraduate sees and
replies to the Job advertisement in the papers are 0.002, 0.001 and 0.005
respectively. Assume that the ungergraduate sees Only one job advertisement a)
the ergineering company receives only one reply to it advertisements, calculate
the probability that the applicant has seen the job adv ertised in place.
1.a,A b,B, c,C.
2.if the company recaives two replies, what is the probability that both
applicants saw the jOb advertised in paper A?
Click here to see answer by GingerAle(43) |
Question 1200525: Use the value of the linear correlation coefficient to calculate the coefficient of determination. What does this tell you about the explained variation of the data about the regressionโ line? About the unexplainedโ variation?
r=0.445
Click here to see answer by GingerAle(43) |
Question 1200633: Gaynor Advertising conducted a survey to determine individualโs main source of news as well as their educational level. 2500 individuals were surveyed and the results are given below:
Source of News Primary Secondary Graduate Post Graduate Total
Newspapers 95 200 121 400 816
Television 136 127 135 211 609
Social Media 155 99 170 146 570
Grapevine 250 155 95 25 505
Total 636 561 521 782 2500
a. State both the null and alternative hypotheses. [2 marks]
b. Provide the decision rule for making this decision. Use an alpha level of 5%. [2 marks]
c. Show all of the work necessary to calculate the appropriate statistic. [5 marks]
d. What conclusion are you allowed to draw? [2 marks]
e. Would your conclusion change at the 10% level of significance? [2 marks]
f. Confirm test results in part (c) using JASP. Note: All JASP input files and output tables should be provided [3 marks]
Click here to see answer by GingerAle(43) |
Question 1201153: Hello, please i need help solving this: The Donaldson Corporation wants to hire a temporary secretary. There are two employment agencies in town, and it is believed that the average hourly wage charged by both agencies is the same. A Donaldson manager surveyed other employers in town to find what they paid the agencies for temporary secretaries. The results are summarized below. At alpha = 0.05, test the claim that each agency charges the same hourly wage.
Agency A: x1 = 9.55/hr, $1 =$1.45/hr, n1= 20.
Agency B: x1 = 9.25/hr, $1 =$1.25/hr, n1= 18.
Click here to see answer by GingerAle(43) |
Question 1200520: Out of 1000 managers, 72% say they use social media to screen applications. Out of 5 applications, what is the probability that exactly 3 of the managers use social media to screen
What is the probability that non will use social media
What is the probability that all 5 will use social media
Click here to see answer by GingerAle(43) |
Question 1200377: In a state with a total population of 70,000 adults, 34000 are males and out of a total of 6000 graduates 700 are female. Out of 1200 graduate employees of the state, 200 are females. Is there any gender bias in education among people ? The state claims that no distinction is made in appointment in respect of gender. How for si their claim substantiated by the data given above?
Click here to see answer by GingerAle(43) |
Question 1207924: A random sample of n = 36 observations has a mean x = 28.7 and a standard deviation s = 3.8.
GIVEN:-
- point estimate of the population mean ๐ = 28.7
- 95% margin of error for your estimate = 1.2413
- 90% confidence interval for ๐ = 27.658 to 29.742
- In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean.
- (a) bound is calculated using z๐ผ, while the lower confidence limit in part (b) is calculated using z๐ผ/2.
(a) Find a 90% lower confidence bound for the population mean ๐. (Round your answer to two decimal places.)
(b) How many observations do you need to estimate ๐ to within 0.6, with probability equal to 0.95? (Round your answer up to the nearest whole number.)
observations
Click here to see answer by GingerAle(43) |
Question 1200375: Raffle tickets numbered 1 through 30 are placed in a box. Tickets for a second raffle are
numbered 21 through 48 and placed in a second box. One ticket is randomly drawn from each box.
Find the probability the first ticket is greater than 10, and the second ticket is less than 40 or odd
Click here to see answer by GingerAle(43) |
Question 1200459: 3. A corporation must appoint a president, chief executive officer (CEO), chief financial officer (CFO) and chief operating officer (COO). It must also appoint a planning committee with six different members. There are 12 qualified candidates, and officers can also serve on the committee.
(i) How many different ways can the officers be appointed?
(ii) What is the probability of randomly selecting the officers and getting the youngest candidate a president?
(iii) How many different ways can the committee be appointed?
(iv) What is the probability of randomly selecting the committee members and getting the six youngest of the qualified candidates?
Click here to see answer by GingerAle(43) |
Question 1200427: Suppose it is known that the probability of recovery for a certain disease is 0.4. If 35 people are stricken with the disease, what is the probability that:
(a) 25 or more will recover?
(b) Fewer than five will recover?
(Use the normal approximation.)
Click here to see answer by GingerAle(43) |
Question 1200583: A workplace injury policy has a premium (policy cost) of $7. The probability of a claim is
0.43, in which case the amount of the claim has density 1.2/(๐ฅ^2.2), when ๐ฅ โฅ 1. Find the expected
value of the net revenue to the company.
Click here to see answer by GingerAle(43) |
Question 1200573: In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities.
It is estimated that 3.5% of the general population will live past their 90th birthday. In a graduating class of 758 high school seniors, find the following probabilities. (Round your answers to four decimal places)
what is the probability that 30 or more will live beyond their 90th birthday?
Click here to see answer by GingerAle(43) |
Question 1200129: The resting heart rate for an adult horse should average about ๐ = 43 beats per minute with a (95% of data) range from 14 to 72 beats per minute. Let x be a random variable that represents the resting heart rate for an adult horse. Assume that x has a distribution that is approximately normal.
(a) The empirical rule indicates that for a symmetrical and bell-shaped distribution, approximately 95% of the data lies within two standard deviations of the mean. Therefore, a 95% range of data values extending from ๐ - 2๐ to ๐ + 2๐ is often used for "commonly occurring" data values. Note that the interval from ๐ - 2๐ to ๐ + 2๐ is 4๐ in length. This leads to a "rule of thumb" for estimating the standard deviation from a 95% range of data values:
For a symmetric, bell-shaped distribution:
standard deviation โ range/4โ(high value - low value)/4
where it is estimated that about 95% of the commonly occurring data values fall into this range.
Use this "rule of thumb" to estimate the standard deviation of x distribution. (Round your answer to one decimal place.)
beats
(b) What is the probability that the heart rate is less than 25 beats per minute? (Round your answer to four decimal places.)
(c) What is the probability that the heart rate is greater than 60 beats per minute? (Round your answer to four decimal places.)
(d) What is the probability that the heart rate is between 25 and 60 beats per minute? (Round your answer to four decimal places.)
(e) A horse whose resting heart rate is in the upper 13% of the probability distribution of heart rates may have a secondary infection or illness that needs to be treated. What is the heart rate corresponding to the upper 13% cutoff point of the probability distribution? (Round your answer to the nearest whole number.)
Click here to see answer by GingerAle(43) |
Question 1200096: The mean height of a population of girls aged 15 to 19 years in a certain population was found to be 165 cm with a standard deviation of 15cm. Assuming that the heights are normally distributed, find the heights in centimeters that correspond to the following percentiles:
a. Between the 20th and 50th percentiles.
b. Between the 40th and 60th percentiles.
c. Between the 10th and 90th percentiles.
d. Above the 80th percentile.
e. Below the 10th percentile.
f. Above the 5th percentile.
Click here to see answer by GingerAle(43) |
Question 1200079: Virgil has a bag of Skittles. He randomly selected a piece of candy recorded the color and then put it back in the bag. He did this ten times and recorded the results below.
Experiment
Trial Number 1 2 3 4 5 6 7 8 9 10
Outcome red yellow purple purple green yellow orange red purple blue
Color and Number of Candies
Then he poured all of the candies out and recorded the number of each colored candy.
Color Green Yellow Orange Red Blue Purple Total
Number of Candies 16 7 9 15 5 11
Answer
63
Enter the total in the box.
Probability of Next Candy
Fill in the chart below with the probability of choosing the next candy.
Event Write the probability using symbols. Experimental Probability
(Enter as a reduced fraction.) Theoretical Probability
(Enter as a reduced fraction.)
What is the probability of choosing a red Skittle? P(R)=
15
Answer
What is the probability of choosing an orange Skittle? Answer
P(O)
= Answer
17
What is the probability of choosing a purple Skittle? P(P)=
Answer
Answer
What is the probability of choosing a Skittle that is green? Answer
P(G)
= 110
Answer
Click here to see answer by GingerAle(43) |
Question 1201093: According to the storeโs historical records, 65% of its digital camera customers
are male, 18% of its digital camera customers purchased the extended warranty,
and 10% of its digital camera customers are female and purchased the extended
warranty.
(i) Determine the probability that a male digital camera customer will
purchase the extended warranty. [4 Marks]
(ii) Are female customers more likely to purchase the extended warranty?
Justify your answers
Click here to see answer by GingerAle(43) |
Question 1200444: Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The mean arrival rate is 11 passengers per minute.
a. Compute the probability of no arrivals in a one-minute period (to 6 decimals).
Click here to see answer by GingerAle(43) |
Question 1200098: 10. Suppose it is known that the probability of recovery for a certain disease is 0.4. If 35 people are stricken with the disease, what is the probability that:
(a) 25 or more will recover?
(b) Fewer than five will recover?
(Use the normal approximation.)
Click here to see answer by GingerAle(43) |
Question 1200311: The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to 4 decimal places where possible,
a.What is the distribution of X? X ~ N( ----, ----)
b.Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 10.9.
c. Find the 78th percentile for this distribution.
Click here to see answer by GingerAle(43) |
Question 1200097: 5. The following questions pertain to some important facts to know about a normal
distribution:
a. What are three important properties of a normal distribution?
b. What percentage of the values are:
i. Within 1 standard deviation of the mean?
ii. Two standard deviations or more above the mean?
Click here to see answer by amarjeeth123(569) |
Question 1200047: In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities.
Do you try to pad an insurance claim to cover your deductible? About 37% of all U.S. adults will try to pad their insurance claims! Suppose that you are the director of an insurance adjustment office. Your office has just received 138 insurance claims to be processed in the next few days. Find the following probabilities. (Round your answers to four decimal places.)
(a) half or more of the claims have been padded
(b) fewer than 45 of the claims have been padded
(c) from 40 to 64 of the claims have been padded
(d) more than 80 of the claims have not been padded
Click here to see answer by textot(100) |
Question 1200043: The flowing data is organized by using a stem-and lead displays for the weights of 10 people
Stems Leaves
5 0 2
6 2 4 4
7 1 5 5 5
8 8
Based on the above data:
a) Develop the frequency distribution table
b) Show on the table the relative frequently distribution and percent frequency distribution for each group
c) Calculate the mean
d) Calculate 1 percent of trimmed mean
e) Calculate the weighted mean
f) Calculate median
g) Calculate the mode
h) Calculate the range
i) Find the first, second and third quartile
j) Calculate the 80th percentile and interpret the results obtained
Click here to see answer by textot(100) |
Question 1199985: The following data on annual rates of return were collected from eleven randomly selected stocks listed on the New York Stock Exchange (โthe big boardโ) and twelve randomly selected stocks listed on NASDAQ. Assume the population standard deviations are the same. At the 0.10 significance level, can we conclude that the annual rates of return are higher on the big board?
NYSE: 15.0, 10.7, 20.2, 18.6, 19.1, 8.7, 17.8, 13.8, 22.7, 14.0, 26.1
NASDAQ: 8.8, 6.0, 14.4, 19.1, 17.6, 17.8, 15.9, 17.9, 21.6, 6.0, 11.9, 23.4
Click here to see answer by textot(100) |
Question 1199984: If 4% of the population carries a certain
genetic trait, hnd the probability that in a sample
of 100 people, there are exactly 8 people who have
the trait. Assume the distribution is approximately
Poisson.
Click here to see answer by textot(100) |
Question 1200425: A pharmaceutical firm claims that a new analgesic drug relieves mild pain under standard conditions for 3 hours, with a standard deviation 1 hour. Sixteen patients are tested under the same conditions and have an average pain relief time of 2.5 hours. Test the hypothesis that the population mean of this sample is actually 3 hours. Use ( =0.05). Try to follow all steps in hypothesis testing.
Click here to see answer by textot(100) |
Question 1201174: The germination rate of seeds is defined as the proportion of seeds that when properly planted and watered, spruot and grow. A certain variety of grass seed usually has a germination rate of 0.80, and a company wants to see if spraying the seeds with a chemical that is known to change germination rates in other species will change the germination rate of this grass species.
(a) Suppose the company plans to spray a random sample of 400 seeds and conduct a two-sided test of H0: p=0.8 using (Alpha)=O.05. They determine that the power of this test against the alternative p=0.75 is 0.69. Interpret the power of this test.
(b) Describe two ways the company can increase the power of the test. What a disadvantage of each of these ways?
(c) The company researchers spray 400 seeds with the chemical and 307 of the seeds germinate. This produces a 95% confidence interval for the proportions of seeds that germinate of (0.726,0.809). Use this confidence interval to determine whether this test would reject or fail to reject the null hypothesis. Explain your reasoning.
Click here to see answer by textot(100) |
Question 1200213: Deck X has fifteen cards of which 8 are red and 7 are black. Deck Y has twelve cards of which 6 are
red and 6 are black. A card is drawn at random from Deck X and is discarded. Then all the
remaining cards are transferred to Deck Y. A card is now drawn from Deck Y and is found to be
red.
For this problem, draw a Venn diagram and fill in each of the 4 regions with their correct
symbols and probabilities using fractions. Show complete solutions.
Click here to see answer by textot(100) |
Question 1200388: The probability of winning on an arcade game is 0.678. If you play the arcade game 24 times, what is the probability of winning no more than 12 times? (Round your answer to 3 decimal places, if necessary.)
Click here to see answer by textot(100) |
Question 1199947: Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 44 couples.
(a) through (c) below.
a) Find the mean and the standard deviation for the numbers of girls in groups of 44 births.
The value of the mean is U=.
The value of the standard deviation is o=
b) Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of significantly low.
girls are ?
Values of significantly high.
girls are?
c) Is the result of 43 girls a result that is significantly high?
What does it suggest about the effective ness of the method?
The result significantly high, because 43 girls is
girls. A result of 43 girls would suggest that the method
Click here to see answer by textot(100) |
Question 1200367: At a large publishing company, the mean age of proofreaders is 36.2 years and the standard deviation of the distribution is 3.7 years. A random sample of 40 proofreaders is selected.
a. State the importance of central limit theorem if we are interested to determine the probability for the sample mean age of the selected proofreaders. (2 marks)
b. Find the probability that the mean age of the proofreaders in the sample will be between 35 and 37 years.
Click here to see answer by textot(100) |
Question 1199956: d. According to an officer in the Health Care Financing Administration, the average annual
expenditure on toiletries is RM110 per person in Malaysia. The data of 30 randomly
selected persons are as follows and the standard deviation of the sample is 19.2152.
125 110 110 90 90
85 125 110 85 120
130 125 130 90 130
80 120 90 110 90
90 85 100 130 80
90 100 125 150 100
i. Find the sample mean of the data.
ii. Is there enough evidence to support the officerโs claim at 0.02 level of significance?
iii. What is the decision at a 0.2% significance level?
Click here to see answer by textot(100) |
Question 1207925: Independent random samples of n1 = 18 and n2 = 13 observations were selected from two normal populations with equal variances.
DATA:-
__________________Population (IGNORE the lines - represents space)
__________________1______2 (IGNORE the lines - represents space)
Sample Size______18______13 (IGNORE the lines - represents space)
Sample Mean_____34.6_____32.1 (IGNORE the lines - represents space)
Sample Variance__4.5_____5.9 (IGNORE the lines - represents space)
(a) Find the rejection region for the test in part (a) for ๐ผ = 0.01. (If the test is one-tailed, enter NONE for the unused region. Round your answers to three decimal places.)
t > _________
t < _________
(b) Find the value of the test statistic. (Round your answer to three decimal places.)
t = _________
Click here to see answer by textot(100) |
Question 1199957: Suppose that the scores of architects on a particular creativity test are normally distributed with a mean of 285 and a standard deviation of 25. Using a normal curveโ table, find the top and bottom scores for each of the following middle percentages of architects.
โ(a)
โ%55
โ(b)
โ%86
โ(c)
โ%99
Click here to see answer by textot(100) |
Question 1200742: The free seats in a movie theater are numbered 1, 2, ..., n. m friends buy tickets one after the other, and seats are assigned to them randomly. What is the probability that they will all get seats with even numbers? Previously, k friends received seats with even numbers. What is the probability that the remaining friends will also get seats with even numbers? ([n, m, k] = [33, 6, 4])
Click here to see answer by textot(100) |
Question 1200130: 72% of all bald eagles survive their first year of life. Give your answers as decimals, not percents. If 34 bald eagles are randomly selected, find the probability that
a. Exactly 26 of them survive their first year of life_______
b. At most 26 of them survive their first year of life________
c. At least 24 of them survive their first year of life_______
d. Between 19 and 26 (including 19 and 26) of them survive their first year of life_______
Click here to see answer by textot(100) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 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11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 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