Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1163032: We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find tα/2,df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.)
tα/2,df
a. A 95% confidence level and a sample of 18 observations.
b. A 99% confidence level and a sample of 18 observations.
c. A 95% confidence level and a sample of 9 observations.
d. A 99% confidence level and a sample of 9 observations.
Please label answers by a., b., c., and d.
Thank you very much! I appreciate it!
Click here to see answer by jim_thompson5910(35256)  |
Question 1163048: Q1) [] In how many ways can 5 boys and 4 girls be seated in a row so that those of the same gender sit together?
Q3) [] A class has 12 boys and 4 girls. If 3 students are selected at random from the class, what is the probability p that they are all boys?
Q5) [] A student is to answer 8 out of 10 questions on an exam. How many choices has he if he must answer the first 3 questions?
_______________________
Q6) [] A class contains 10 men and 20 women of which half the men and half the women have brown
Click here to see answer by solver91311(24713)  |
Question 1163048: Q1) [] In how many ways can 5 boys and 4 girls be seated in a row so that those of the same gender sit together?
Q3) [] A class has 12 boys and 4 girls. If 3 students are selected at random from the class, what is the probability p that they are all boys?
Q5) [] A student is to answer 8 out of 10 questions on an exam. How many choices has he if he must answer the first 3 questions?
_______________________
Q6) [] A class contains 10 men and 20 women of which half the men and half the women have brown
Click here to see answer by Edwin McCravy(20054)  |
Question 1163053: The lifetime of a certain light bulb can be standardised to a normal model with a mean of 400 hours and a standard deviation of 65 hours . For a group of 6,400 lights use the empirical rule to determine how many of them are expected to last between 400 hours and 530 hours
Click here to see answer by jim_thompson5910(35256) |
Question 1163064: The property tax paid by homeowners in a large city was determined to be normally distributed with a mean of $2,800 and a standard deviation of $400. A random sample of four homes was drawn.
a. What is the probability distribution of the mean of the sample of four homes?
b. Determine the probability that the sample mean falls between $2,500 and $2,900
Click here to see answer by Boreal(15235)  |
Question 1163031: A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is taking longer than before to sell a house. The wife is concerned and wants to know when it is optimal to put their house on the market. Her realtor friend informs them that the last 20 houses that sold in their neighborhood took an average time of 90 days to sell. The realtor also tells them that based on her prior experience, the population standard deviation is 24 days. [You may find it useful to reference the z table.]
a. What assumption regarding the population is necessary for making an interval estimate for the population mean?
Assume that the central limit theorem applies.
Assume that the population has a normal distribution.
b. Construct the 90% confidence interval for the mean sale time for all homes in the neighborhood. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answers to 2 decimal places.)
Click here to see answer by Boreal(15235) |
Question 1163068: PLEASE HELP!!!!!!!!!!!
In a recent poll of 1,600 homeowners in the United States, one in eight homeowners reports having a home equity loan that he or she is currently paying off. Using a confidence coefficient of 0.99, derive the interval estimate for the proportion of all homeowners in the United States that hold a home equity loan. (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)
Thank you very much for your help!!
Click here to see answer by Boreal(15235) |
Question 1162650: A random variable X follows the uniform distribution with a lower limit of 520 and an upper limit of 620.
a. Calculate the mean and the standard deviation for the distribution. (Round intermediate calculation for standard deviation to 4 decimal places and final answer to 2 decimal places.)
b. What is the probability that X is less than 570? (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
Click here to see answer by Boreal(15235) |
Question 1163081: The estimate of the population proportion is to be within plus or minus 0.05, with a 90% level of confidence. The best estimate of the population proportion is 0.31. How large a sample is required?
Click here to see answer by Theo(13342)  |
Question 1162635: Consider the following joint probability table.
B1 B2 B3 B4
A 0.18 0.09 0.11 0.15
Ac 0.11 0.11 0.10 0.15
Click here for the Excel Data File
a. What is the probability that A occurs? (Round your answer to 2 decimal places.)
b. What is the probability that B2 occurs? (Round your answer to 2 decimal places.)
c. What is the probability that Ac and B4 occur? (Round your answer to 2 decimal places.)
d. What is the probability that A or B3 occurs? (Round your answer to 2 decimal places.)
e. Given that B2 has occurred, what is the probability that A occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)
f. Given that A has occurred, what is the probability that B4 occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)
Click here to see answer by ikleyn(52752)  |
Question 1163104: On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she has assigned the following probability distribution to the number of tubes she will rent on a randomly selected day.
x 25 50 75 100 Total
P(x) .20 .35 .30 .15 1.00
________________________________________
What is the probability expression for P(X=50), P(X<100), P(X>50), P(less/equal 75)
Click here to see answer by ikleyn(52752) |
Question 1163096: PLEASE HELP!!!!!!!!!!
Consider the following hypotheses:
H0: μ = 73
HA: μ ≠ 73
Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table)
1. x¯ = 70; s = 6.9; n = 35
A. p-value < 0.01
B. p-value > or equal to 0.10
C. 0.01 < or equal to p-value < 0.02
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
2. x¯ = 76; s = 6.9; n = 35
A. 0.01 < or equal to p-value < 0.02
B. p-value < 0.01
C. p-value > or equal to 0.10
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
3. x¯ = 70; s = 6.4; n = 19
A. 0.05 < or equal to p-value < 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.02
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
4. x¯ = 70; s = 6.4; n = 24
A. p-value < 0.01
B. 0.01 < or equal to p-value < 0.02
C. 0.05 < or equal to p-value < 0.10
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
PLEASE LABEL QUESTIONS 1-4 AND THEIR CORRESPONDING ANSWERS A-E.
THANK YOU VERY MUCH!!!!!!!!!
Click here to see answer by Alan3354(69443)  |
Question 1163099: PLEASE HELP!!!!!!!!!!
Consider the following hypotheses:
H0: p ≥ 0.47
HA: p < 0.47
Compute the p-value based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table) (Round "z" value to 2 decimal places. Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)
p-value
a. x = 46; n = 118 _______
b. x = 112; n = 311 _______
c. p¯ = 0.38; n = 53 _______
d. p¯ = 0.38; n = 430 _______
THANK YOU VERY MUCH!!!!!!!!!
Click here to see answer by Boreal(15235) |
Question 1163097: PLEASE HELP!!!!!!!!!!
Consider the following hypotheses:
H0: μ = 37
HA: μ ≠ 37
The population is normally distributed. A sample produces the following observations: (You may find it useful to reference the appropriate table: z table or t table)
36 42 37 32 41 37 37
Click here for the Excel Data File
1. Find the mean and the standard deviation. (Round your answers to 2 decimal places.)
2. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
3. Find the p-value.
A. p-value > or equal to 0.10
B. 0.05 < or equal to p-value < 0.10
C. 0.02 < or equal to p-value < 0.05
D. 0.01 < or equal to p-value < 0.02
E. p-value < 0.01
4. At the 1% significance level, what is the conclusion?
A. Reject H0 since the p-value is greater than α.
B. Reject H0 since the p-value is smaller than α.
C. Do not reject H0 since the p-value is greater than α.
D. Do not reject H0 since the p-value is smaller than α.
5. Interpret the results α = 0.01.
A. We conclude that the sample mean differs from 37.
B. We cannot conclude that the population mean differs from 37.
C. We conclude that the population mean differs from 37.
D. We cannot conclude that the sample mean differs from 37.
PLEASE LABEL QUESTIONS 1-5 AND THE CORRESPONDING ANSWERS A-D (WITH QUESTIONS 3-5).
THANK YOU VERY MUCH!!!!!!!!!
Click here to see answer by Boreal(15235) |
Question 1161598: The average per capita spending on health care in the United States
is $5274. If the standard deviation is $600 and the
distribution of health care spending is approximately
normal, what is the probability that a randomly
selected person spends more than $6000? Find the
limits of the middle 50% of individual health care
expenditures.
Click here to see answer by Boreal(15235) |
Question 1163030: In a recent poll of 1,600 homeowners in the United States, one in eight homeowners reports having a home equity loan that he or she is currently paying off. Using a confidence coefficient of 0.99, derive the interval estimate for the proportion of all homeowners in the United States that hold a home equity loan. (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)
Click here to see answer by Boreal(15235) |
Question 1163095: PLEASE HELP!!!!!!!!!!
The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fairly reliable. It gives a positive reaction in 98.2% of the people who have that disease. However, it erroneously gives a positive reaction in 1.3% of the people who do not have the disease. Consider the null hypothesis "the individual does not have the disease" to answer the following questions.
a. What is the probability of a Type I error? (Round your answer to 3 decimal places.)
b. What is the probability of a Type II error? (Round your answer to 3 decimal places.)
PLEASE LABEL ANSWERS A. AND B.
THANK YOU VERY MUCH!!!!!!!!!
Click here to see answer by solver91311(24713) |
Question 1163122: An urn contains x red balls and y green balls. if a ball is taken at random from the urn, the probability that it is red is 3/7. Write down an equation connecting x and y. if there had been 5 more red balls, the probability would have been 1/2. find x and y.
Click here to see answer by Edwin McCravy(20054) |
Question 1163134: A cell phone company orders 600 new phones from a manufacturer. If the probability of a phone being defective is 3.5%, predict how many of the phones are likely to be defective. Round to the nearest whole number.
Click here to see answer by ikleyn(52752) |
Question 1163144: Eight students are choosen at random from a normal population and their heights are found to be in inches 63, 67, 68, 69, 70,70, 71, 72. In the light of these data, discuss the suggestions that mean height is less than 68 inches.
Click here to see answer by greenestamps(13195)  |
Question 1163155: In their first day of training, the incoming class runs a mile with a mean time of 9.5 minutes and standard deviation of 1.2 minutes. Calculate the z-score and percentile for a runner who runs a mile in 11 minutes. Briefly interpret this result relative to the rest of the class. If possible if you can provide the work so I know how to do it.
Click here to see answer by solver91311(24713) |
Question 1163153: PLEASE HELP!!!!!!!!!!
In order to conduct a hypothesis test for the population proportion, you sample 290 observations that result in 87 successes. (You may find it useful to reference the appropriate table: z table or t table)
H0: p ≥ 0.36; HA: p < 0.36.
1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
2. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
3. At the 0.01 significance level, What is the conclusion?
A. Do not reject H0 since the p-value is smaller than significance level.
B. Do not reject H0 since the p-value is greater than significance level.
C. Reject H0 since the p-value is smaller than significance level.
D. Reject H0 since the p-value is greater than significance level.
4. Interpret the results at α = 0.01
A. We cannot conclude that the population mean is less than 0.36.
B. We conclude that the population mean is less than 0.36.
C. We cannot conclude that the population proportion is less than 0.36.
D. We conclude that the population proportion is less than 0.36.
H0: p = 0.36; HA: p ≠ 0.36.
5. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
6. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
7. At the 0.01 significance level, What is the conclusion?
A. Reject H0 since the p-value is greater than significance level.
B. Reject H0 since the p-value is smaller than significance level.
C. Do not reject H0 since the p-value is greater than significance level.
D. Do not reject H0 since the p-value is smaller than significance level.
8. Interpret the results at α = 0.01.
A. We conclude that the population mean differs from 0.36.
B. We cannot conclude that the population mean differs from 0.36.
C. We conclude the population proportion differs from 0.36.
D. We cannot conclude that the population proportion differs from 0.36.
PLEASE LABEL QUESTIONS 1-8 AND THEIR CORRESPONDING ANSWERS A-E (FOR QUESTIONS 2-4 AND 6-8).
THANK YOU VERY MUCH!!!!!!!!!
Click here to see answer by solver91311(24713) |
Question 1163126: Help needed please....
Consider the following hypotheses:
H0: μ = 73
HA: μ ≠ 73
Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table)
1. x¯ = 70; s = 6.9; n = 35
A. p-value < 0.01
B. p-value > or equal to 0.10
C. 0.01 < or equal to p-value < 0.02
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
2. x¯ = 76; s = 6.9; n = 35
A. 0.01 < or equal to p-value < 0.02
B. p-value < 0.01
C. p-value > or equal to 0.10
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
3. x¯ = 70; s = 6.4; n = 19
A. 0.05 < or equal to p-value < 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.02
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
4. x¯ = 70; s = 6.4; n = 24
A. p-value < 0.01
B. 0.01 < or equal to p-value < 0.02
C. 0.05 < or equal to p-value < 0.10
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
Please label the answers to match the questions 1-4 and A-E. Thank you for your help.
Click here to see answer by solver91311(24713) |
Question 1163131: An elevator has a placard stating that the maximum capacity is 1368 lb passengers. So,8 adult male passengers can have a mean weight of up to 1368/8=171. If the elevator is loaded with 8 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than 171 lb. (Assume that weights of males are normally distributed with a mean of 177 and a standard deviation of 26.) Does this elevator appear to be safe?
The probability the elevator is overloaded is?
Click here to see answer by Theo(13342) |
Question 1163124: Help needed please....
The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fairly reliable. It gives a positive reaction in 98.2% of the people who have that disease. However, it erroneously gives a positive reaction in 1.3% of the people who do not have the disease. Consider the null hypothesis "the individual does not have the disease" to answer the following questions.
a. Calculate the probability of a Type I error? (Round your answer to 3 decimal places.)
b. Calculate the probability of a Type II error? (Round your answer to 3 decimal places.)
Click here to see answer by solver91311(24713) |
Question 1163184: hello I am looking to see what the square root of -171 would be I am getting multiple different answers using calculator. The problem I am working on is deviation from the mean and the mean is -171 that has to be squared. I am getting 13 one time i get invalid and i have gotten 29241. This is for a math problem I am struggling with any help is greatly appreciated
Click here to see answer by ikleyn(52752) |
Question 1163213: You have to conduct a hypothesis test for the population proportion. In order to do such you have to sample 290 observations that result in 87 successes. (You may find it useful to reference the appropriate table: z table or t table)
H0: p ≥ 0.36; HA: p < 0.36.
1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
2. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
3. At the 0.01 significance level, What is the conclusion?
A. Do not reject H0 since the p-value is smaller than significance level.
B. Do not reject H0 since the p-value is greater than significance level.
C. Reject H0 since the p-value is smaller than significance level.
D. Reject H0 since the p-value is greater than significance level.
4. Interpret the results at α = 0.01
A. We cannot conclude that the population mean is less than 0.36.
B. We conclude that the population mean is less than 0.36.
C. We cannot conclude that the population proportion is less than 0.36.
D. We conclude that the population proportion is less than 0.36.
H0: p = 0.36; HA: p ≠ 0.36.
5. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
6. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
7. At the 0.01 significance level, What is the conclusion?
A. Reject H0 since the p-value is greater than significance level.
B. Reject H0 since the p-value is smaller than significance level.
C. Do not reject H0 since the p-value is greater than significance level.
D. Do not reject H0 since the p-value is smaller than significance level.
8. Interpret the results at α = 0.01.
A. We conclude that the population mean differs from 0.36.
B. We cannot conclude that the population mean differs from 0.36.
C. We conclude the population proportion differs from 0.36.
D. We cannot conclude that the population proportion differs from 0.36.
Click here to see answer by solver91311(24713) |
Question 1163212: There is a screening process for detecting a rare disease that is not perfect. The researchers have developed a blood test that is considered to be fairly reliable. The blood test gives a positive reaction in 98.2% of the people who have the rare disease. However, it erroneously gives a positive reaction in 1.3% of the people who do not have the rare disease. Consider the null hypothesis "the individual does not have the rare disease" to answer the following questions.
a. What is the calculated number (rounded to 3 decimal places) of the probability of a Type I error?
b. What is the calculated number (rounded to 3 decimal places) of the probability of a Type II error?
Click here to see answer by solver91311(24713) |
Question 1163211: H0: μ = 73
HA: μ ≠ 73
Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table)
1. x¯ = 70; s = 6.9; n = 35
A. p-value < 0.01
B. p-value > or equal to 0.10
C. 0.01 < or equal to p-value < 0.02
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
2. x¯ = 76; s = 6.9; n = 35
A. 0.01 < or equal to p-value < 0.02
B. p-value < 0.01
C. p-value > or equal to 0.10
D. 0.05 < or equal to p-value < 0.10
E. 0.02 < or equal to p-value < 0.05
3. x¯ = 70; s = 6.4; n = 19
A. 0.05 < or equal to p-value < 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.02
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
4. x¯ = 70; s = 6.4; n = 24
A. p-value < 0.01
B. 0.01 < or equal to p-value < 0.02
C. 0.05 < or equal to p-value < 0.10
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
Click here to see answer by solver91311(24713) |
Question 1163166: H0: p ≥ 0.36; HA: p < 0.36.
1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
2. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
3. At the 0.01 significance level, What is the conclusion?
A. Do not reject H0 since the p-value is smaller than significance level.
B. Do not reject H0 since the p-value is greater than significance level.
C. Reject H0 since the p-value is smaller than significance level.
D. Reject H0 since the p-value is greater than significance level.
4. Interpret the results at α = 0.01
A. We cannot conclude that the population mean is less than 0.36.
B. We conclude that the population mean is less than 0.36.
C. We cannot conclude that the population proportion is less than 0.36.
D. We conclude that the population proportion is less than 0.36.
H0: p = 0.36; HA: p ≠ 0.36.
5. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
6. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
7. At the 0.01 significance level, What is the conclusion?
A. Reject H0 since the p-value is greater than significance level.
B. Reject H0 since the p-value is smaller than significance level.
C. Do not reject H0 since the p-value is greater than significance level.
D. Do not reject H0 since the p-value is smaller than significance level.
8. Interpret the results at α = 0.01.
A. We conclude that the population mean differs from 0.36.
B. We cannot conclude that the population mean differs from 0.36.
C. We conclude the population proportion differs from 0.36.
D. We cannot conclude that the population proportion differs from 0.36.
Click here to see answer by solver91311(24713) |
Question 1163222: The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fairly reliable. It gives a positive reaction in 98.2% of the people who have that disease. However, it erroneously gives a positive reaction in 1.3% of the people who do not have the disease. Consider the null hypothesis "the individual does not have the disease" to answer the following questions.
****Written statements for answers are be marked as incorrect.****
a. What is the probability of a Type I error? (Round your answer to 3 decimal places.)
b. What is the probability of a Type II error? (Round your answer to 3 decimal places.)
Click here to see answer by solver91311(24713) |
Question 1163221: Consider the following hypotheses:
H0: p ≥ 0.47
HA: p < 0.47
Compute the p-value based on the following sample information.
p-value
a. x = 46 ; n = 118 _________________
b. x = 112 ; n = 311 _________________
c. p¯= 0.38 ; n = 53 _________________
d. p¯= 0.38 ; n = 430 _________________
Click here to see answer by Boreal(15235) |
Question 1162935: A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is taking longer than before to sell a house. The wife is concerned and wants to know when it is optimal to put their house on the market. Her realtor friend informs them that the last 20 houses that sold in their neighborhood took an average time of 90 days to sell. The realtor also tells them that based on her prior experience, the population standard deviation is 24 days. [You may find it useful to reference the z table.]
a. What assumption regarding the population is necessary for making an interval estimate for the population mean?
Assume that the central limit theorem applies.
Assume that the population has a normal distribution.
b. Construct the 90% confidence interval for the mean sale time for all homes in the neighborhood. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answers to 2 decimal places.)
Click here to see answer by Boreal(15235) |
Question 1162528: Mortality tables enable actuaries to obtain the probability that a person at any particular age will
live a specified number of years. Insurance companies and others use such probabilities to determine
life-insurance premiums, retirement pensions, and annuity payments. According to tables provided
by the National Center for Health Statistics in Vital Statistics of the United Republic of Tanzania, a
person of age 20 years has about an 80% chance of being alive at age 65 years. Suppose three people
of age 20 years are selected at random.
(a) Formulate the process of observing which people are alive at age 65 as a sequence of three trials
(b) Obtain the possible outcomes of the 3 trials
(c) Determine the probability of each outcome in part (b).
(d) Find the probability that exactly two of the three people will be alive at age 65.
(e) Obtain the probability distribution of the number of people of the 3 who are alive at age 65.
(f) Draw the probability histograms for probability distribution in (e) above and state the type o
Click here to see answer by Boreal(15235) |
Question 1163217: Hi guys, I'm really stuck and need some help or a hint at least please. Thanks in advance! :)
A prisoner is trapped in a cell containing 3 doors. The first door leads to a tunnel that returns him to his cell after 2 days’ travel. The second leads to a tunnel that returns him to his cell after 4 day’s travel. The third door leads to freedom after 1 day of travel. If it is assumed that the prisoner will always select doors 1,2,and 3 with respective probabilities 0.5, 0.3, and 0.2, what is the expected number of days until the prisoner reaches freedom?
Click here to see answer by Edwin McCravy(20054) |
Question 1163179: A study was made by a retail merchant to determine the relation between weekly advertising expenditure and sales. The following data were recorded:-
Advertising Costs
Sales
40
20
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Find the equation of the regression line to predict weekly sales from advertising expenditure.
Interpret regression co-efficient and y-intercept
Can we take advertising costs as dependent variable if yes then how if not then why?
Could this question be studied using correlation, if yes then how if not then why
Click here to see answer by ikleyn(52752) |
Question 1163237: In order to conduct a hypothesis test for the population proportion, you sample 290 observations that result in 87 successes. (You may find it useful to reference the appropriate table: z table or t table)
H0: p = 0.36; HA: p ≠ 0.36.
1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
2. Find the p-value.
A. p-value > or equal to 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.025
D. 0.025 < or equal to p-value < 0.05
E. 0.05 < or equal to p-value < 0.10
3. At the 0.01 significance level, What is the conclusion?
A. Reject H0 since the p-value is greater than significance level.
B. Reject H0 since the p-value is smaller than significance level.
C. Do not reject H0 since the p-value is greater than significance level.
D. Do not reject H0 since the p-value is smaller than significance level.
4. Interpret the results at α = 0.01.
A. We conclude that the population mean differs from 0.36.
B. We cannot conclude that the population mean differs from 0.36.
C. We conclude the population proportion differs from 0.36.
D. We cannot conclude that the population proportion differs from 0.36.
Click here to see answer by Boreal(15235) |
Question 1163234: H0: μ = 73
HA: μ ≠ 73
Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table)
1. x¯ = 70; s = 6.4; n = 19
A. 0.05 < or equal to p-value < 0.10
B. p-value < 0.01
C. 0.01 < or equal to p-value < 0.02
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
2. x¯ = 70; s = 6.4; n = 24
A. p-value < 0.01
B. 0.01 < or equal to p-value < 0.02
C. 0.05 < or equal to p-value < 0.10
D. p-value > or equal to 0.10
E. 0.02 < or equal to p-value < 0.05
Click here to see answer by Boreal(15235) |
Question 1162915: The money raised and spent (both in millions of dollars) by all congressional campaigns for 8 recent 2-year periods are shown in the table. The equation of the regression line is ^Y= 0.950X+ 22.110. Find the coefficient of determination and interpret the result.
Money raised,X: 450.9, 671.8, 730.8, 775.2, 783.6, 1034.9, 959.2, 1203.8
Money spent, Y: 441.7, 682.5, 737.1, 752.5, 731,2. 1002.7, 942.1, 1164.5
Click here to see answer by Boreal(15235) |
Question 1162828: The mean amount purchased by each customer at Churchill's Grocery Store is $ 19 with a standard deviation of $9. The population is positively skewedFor a sample of 55 customers, answer the following questions a. What is the likelihood the sample mean is at least $20? (Round the value to 2 decimal places and the final answer to 4 decimal ploces.) Sample mean 0.2061 b. What is the likelihood the sample mean is greater than $16 but less than $20( Round the zwolue to 2 decimal places and the final answer to 4 declal places.) Sample mean 0.7871 c. Within what limits will 95% of the sample means occur(Round the final answers to 2 decimal places) Sample mean 16.62 and
Click here to see answer by Boreal(15235) |
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