Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1133950: A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi?
0.59 0.68 0.10 0.98 1.37 0.55 0.97
What is the confidence interval estimate of the population mean mu?
_ppm < mu < _ ppm
(Round to three decimal places as needed.)
Click here to see answer by Boreal(15235)   |
Question 1133949: Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n equals 1011 and x equals 582 who said "yes." Use a 90 % confidence level.
a) Find the best point estimate of the population proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E =
(Round to three decimal places as needed.)
c) Construct the confidence interval.
(Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
A.
One has 99% confidence that the sample proportion is equal to the population proportion.
B.
There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
C.
One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
99% of sample proportions will fall between the lower bound and the upper bound.
Click here to see answer by Boreal(15235) |
Question 1133984: Two cards are drawn without replacement from a standard deck of
52 playing cards. What is the probability of choosing a king for the second card drawn, if the first card, drawn without replacement, was a jack? Express your answer as a fraction or a decimal number rounded to four decimal places.
Click here to see answer by Glaviolette(140)  |
Question 1133983: CNNBC recently reported that the mean annual cost of auto insurance is 1040 dollars. Assume the standard deviation is 293 dollars. You take a simple random sample of 84 auto insurance policies.
(a) Find the probability that a single randomly selected value is less than 994 dollars.
P(X < 994) =
(b) Find the probability that a sample of size n=84 is randomly selected with a mean less than 994 dollars.
P(M < 994) =
Enter your answers as numbers accurate to 4 decimal places.
Click here to see answer by Glaviolette(140) |
Question 1133979: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 150000 dollars. Assume the standard deviation is 38000 dollars. Suppose you take a simple random sample of 98 graduates.
(a) Find the probability that a single randomly selected policy has a mean value between 139252 and 141171.3 dollars.
P(139252 < X < 141171.3) =
(Enter your answers as numbers accurate to 4 decimal places.)
Find the probability that a random sample of size n=98 has a mean value between 139252 and 141171.3 dollars.
P(139252 < M < 141171.3) =
(Enter your answers as numbers accurate to 4 decimal places.)
Click here to see answer by Glaviolette(140) |
Question 1133958: Start of Questions
Stu Dent has 11 different math books, 14 different science books and 9 different engineering books. Find the number of ways to pick two books with different subjects.
Hint: Consider 3 separate cases which depend on the selected subjects.
Click here to see answer by Glaviolette(140) |
Question 1133957: A group of 6 friends are playing poker one night, and one of the friends decides to try out a new game. They are using a standard 52-card deck. The dealer is going to deal the cards face up. There will be a round of betting after everyone gets one card. Another round of betting after each player gets a second card, etc. Once a total of 7 cards have been dealt to each player, the player with the best hand will win. However, if any player is dealt one of the designated cards, the dealer collects all cards, shuffles, and starts over.
The designated cards are: 7 of Spades, 5 of Hearts, Ace of Clubs. The players wish to determine the likelihood of actually getting to play a hand without mucking the cards and starting over.
What is the probability of a successful hand that will go all the way till everyone gets 7 cards?
Click here to see answer by Glaviolette(140) |
Question 1133948: Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n equals 1011 and x equals 582 who said "yes." Use a 90 % confidence level.
a) Find the best point estimate of the population proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E =
(Round to three decimal places as needed.)
c) Construct the confidence interval.
(Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
A.
One has 99% confidence that the sample proportion is equal to the population proportion.
B.
There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
C.
One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
99% of sample proportions will fall between the lower bound and the upper bound.
Click here to see answer by Glaviolette(140) |
Question 1133947: Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n equals 1080 and x equals 574 who said "yes." Use a 99 % confidence level.
LOADING... Click the icon to view a table of z scores.
a) Find the best point estimate of the population proportion p.
0.531
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
Eequals
0.039
(Round to three decimal places as needed.)
c) Construct the confidence interval.
0.492less than p less than
0.57
(Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
A.
One has 99% confidence that the sample proportion is equal to the population proportion.
B.
There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
C.
One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
Your answer is correct.D.
99% of sample proportions will fall between the lower bound and the upper bound.
Question is complete. Tap on the red indicators to see incorrect answers.
Click here to see answer by Glaviolette(140) |
Question 1133946: A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi?
0.59 0.68 0.10 0.98 1.37 0.55 0.97
What is the confidence interval estimate of the population mean mu?
_ppm < mu < _ ppm
(Round to three decimal places as needed.)
Click here to see answer by Glaviolette(140) |
Question 1133941: A box contains n balls marked from 1 to n.Two balls drawn in succession with replacement. Find the probability that number on the balls are consecutive integers(ignore the order of balls)?
I find it 2*(n-1)/n^2.
Is that correct?
Click here to see answer by Glaviolette(140) |
Question 1133941: A box contains n balls marked from 1 to n.Two balls drawn in succession with replacement. Find the probability that number on the balls are consecutive integers(ignore the order of balls)?
I find it 2*(n-1)/n^2.
Is that correct?
Click here to see answer by ikleyn(52752)  |
Question 1133772: The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.
For a sample of n =75, find the probability of a sample mean being greater than
217 if μ= 216 and σ= 6.1.
For a sample of n=75, the probability of a sample mean being greater than
217 if μ=216 and σ= 6.1 is?
Click here to see answer by Boreal(15235) |
Question 1133728: Twenty tires are tested to see if they last as long as they claim they do. Three tire fail the test. Two tires are selected at random without replacement for a detained inspection.
A. What the probability that both tires failed the test.
B. What is greater the probability that the first tire passed the test and the second one failed or the probability that the first one passed and the second one passed?
C. Suppose 2 tires are selected at random without replacement 60 times, how can we predict the number of times both tires fail the test
Click here to see answer by Boreal(15235) |
Question 1133819: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.
99% confidence; n=6500; x= 1950
Click here to see answer by Glaviolette(140) |
Question 1133708: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 150000 dollars. Assume the standard deviation is 38000 dollars. Suppose you take a simple random sample of 98 graduates.
1. Find the probability that a single randomly selected policy has a mean value between 139252 and 141171.3 dollars.
P(139252 < X < 141171.3) = ___________(Enter your answers as numbers accurate to 4 decimal places.)
2. Find the probability that a random sample of size
n=98 has a mean value between 139252 and 141171.3 dollars.
P(139252 < M < 141171.3) = ________(Enter your answers as numbers accurate to 4 decimal places.)
Click here to see answer by Boreal(15235) |
Question 1134025: The local Homeowners Association determined that 53% of the houses in a random town were painted white. If 2,000 houses are selected from this town a random, what is the probability that less than half of the houses would be painted white?
Click here to see answer by Glaviolette(140) |
Question 1134057: In a certain region all license plates are composed of three letters followed by three numbers, or three numbers followed by three letters. The only restriction is that zero can never be the first of the three numbers if the three numbers come first. Find how many license plates are possible.
Click here to see answer by Glaviolette(140) |
Question 1133770: CNNBC recently reported that the mean annual cost of auto insurance is 1040 dollars. Assume the standard deviation is 293 dollars. You take a simple random sample of 84 auto insurance policies.
1. Find the probability that a single randomly selected value is less than 994 dollars.
P(X < 994) = _________
2. Find the probability that a sample of size n=84 is randomly selected with a mean less than 994 dollars.
P(M < 994) = ___________
Enter your answers as numbers accurate to 4 decimal places.
Click here to see answer by Boreal(15235) |
Question 1133415: Patient response to a generic drug to control pain is scored on a 5 point scale where a 5 indicate relief. Historically, the distribution of score are:
1 - (0.05)
2 - (0.1)
3 - (0.2)
4 - (0.25)
5 - (0.4)
Two patients, assumed to be independent, are each score.
Click here to see answer by Shin123(626)  |
Question 1134103: The workers in a VS shop need to attend a competency course and pass three tests. The probability of passing the first test is 0.8 and if a worker passes a test, the probability that the worker will pass the subsequent test is 0.7. Instead, if the worker fails, the probability that the worker will fail the subsequent test is 0.8. Find the probability that a worker will pass the first and the third test? Find the probability that a worker will pass at least two tests?Find the conditional probability that a worker will pass the first and the third test, given that a worker will pass at least two tests? Find the probability that a worker will fail all tests or pass all tests?
Click here to see answer by Shin123(626) |
Question 1134103: The workers in a VS shop need to attend a competency course and pass three tests. The probability of passing the first test is 0.8 and if a worker passes a test, the probability that the worker will pass the subsequent test is 0.7. Instead, if the worker fails, the probability that the worker will fail the subsequent test is 0.8. Find the probability that a worker will pass the first and the third test? Find the probability that a worker will pass at least two tests?Find the conditional probability that a worker will pass the first and the third test, given that a worker will pass at least two tests? Find the probability that a worker will fail all tests or pass all tests?
Click here to see answer by greenestamps(13195)  |
Question 1134100: A team of four members consisting of eight mathematicians and seven chemists will be selected. Calculate the number of different ways to form a team member if all members are mathematicians? if the number of mathematicians and chemists are equal? if the team contains at least two mathematicians?
Click here to see answer by Boreal(15235) |
Question 1134221: A researcher looked at the occurrence of retinal capillary hemangioma (RCH) in patients with von Hippel - Lindau (VHL) disease. RCH is a benign vascular tumor of the retina. Using a retrospective consecutive case series review, the researchers found that the number of RCH tumor incidents followed a Poisson distribution with λ = 3 tumors per eye for patients with VHL. Using this model, find the probability that in a randomly selected patient with VHL:
a. There are exactly four occurrences of tumors per eye.
b. There are more than four occurrences of tumors per eye.
c. There are fewer than four occurrences of tumors per eye.
d. There are between four and six occurrences of tumors per eye, inclusive.
Click here to see answer by Boreal(15235) |
Question 1134222: Question No. 7
A study conducted among 29-year-old male, acetone levels were normally distributed with a mean of 1070 and a standard deviation of 311 ppb. Find the probability that on a given day the subject’s acetone level is:
a. Between 700 and 1100 ppb
b. Over 1000 ppb
c. Under 600 ppb
d. Between 1000 and 1200 ppb
Question No. 8
The weights of a certain population of young adult females are approximately normally distributed with a mean of 231 pounds and a standard deviation of 21. Find the probability that a subject selected at random from this population will weigh:
a. More than 175 pounds
b. 121 pounds or less
c. Between 115 and 155 pounds
Click here to see answer by Boreal(15235) |
Question 1134218: Carol McHugh has 3 quarters, 4 dimes, and 2 nickels in her purse. she takes one coin out of her purse without looking.
a) find the probability that carol has taken: (1) a quarter; (2) a dime; (3) a nickel
b) show that the sum of the probabilities from part a is 1.
c) find the probability that the coin has taken is worth: (1) less than 25 cents; (2)less than 25 cents; (3) not more than 5 cents
I understand how to do both a and b, however, got stuck with c.1,2 and 3.
thanks for helping!
Click here to see answer by Theo(13342)  |
Question 1134218: Carol McHugh has 3 quarters, 4 dimes, and 2 nickels in her purse. she takes one coin out of her purse without looking.
a) find the probability that carol has taken: (1) a quarter; (2) a dime; (3) a nickel
b) show that the sum of the probabilities from part a is 1.
c) find the probability that the coin has taken is worth: (1) less than 25 cents; (2)less than 25 cents; (3) not more than 5 cents
I understand how to do both a and b, however, got stuck with c.1,2 and 3.
thanks for helping!
Click here to see answer by Glaviolette(140) |
Question 1134213: The probability that John parks in a no parking zone and gets a parking ticket is 0.08 and the probability John cannot get a legal parking space and has to park in a no parking zone is 0.4. On Friday, John arrives at Campus and has to park in a no parking zone. What is the probability that he will get a parking ticket.
Click here to see answer by Glaviolette(140) |
Question 1134232: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 189000 dollars. Assume the standard deviation is 34000 dollars. Suppose you take a simple random sample of 97 graduates.
(a) Find the probability that a single randomly selected policy has a mean value between 190726.1 and 197975.7 dollars.
P(190726.1 < X < 197975.7) = _____________
(Enter your answers as numbers accurate to 4 decimal places.)
(b) Find the probability that a random sample of size n=97 has a mean value between 190726.1 and 197975.7 dollars.
P(190726.1 < M < 197975.7) = ______________
(Enter your answers as numbers accurate to 4 decimal places.)
Click here to see answer by Glaviolette(140) |
Question 1134235: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 166000 dollars. Assume the standard deviation is 37000 dollars. Suppose you take a simple random sample of 62 graduates.
Find the probability that a single randomly selected policy has a mean value between 160831.1 and 169759.2 dollars.
P(160831.1 < X < 169759.2) = ______________
(Enter your answers as numbers accurate to 4 decimal places.)
**Below is what I have tried before and the system told me that it is wrong (note: the numbers are different because it switches the numbers in every attempt):
mean= 150,000 standard deviation=38,000 n=98
P(139252 < X < 141171.3)
z=(139252-150,000)/38,000 = -.28
z= (141171.3-150,000)/38,000 = -.23
From z-table: 0.4090 - 0.3897 = 0.0193
Click here to see answer by Glaviolette(140) |
Question 1134243: Suppose the scores of students on a Statistics course are Normally distributed with a mean of 226 and a standard deviation of 55.
What percentage of the students scored between 226 and 336 on the exam? (Give your answer to 3 significant figures.)
Click here to see answer by Glaviolette(140) |
Question 1134242: The price-earnings (PE) ratios of a sample of stocks have a mean value of 12.25 and a standard deviation of 1.7. If the PE ratios have a bell shaped distribution, use the 68-95-99.7 Rule to estimate the percentage of PE ratios that fall between:
Click here to see answer by Glaviolette(140) |
Question 1134279: In a survey of nursing students pursuing a master’s degree, 84 percent stated that they expect to be promoted to a higher position within one month after receiving the degree. If this percentage holds for the entire population, find, for a sample of 20, the probability that the number expecting a promotion within a month after receiving their degree is:
a. Five b. At least six
c. No more than four d. Between five and eight, inclusive
Click here to see answer by rothauserc(4718)  |
Question 1134345: A blue plastic container has four black pieces of cloth, two striped pieces, and six dotted pieces, each representing the category of patient depending on illness status. Stripped for mild and dotted for severe illness. A piece is selected randomly and then placed back in the box. A second piece is selected randomly. What is the probability that: a. both pieces are dotted? b. the first piece is black and the second piece is dotted? c. one piece is black and one piece is striped?
Click here to see answer by Boreal(15235) |
Question 1134344: 7. Consider the approximately normal population of heights of male college students with mean μ = 65 inches and standard deviation of σ = 4 inches. A random sample of 16 heights is obtained.
(a) Describe the distribution of x, height of male college students. (Choose one)
-skewed right
-approximately normal
-skewed left
-chi-square
(b) Find the proportion of male college students whose height is greater than 72 inches. (Give your answer correct to four decimal places.)
(c) Describe the distribution of x, the mean of samples of size 16.
-skewed right
-approximately normal
-skewed left
-chi-square
(d) Find the mean of the x distribution. (Give your answer correct to the nearest whole number.)
(ii) Find the standard error of the x distribution. (Give your answer correct to four decimal places.)
(e) Find P(x > 71). (Give your answer correct to four decimal places.)
(f) Find P(x < 70). (Give your answer correct to four decimal places.)
Click here to see answer by Boreal(15235) |
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3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 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