Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1132378: 1. Is It Unusual? A population is normally distributed with a mean of 100 and a standard deviation of 15. Determine if the following event is unusual. Explain your reasoning.
a. mean of a sample of 3 is 115 or more
b. mean of a sample of 20 is 105 or more
Click here to see answer by Theo(13342)   |
Question 1132437: One hundred twenty people seated at different tables in a Mexican food restaurant were asked if their party had ordered any of the following items: enchiladas, chili con queso or quesadillas. 21 people had ordered none of these items; No one ordered only chili con queso; 5 ordered only quesadillas; 11 people had ordered all three of these items; 29 people had ordered chili con queso or quesadillas but did not order enchiladas; 79 people had ordered at least two of these items; 13 people had ordered enchiladas and quesadillas but had not ordered chili con queso; 26 people had ordered only enchiladas and chili con queso.
What is the probability of choosing two persons that ordered only enchiladas?
Click here to see answer by greenestamps(13198)  |
Question 1132436: Here’s a question we were unsure of.
According to a study of the numbers of male and female children in families in a certain population, a model has been determined that for any subsequent children, the probability that they will be of the same gender as the previous child is 3/5. Using this model, calculate the probability that, in a randomly chosen family of 3 children, there will be;
a) 2 males and 1 female
b) at least one female
Hence, construct the probability distribution table of X if X is the number of female selected among the 3 children.
Click here to see answer by Boreal(15235)  |
Question 1132436: Here’s a question we were unsure of.
According to a study of the numbers of male and female children in families in a certain population, a model has been determined that for any subsequent children, the probability that they will be of the same gender as the previous child is 3/5. Using this model, calculate the probability that, in a randomly chosen family of 3 children, there will be;
a) 2 males and 1 female
b) at least one female
Hence, construct the probability distribution table of X if X is the number of female selected among the 3 children.
Click here to see answer by greenestamps(13198) |
Question 1132379: The mean age of students at a high school is 16.5 with a standard deviation of 0.7. You use the Standard Normal Table to help you determine that the probability of selecting one student at random and finding his or her age to be more than 17.5 years is about 8%. What is the error in this problem?
Click here to see answer by rothauserc(4718)  |
Question 1132454: the probability that 3boys passed an exam are 2/3,5/8,3/4 respectively.find the probability that all the three boys passed and also the probability that none of the three boys passed .fin
d the probability that only two boys passed
Click here to see answer by ikleyn(52765)  |
Question 1132471: carl's basketball shooting record indicates that for any frame, the probability in a 2 point shoot is 30 percent,a 3 point shoot 45 percent,and neither,25 percent.what is the probabillity that cindy will score either in a 2point shoot or in 3 point shoot?
Click here to see answer by ikleyn(52765) |
Question 1132470: of 240 students 176 are on honor roll 48 are members of the varsity team and 36 are in the honor roll and are also members of the varsity team.what is the probability that a randomly selected student is honor roll or is a member of the varsity team?
Click here to see answer by ikleyn(52765) |
Question 1132477: Subjects for the next presidential election poll are contacted using telephone numbers in which the last four digits are randomly selected (with replacement). Find the probability that for one such phone number, the last four digits include at least one 0.
The probability is ?
Click here to see answer by ikleyn(52765) |
Question 1132476: Subjects for the next presidential election poll are contacted using telephone numbers in which the last four digits are randomly selected (with replacement). Find the probability that for one such phone number, the last four digits include at least one 0.
The probability is_?
Click here to see answer by ikleyn(52765) |
Question 1132460: A real estate agent has 18 properties that she shows. She feels that there is a 40% chance of selling any one property during a week. The chance of selling any one property is independent of selling another property. Compute the probability of selling less than 2 properties in one week. (Answer must be written as a simplified fraction or rounded to four decimal places)
Click here to see answer by ikleyn(52765) |
Question 1132397: Suppose a discrete random variable X has a probability density function given by:
x 3 5 7 8 9 10 12 16
P(X=x) 0.08 0.10 0.16 0.25 0.20 0.03 0.13 0.05
(Note: The probabilities add to one. Any value x which is not in the table has probability zero.)
a) Calculate P(X > 9)
b) Calculate P(X is bigger than or equal to 9)
c) Calculate P(5 < X is smaller than or equal to 10)
d) Calculate the expected value of X, E(X)
Click here to see answer by Boreal(15235) |
Question 1132539: Sally found the magic number 12345679 in a book by Lewis Carroll. She got two students in her class to tell her their favourite numbers. The first was 3 and the second was 5. Sally first multiplied each of these numbers by 9, giving her 27 and 45. She then multiplied the Magic Number by 27, wrote down the answer on the board, and then did the same with 45. The sum of these two answers was:
a) 884 632 198 b)888 888 888 c) 788 365 288 d)222 222 222
Click here to see answer by MathLover1(20849)  |
Question 1132601: Two guys walk into a bar; the third one ducks. If these three men acted independently, and the probability is 0.7 that a person who is about to walk into a bar instead ducks to avoid the bar, then what was the probability of observing the first two walking into the bar and the third ducking?
Click here to see answer by Boreal(15235) |
Question 1132398: A machine is used to regulate the amount of dye dispensed for mixing shades of paint. Suppose the amount of dye dispensed per paint can is normally distributed with a mean of 6 ml and a standard deviation of 0.4 ml.
a) What proportion of paint cans will have more than 6.5 ml of dye?
b) Find the amount of dye that the bottom 2% of paint cans have less than.
c) Suppose that new quality control procedures are introduced that lower the standard deviation from 0.4 to a new value (the mean is still 6 ml). With this new standard deviation, we are told that 98% of the paint cans contain between 5.5 and 6.5 ml of dye. Calculate the standard deviation.
Click here to see answer by Boreal(15235) |
Question 1131184: Assume that the significance level is alpha equals 0.05. Use the given information to find the P-value and the critical value(s).
With Upper H 1 : p does not equal one half
, the test statistic is equaled negative 1.18.
Click here to see answer by Boreal(15235) |
Question 1132664: A researcher found that 55% of families in the United States have one child under the age of 21, 22% have two children under the age of 21, 15% have three children under the age of 21, 5% have 4 children under the age of 21and 3% have 5 or more children under the age of 21. If a family is selected at random, what is the probability the family has at least 3 children under the age of 21? (Express your answer as a percent, Please include the % symbol.)
Click here to see answer by Theo(13342) |
Question 1132686: If a fair coin is flipped twice and a standard 6-sided die is rolled twice, what is the likelihood of getting two 'heads' on the coin and a '6' on the die twice?
​Express your answer as a decimal rounded to the ten - thousandths place.
Click here to see answer by solver91311(24713)  |
Question 1132697: Textbook prices have a seasonal structure on Ebay. At the end of a term, the supply of used books outstrips demand, and the price is lower. Near the start of a term, many students are looking for books, and the price is higher. Suppose we can classify sales for a particular chemistry textbook into these two time periods and an "other" time period in the proportions shown below. We have also listed the average price the textbook sells for in each of these three time periods
Sales proportion--> Start of term: 0.45, End of term: 0.31, Other: 0.24
Average Price--> Start of term:$82.52, End of term:$49.12, Other: $65.23
For example, about 45% of Ebay auctions for this chemistry textbook occur at the start of the term and the books sell for an average of $82.52 during this time. Using the information above, compute the average price of the textbook over all seasons. (Do not put a dollar sign in your answer.)
Click here to see answer by stanbon(75887) |
Question 1132663: A surprising number of people are scared of clowns. You expect that people will have more nightmares the night that they see clowns at the circus. To test this, you send a group of people to a circus with clowns, and a group to a circus without clowns, and measure the number of people in each group who have nightmares that night. Your data is shown below:
Nightmares Nice dreams
No clowns 12 35
Clowns 30 8
Perform a Z-test on nightmares after the no-clown circus minus nightmares after the clown circus. Report the test statistic.
Click here to see answer by stanbon(75887) |
Question 1132661: A random sample of 61 Basic Statistics students were asked what they thought of statistics on a scale of 0 (very stupid) to 100 (very nice). Interestingly, students seem to find statistics quite nice: the sample mean equals 83. The sample standard deviation equals 7. We know that the standard deviation in the population (all BS students) is 8. Calculate the 90% confidence interval.
Click here to see answer by stanbon(75887) |
Question 1132694: A portfolio's value increases by 18% during a financial boom and by 9% during normal times. It decreases by 12% during a recession. What is the expected return on this portfolio if each scenario is equally likely? (round to the nearest whole percent)
Click here to see answer by ikleyn(52765) |
Question 1132699: The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 2 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 13 percent. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 10 percent.
Calculate the probability that a positive test result means someone has Zika.
(Answer in percent to 2 decimal places).
Click here to see answer by Boreal(15235) |
Question 1132696: An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 54% of passengers have no checked luggage, 34% have only one piece of checked luggage and 12% have two pieces. We suppose a negligible portion of people check more than two bags.
) The average baggage-related revenue per passenger is: $
(please round to the nearest cent)
b) The standard deviation of baggage-related revenue is: $
(please round to the nearest cent)
c) About how much revenue should the airline expect for a flight of 120 passengers? $
(please round to the nearest dollar)
Click here to see answer by Boreal(15235) |
Question 1132695: A grocery store is reevaluating the retail price of their oranges. They have a contract where they can purchase oranges for $0.52 per pound. However, this includes high quality oranges (about 40% of the time), low quality oranges (55%), and occasionally rotten fruit (5%). Suppose they sell 80% of all high quality oranges at $1.99 per pound, 65% of all low quality oranges at $1.49 per pound (they offer a sale), and they cannot sell any of the rotten fruit.
What is the store's expected profit from a random shipment of 500 pounds of oranges? We do not consider personnel and other overhead costs, only the wholesale cost of the oranges. (Give your answer as a number, no dollar sign included.)
Click here to see answer by greenestamps(13198) |
Question 1132740: Heights of women have a bell-shaped distribution with a mean of 161 cm and a standard deviation of 5 cm. Using Chebyshev's theorem, what do we know about the percentage of women with heights that are within 2 standard deviations of the mean? What are the minimum and maximum heights that are within 2 standard deviations of the mean?
At least _____% of women have heights within 2 standard deviations of 161 cm.
(Round to the nearest percent as needed.)
Click here to see answer by solver91311(24713) |
Question 1132741: Determine whether the given procedure results in a binomial distribution. If it is not binomial, identify the requirements that are not satisfied.
Surveying 20 homemakers and recording how satisfied they are with their toaster on a scale from 1 to 5
Choose the correct answer below.
A.Yes,because all 4 requirements are satisfied.
B.No, because the probability of success does not remain the same in all trials.
C.No, because there are more than two possible outcomes.
D.No, because there are more than two possible outcomes and the trials are not independent.
Click here to see answer by solver91311(24713) |
Question 1132756: Refer to the accompanying table, which describes the number of adults in groups of five who reported sleepwalking. Find the mean and standard deviation for the numbers of sleepwalkers in groups of five.
LOADING... Click the icon to view the data table.
The mean is
_sleepwalker(s). (Round to one decimal place as needed.)
Click here to see answer by ikleyn(52765) |
Question 1132731: Hi!
Can you help explain this problem?
The personnel office at a large electronics firm regularly schedules job interviews and maintains records of the interviews. From past records, they have found that the length of a first interview is normally distributed with mean u=35 minutes and standard deviation q=7 minutes.
a) WHat is the probability that the interview will last 40 minutes or longer?
b)Nine first interviews are usually scheduled per day. What is the probability that the average length of time for the 9 interviews will be 40 minutes or longer.
Click here to see answer by Theo(13342) |
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33526..33570, 33571..33615, 33616..33660, 33661..33705, 33706..33750, 33751..33795, 33796..33840, 33841..33885, 33886..33930, 33931..33975, 33976..34020, 34021..34065, 34066..34110, 34111..34155, 34156..34200, 34201..34245, 34246..34290, 34291..34335, 34336..34380, 34381..34425, 34426..34470, 34471..34515, 34516..34560, 34561..34605, 34606..34650, 34651..34695, 34696..34740, 34741..34785, 34786..34830, 34831..34875, 34876..34920, 34921..34965, 34966..35010, 35011..35055, 35056..35100, 35101..35145, 35146..35190, 35191..35235, 35236..35280, 35281..35325, 35326..35370, 35371..35415, 35416..35460, 35461..35505, 35506..35550, 35551..35595, 35596..35640, 35641..35685, 35686..35730, 35731..35775, 35776..35820, 35821..35865, 35866..35910, 35911..35955, 35956..36000, 36001..36045, 36046..36090, 36091..36135, 36136..36180, 36181..36225, 36226..36270, 36271..36315, 36316..36360, 36361..36405, 36406..36450, 36451..36495, 36496..36540, 36541..36585, 36586..36630, 36631..36675, 36676..36720, 36721..36765, 36766..36810, 36811..36855, 36856..36900, 36901..36945, 36946..36990, 36991..37035, 37036..37080, 37081..37125, 37126..37170, 37171..37215, 37216..37260, 37261..37305, 37306..37350, 37351..37395, 37396..37440, 37441..37485, 37486..37530, 37531..37575, 37576..37620, 37621..37665, 37666..37710, 37711..37755, 37756..37800, 37801..37845, 37846..37890, 37891..37935, 37936..37980, 37981..38025, 38026..38070, 38071..38115, 38116..38160, 38161..38205, 38206..38250, 38251..38295, 38296..38340, 38341..38385, 38386..38430, 38431..38475, 38476..38520, 38521..38565, 38566..38610, 38611..38655, 38656..38700, 38701..38745, 38746..38790, 38791..38835, 38836..38880, 38881..38925, 38926..38970, 38971..39015, 39016..39060, 39061..39105, 39106..39150, 39151..39195, 39196..39240, 39241..39285, 39286..39330, 39331..39375, 39376..39420, 39421..39465, 39466..39510, 39511..39555, 39556..39600, 39601..39645, 39646..39690, 39691..39735, 39736..39780, 39781..39825, 39826..39870, 39871..39915, 39916..39960, 39961..40005, 40006..40050, 40051..40095, 40096..40140, 40141..40185, 40186..40230, 40231..40275, 40276..40320, 40321..40365, 40366..40410, 40411..40455, 40456..40500, 40501..40545, 40546..40590, 40591..40635, 40636..40680, 40681..40725, 40726..40770, 40771..40815, 40816..40860, 40861..40905, 40906..40950, 40951..40995, 40996..41040, 41041..41085, 41086..41130, 41131..41175, 41176..41220, 41221..41265, 41266..41310, 41311..41355, 41356..41400, 41401..41445, 41446..41490, 41491..41535, 41536..41580, 41581..41625, 41626..41670, 41671..41715, 41716..41760, 41761..41805, 41806..41850, 41851..41895, 41896..41940, 41941..41985, 41986..42030, 42031..42075, 42076..42120, 42121..42165, 42166..42210, 42211..42255, 42256..42300, 42301..42345, 42346..42390, 42391..42435, 42436..42480, 42481..42525, 42526..42570, 42571..42615, 42616..42660, 42661..42705, 42706..42750, 42751..42795, 42796..42840, 42841..42885, 42886..42930, 42931..42975, 42976..43020, 43021..43065, 43066..43110, 43111..43155, 43156..43200, 43201..43245, 43246..43290, 43291..43335, 43336..43380, 43381..43425, 43426..43470, 43471..43515, 43516..43560, 43561..43605, 43606..43650, 43651..43695, 43696..43740, 43741..43785, 43786..43830, 43831..43875, 43876..43920, 43921..43965, 43966..44010, 44011..44055, 44056..44100, 44101..44145, 44146..44190, 44191..44235, 44236..44280, 44281..44325, 44326..44370, 44371..44415, 44416..44460, 44461..44505, 44506..44550, 44551..44595, 44596..44640, 44641..44685, 44686..44730, 44731..44775, 44776..44820, 44821..44865, 44866..44910, 44911..44955, 44956..45000, 45001..45045, 45046..45090, 45091..45135, 45136..45180, 45181..45225, 45226..45270, 45271..45315, 45316..45360, 45361..45405, 45406..45450, 45451..45495, 45496..45540, 45541..45585, 45586..45630, 45631..45675, 45676..45720, 45721..45765, 45766..45810, 45811..45855, 45856..45900, 45901..45945, 45946..45990, 45991..46035, 46036..46080, 46081..46125, 46126..46170, 46171..46215, 46216..46260, 46261..46305, 46306..46350, 46351..46395, 46396..46440, 46441..46485, 46486..46530, 46531..46575, 46576..46620, 46621..46665, 46666..46710, 46711..46755, 46756..46800, 46801..46845, 46846..46890, 46891..46935, 46936..46980, 46981..47025, 47026..47070, 47071..47115, 47116..47160, 47161..47205, 47206..47250, 47251..47295, 47296..47340, 47341..47385, 47386..47430, 47431..47475, 47476..47520, 47521..47565, 47566..47610, 47611..47655, 47656..47700, 47701..47745, 47746..47790, 47791..47835, 47836..47880, 47881..47925, 47926..47970, 47971..48015, 48016..48060, 48061..48105, 48106..48150, 48151..48195, 48196..48240, 48241..48285, 48286..48330, 48331..48375, 48376..48420, 48421..48465, 48466..48510, 48511..48555, 48556..48600, 48601..48645, 48646..48690, 48691..48735, 48736..48780, 48781..48825, 48826..48870, 48871..48915, 48916..48960, 48961..49005, 49006..49050, 49051..49095, 49096..49140, 49141..49185, 49186..49230, 49231..49275, 49276..49320, 49321..49365, 49366..49410, 49411..49455, 49456..49500, 49501..49545, 49546..49590, 49591..49635, 49636..49680, 49681..49725, 49726..49770, 49771..49815, 49816..49860, 49861..49905, 49906..49950, 49951..49995, 49996..50040, 50041..50085, 50086..50130, 50131..50175, 50176..50220, 50221..50265, 50266..50310, 50311..50355, 50356..50400, 50401..50445, 50446..50490, 50491..50535, 50536..50580, 50581..50625, 50626..50670, 50671..50715, 50716..50760, 50761..50805, 50806..50850, 50851..50895, 50896..50940, 50941..50985, 50986..51030, 51031..51075, 51076..51120, 51121..51165, 51166..51210, 51211..51255, 51256..51300, 51301..51345
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