Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1121413: The ATM at a local convenience store allows customers to make withdrawals of $10, $20, $50, or $100. Let X denote a random variable that indicates the amount withdrawn by a customer. The probability distribution of X is
P(10) = 0.2
P(20) = 0.5
P(50) = 0.2
P(100) = 0.1
(a) Draw the probability distribution of X.
(b) What is the probability that a customer withdraws more than $20?
(c) What is the expected amount of money withdrawn by a customer?
(d) The expected value is not a possible value of the amount withdrawn. Interpret the expected value for a manager.
(e) Find the variance and standard deviation of X.
Click here to see answer by Boreal(15235)   |
Question 1121415: A basketball team is down by 2 points with only a few seconds remaining in the game. There’s a 50% chance that the team will be able to make a 2-point shot and tie the game, compared to a 30% chance that it will make a 3-point shot and win. If the game ends in a tie, the game continues to overtime. In overtime, the team has a 50% chance of winning. What should the coach do, go for the 2-point shot or the 3-point shot? Be sure to identify any assumptions you make.
Click here to see answer by Boreal(15235) |
Question 1120532: study was conducted to see whether monetary incentives to use less water during times of drought had an effect on water usage. Sixty single family homeowners were randomly assigned to one of two groups: 1) monetary incentives and 2) no monetary incentives. At the end of three months, the total amount of water usage for each household, in gallons, was measured.
(a) What would be the appropriate hypothesis test to use to test the claim that monetary incentives reduce water usage?
i. t-test for two independent samples
ii. t-test for dependent samples
iii. z-test for population mean
iv. correlation
(b) Explain the rationale for your selection in (a). Specifically, why would this be the appropriate statistical approach?
Click here to see answer by Boreal(15235) |
Question 1121459: toss five coins together and define a random variable X as the number of heads.
range of space S = [0, 1, 2, 3, 4, 5]
Repeat the experiment 30 times and find the observed frequency, and the expected frequency.
Click here to see answer by ikleyn(52750)  |
Question 1121439: Not everyone pays the same price for the same model of a car. Suppose the price of a car is normally distributed. The figure illustrates a normal distribution for the prices paid for a particular model of a new car.The mean is $21,000 and the standard deviation is $2000, use the 68-95-99.7 ruled to find what percentage of buyers paid between $15,000 and $21,000
it's a graph as 15=99.7% 17= 9.5% 19= 68% 21= it's in the middle between 19 and 23 23=68% 25=9.5 27-99.7
Click here to see answer by Boreal(15235) |
Question 1121438: find the median for the data item in given frequency distribution
Score x= 1,2,3,4,5,6,7,8
frequency f= 2,3,3,3,5,5,4,1
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Question 1120975: Check my work mode .: This shows what is correct or incorrect for the work you have completed so far. It does not indicate completion.
Item2
10
points
Return to question Item 2 Item 2 10 points
Ms. Lisa Monnin is the budget director for Nexus Media Inc. She would like to compare the daily travel expenses for the sales staff and the audit staff. She collected the following sample information.
Sales ($) 131 133 148 166 138 140
Audit ($) 123 141 128 143 153 127 131
At the 0.100 significance level, can she conclude that the mean daily expenses are greater for the sales staff than the audit staff?
Click here for the Excel Data File
State the decision rule. (Round your answer to 3 decimal places.)
Compute the pooled estimate of the population variance. (Round your answer to 2 decimal places.)
Compute the test statistic. (Round your answer to 3 decimal places.)
State your decision about the null hypothesis.
Do not reject H0: μs ≤ μa
Reject H0: μs ≤ μa
Estimate the p-value.
Between 0.10 and 0.15
Between 0.001 and 0.005
Between 0.005 and 0.01
Between 0.01 and 0.025
Click here to see answer by Boreal(15235) |
Question 1121478: In a survey of 3236 adults, 1495 say they have started paying bills online in the last year.
Construct a 99% confidence interval for the population proportion. Interpret the results.
A 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis
.
(Round to three decimal places as needed.)
Click here to see answer by Boreal(15235) |
Question 1121493: Estimate the indicated probability by using the normal distribution as an approximation of the binomial distribution. A multiple choice exam consists of 60 questions. Each question has 4 possible answers of which one is correct. If all the answers are random guesses, calculate the probability of obtaining at least 20% of correct answers.
Click here to see answer by rothauserc(4718)  |
Question 1121479: In a survey of 6000 ;women, 3431 say they change their nail polish once a week. Construct a 99 % confidence interval for the population proportion of women who change their nail polish once a week.
A 99% confidence interval for the population proportion is (
nothing,
nothing)
(Round to three decimal places as needed.)
Click here to see answer by Boreal(15235) |
Question 1121476: People were polled on how many books they read the previous year. How many subjects are needed to estimate the number of books read the previous year within one book with 95% confidence? Initial survey results indicate that sigmaequals19.5 books.
A 95 % confidence level requires
nothing subjects.
(Round up to the nearest whole number as needed.)
Click here to see answer by Boreal(15235) |
Question 1121477: Construct the indicated confidence interval for the population mean mu using a t-distribution.
cequals0.95, x overbarequals115, sequals10, nequals12
The confidence interval is left parenthesis nothing comma nothing right parenthesis .
(Round to the nearest tenth as needed.)
Click here to see answer by Boreal(15235) |
Question 1121524: Sixty five percent of 12th graders attend school in a particular urban district. If a sample of 450 12th grade children is selected.
1. Find the probability that at least 290 are actually enrolled in the school
Click here to see answer by Boreal(15235) |
Question 1121536: A lacrosse team has been in its premier league for the last 47 seasons. During this time they have a mean number of wins of 17.3 and a standard deviation of 2.2 wins.
[2] a) What is the probability of the lacrosse team getting 21 wins in the upcoming season?
[3] b) What is the probability of the lacrosse team getting between 15 and 18 wins?
Click here to see answer by Boreal(15235) |
Question 1121480: A researcher wishes to estimate, with 99% confidence, the population proportion of adults who are confident with their country's banking system. His estimate must be accurate within 3% of the population proportion.
(a) No preliminary estimate is available. Find the minimum sample size needed.
(b) Find the minimum sample size needed, using a prior study that found that 26% of the respondents said they are confident with their country's banking system.
(c) Compare the results from parts (a) and (b).
(a) What is the minimum sample size needed assuming that no prior information is available?
nequals
nothing (Round up to the nearest whole number as needed.)
Click here to see answer by Boreal(15235) |
Question 1121572: A journal polled its readers to determine the proportion of wives who, if given a second chance, would marry their husband again.
According to the responses from the survey, 72% of wives would marry their husbands again.
Suppose a random and independent sample of 5 wives was collected. Define the random variable X as the number of these wives who would marry their husbands again. Use the binomial distribution to find the probability that at most 4 of the wives sampled said they would marry their husbands again.
Select one:
a. 0.998279
b. 0.806508
c. 0.376234
d. 0.193492
Thanks in advance
Click here to see answer by FrankM(1040)  |
Question 1121573: Consider the discrete probability distribution below when answering the following question. Find the probability that X equals 5.
x 2 5 6 8
pr(X=x) 0.25 ? 0.16 0.08
Select one:
a. 0.51
b. 0.49
c. 0.55
d. 0.45
Thanks in advance
Click here to see answer by rothauserc(4718) |
Question 1121571: A university IT department uses a statistical model to help to determine how much student printing capacity to provide. The model assumes that print jobs arrive in a print queue at random and independently. The model also assumes that the average number of print jobs arriving per hour is 150.
Decide what kind of distribution is being used to model the number of print jobs arriving in an interval of time and use this to find the probability of less than 5 print jobs arriving in a one minute interval.
Enter your answer, correct to 3 decimal places
Thanks in advance
Click here to see answer by Boreal(15235) |
Question 1121570: A canvas manufacturer has to adjust the price of the canvas it sells according to how many flaws are present. The manufacturer uses a statistical model to predict numbers of flaws and hence sales revenue. The model assumes that there will be an average of 0.003 flaws per metre and 1000 x 0.003 = 3.0 flaws per 1000 metres.
Decide what kind of distribution is being used to model the number of flaws and use this to find the probability of more than 2 flaws in one 1000m length of canvas.
Enter your answer, correct to 3 decimal places, into the box below
Thanks in advance
Click here to see answer by Boreal(15235) |
Question 1121569: The probability that an individual is left-handed is 0.13. In a class of 20 students, use the binomial distribution to determine what is the mean and standard deviation of the number of left-handers in the class?
a. mean: 2.6; standard deviation: 1.61
b. mean: 2.6; standard deviation: 1.50
c. mean: 20; standard deviation: 1.50
d. mean: 20; standard deviation: 1.61
have a look please
Click here to see answer by Boreal(15235) |
Question 1121556: A gambler places a bet on a horse race. To win, she must pick the top three finishers in any order. Nine horses of equal ability are entered in the race. Assuming the horses finish in a random order, what is the probability that the gambler will win her bet?
Click here to see answer by FrankM(1040) |
Question 1121576: height of men on a baseball team have a bell shaped distribution with a mean of 174 cm and a standard deviation of 7cm. using the empirical rule what is the approximate percentage of the men between 153 cm and 195 cm and 160 cm and 188 cm
Click here to see answer by Boreal(15235) |
Question 1121566: In a basket of 50 apples, the probability of it having all at good quality is 0.35, while the probability of it having 1, 2, 3, 4 bad apples are 0.25, 0.2, 0.18, 0.02 respectively. Now if we randomly choose 10 apples and find out there is one bad apple. What is the probability of no more than 2 bad apples in the basket?
Click here to see answer by Boreal(15235) |
Question 1121525: Sixty five percent of 12th graders attend school in a particular urban district. If a sample of 450 12th grade children is selected.
1. Find the probability that at least 290 are actually enrolled in the school
2. Find the probability that less than 300 are actually enrolled in the school.
3. Find the probability that more than 280 are actually enrolled in the school.
Click here to see answer by Boreal(15235) |
Question 1120441: #4
A survey of 36 people was conducted to compare their self-reported height to their actual height. The difference between reported height and actual height was calculated.
You're testing the claim that the mean difference is greater than 0.6.
From the sample, the mean difference was 0.85, with a standard deviation of 0.7.
Calculate the test statistic, rounded to two decimal places
Click here to see answer by Boreal(15235) |
Question 1120542: A random sample has 42 values. The sample mean is 9.5 and the sample standard deviation is 1.5. Use a level of significance of 0.02 to conduct a left-tailed test of the claim that the population mean is 10.0.
A) Are the requirements met to run a test like this?
B) What are the hypotheses for this test?
C) Compute the test statistic and the p-value for this test.
D) What is your conclusion at the 0.02 level of significance.
Click here to see answer by Boreal(15235) |
Question 1121603: For classes of 274 students, find the mean and standard deviation for the number born on the 4th of July. Ignore leap years.
b. For a class of 274 students, would two be an unusually high number who were born on the 4th of July?
a. The value of the mean is
Click here to see answer by ikleyn(52750) |
Question 1121601: Heights of women have a bell-shaped distribution with a mean of 163 cm and a standard deviation of 6 cm. Using Chebyshev's theorem, what do we know about the percentage of women with heights that are within 3 standard deviations of the mean? What are the minimum and maximum heights that are within 3 standard deviations of the mean?
At least ___% of women have heights within 3 standard deviations of 163 cm.
(Round to the nearest percent as needed.)
Click here to see answer by solver91311(24713)  |
Question 1120384: M10 #13
Two samples are taken with the following sample means, sizes, and standard deviations
¯x1 = 39 ¯x2 = 22
n1 = 50 n2 = 46
s1 = 4 s2 = 2
Estimate the difference in population means using a 91% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth.
______< μ1−μ2 <______
Click here to see answer by Boreal(15235) |
Question 1120383: M10 #9
We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental US in Exercise 5.19. The mean and standard deviation of the reported differences are 1.1 degrees and 4.9 degrees respectively.
(a) Calculate a 90% confidence interval for the average difference between the temperature measurements between 1968 and 2008.
lower bound: ___________degrees( round to two decimal places)
upper bound: ___________ degrees( round to two decimal places)
Click here to see answer by Boreal(15235) |
Question 1120382: M10 #7
A survey of 30 people was conducted to compare their self-reported height to their actual height. The difference between reported height and actual height was calculated.
You're testing the claim that the mean difference is greater than 0.9.
From the sample, the mean difference was 0.95, with a standard deviation of 0.68.
Calculate the test statistic, rounded to two decimal places.
Click here to see answer by Boreal(15235) |
Question 1121626: For the questions below assume that females have pulse rates that are normally distributed with a mean of 74 beats per minute and a standard deviation of 12.5 beats per minute.
a. If 1 adult female is randomly selected, find the probability that her pulse is greater than 70 beats per minute.
b. If 25 adult female are randomly selected, find the probability that they have pulse rates with a mean greater than 70 beats per minute.
c. Why can the normal distribution be used in part (b) above, even though the sample size does not exceed 30?
Click here to see answer by Boreal(15235) |
Question 1121414: A construction firm bids on a contract. It anticipates a profit of $50,000 if it gets the contract for the full project, and it estimates its profit to be $20,000 on a shared project. The firm estimates there’s a 20% chance it will get the full contract and a 75% chance it will get the shared contract; otherwise, it gets nothing.
(a) Define a random variable to model the outcome of the bid for this firm.
(b) What is the expected profit earned on these contracts? Report units with your answer.
(c) What is the standard deviation of the profits?
Click here to see answer by Boreal(15235) |
Question 1121725: Heights of men on a baseball team have a bell-shaped distribution with a mean of 176 cm and a standard deviation of 8 cm. Using the empirical rule, what is the approximate percentage of the men between the following values?
a. 152 cm and 200 cm
b. 168 cm and 184 cm
______% of the men are between 152 cm and 200 cm
______% b.of the men are between 168 cm and 184 cm
Click here to see answer by Boreal(15235) |
Question 1121735: A coffee company was willing to pay $1 to each person interviewed about his or her likes and dislikes on types of coffee. Of the persons interviewed, 200 liked ground coffee, 230 liked instant coffee, 50 liked both, and 40 did not like coffee at all. What was the total amount of money the company had to pay?
Click here to see answer by Boreal(15235) |
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23941..23985, 23986..24030, 24031..24075, 24076..24120, 24121..24165, 24166..24210, 24211..24255, 24256..24300, 24301..24345, 24346..24390, 24391..24435, 24436..24480, 24481..24525, 24526..24570, 24571..24615, 24616..24660, 24661..24705, 24706..24750, 24751..24795, 24796..24840, 24841..24885, 24886..24930, 24931..24975, 24976..25020, 25021..25065, 25066..25110, 25111..25155, 25156..25200, 25201..25245, 25246..25290, 25291..25335, 25336..25380, 25381..25425, 25426..25470, 25471..25515, 25516..25560, 25561..25605, 25606..25650, 25651..25695, 25696..25740, 25741..25785, 25786..25830, 25831..25875, 25876..25920, 25921..25965, 25966..26010, 26011..26055, 26056..26100, 26101..26145, 26146..26190, 26191..26235, 26236..26280, 26281..26325, 26326..26370, 26371..26415, 26416..26460, 26461..26505, 26506..26550, 26551..26595, 26596..26640, 26641..26685, 26686..26730, 26731..26775, 26776..26820, 26821..26865, 26866..26910, 26911..26955, 26956..27000, 27001..27045, 27046..27090, 27091..27135, 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