Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1062125: The height of all the newborns in a certain country are normally distributed, with a mean of 18 inches and a standard deviation of 1 inch. A mother just delivered a baby that is 16 inches long. Which of the following represents the z-score of the babys height?( Round your answer to two decimal places.) A.0.02 B.-0.02 C.-2.00 D.2.00
Click here to see answer by rothauserc(4718)  |
Question 1061968: I would like to share with you the research question I'm after.
I am an agronomist and currently working on a research project dealing with weeds.
I'm interested in knowing
What is the probability that a weed species (wi) develops resistance to the herbicide H given that the two following events have occurred:
Event B: the weed has been reported as developing resistance to at least one herbicide in the same chemical family as that of the herbicide H.
[Note: for this purpose, based on published research on the weed resistance, I set probability of resistance to one herbicide in the family=0.08; to two herbicides in the family=0.16; three herbicides in the family = 0.24 and so on until prob=1.0]
Event C: Weed experts, based on their research experience, affirm that the weed will develop resistance to the herbicide H. About 50 experts have been given their input on how likely they think the weed is in developing resistance to the herbicide. Of course, this probability is empirical.
Based on that, I had originally written the following probability equation:
P(A|B and C)= P(A intersection B intersection C)/P(B intersection C).
However, since it is likely that the opinion of the expert on the likelihood of the weed i developing resistance to the herbicide H is influenced by what is published in the literature then I changed the equation to:
P(A|B Union C)
Since I have no theory on how B and C are related, I don't know if calculating C is even possible.There is where I'm stuck.
Click here to see answer by rothauserc(4718)  |
Question 1061939: The manufacturer of a new line of ink-jet printers would like to include as part of its advertising the number of pages a user can expect from a print cartridge. A sample of 10 cartridges revealed the following number of pages printed.
2,698 2,028 2,474 2,395 2,372 2,475 1,927 3,006 2,334 2,379
a. What is the point estimate of the population mean?
b. Develop a 95% confidence interval for the population mean.
Click here to see answer by Fombitz(32388)  |
Question 1062005: a research concludes that the number of hours of exercise per week for adults is normally distributed with a mean of 3.5 hours and a standard deviation of 3 hours
a- find the 75th percentile for the distribution of exercise time per week
b- what is the probability that a randomly selected adult has more than 5 hours of exercise per week
Click here to see answer by Fombitz(32388)  |
Question 1061040: What is the total amount of minutes that 99.7% of the fitness club members work out for?
On the average, members at a local fitness center work out for 90 minutes with a standard deviation of 15 minutes. The distribution is normal.
Click here to see answer by Fombitz(32388)  |
Question 1061989: Can somebody help me solve these problems?
a. If we are focused on 68% of the normal distribution, what percentage of the distribution is left in the upper tail only?
On the average, members at a local fitness center work out for 90 minutes with a standard deviation of 15 minutes. The distribution is normal.
b. What percentage of the fitness club members work out for 45 minutes or less?
c. What percentage of the fitness club members work out for 2 hours and 15 minutes or more?
d. 68% of the fitness club members work out between which two time intervals?
e. How many minutes did 99.7% of the fitness club members work out for?
Click here to see answer by Boreal(15235)  |
Question 1061011: 1) The probability that brown-eyes parents, both with the recessive gene for blue eyes will have a brown-eyed child is 0.75. If such parents have 6 children what is the probability that they will have
a) All blue-eyed children?
b) Exactly four children with brown eyes?
c) All children with brown eyes?
Click here to see answer by Fombitz(32388)  |
Question 1062182: Could you help me please, to solve this problem
A lottery is created with 35 numbers. You have to pick all five numbers to win the grand prize. If this lottery is an example of sampling without replecemennt, what are the odds of any one $1 ticket winning? If this a state lottery , and the hrand lrize is $250.000, do you expect the state to make money? Explain.
From above question,calculate the odds of any sibgle ticket winning if the lottery is an example if sampling with replecement.
Click here to see answer by math_helper(2461)  |
Question 1062164: You are applying for jobs at two companies. Company C offers starting salaries with μ = $39,000 and σ = $4000. Company D offers starting salaries with μ = $39,000 and σ = $1500. From which company are you more likely to get an offer of $42,000 or more? Explain your reasoning.
Click here to see answer by rothauserc(4718)  |
Question 1062196: Suppose you randomly draw a single card from a standard deck of cards.
a. what is the probability you will draw a six of diamonds?
b. what is the probability you will draw a club?
2. Suppose you randomly draw two cards from a standard deck of playing cards. What is the probability of of drawing a four of clubs and then drawing a seven of hearts?
Click here to see answer by math_helper(2461)  |
Question 1062217: Suppose you randomly draw two cards from a standard deck of playing cards. What's the probability of drawing a four of clubs, and then drawing a seven of hearts? do it with replacement and do it without replacement.
2.a bag contains 7 blue marbles, 3 green marbles, and 5 yellow marbles . Suppose you draw two marbles at random. What is the probability that you draw:
(a.) a blue, then a green marble with replacement and without replacement
(b.) two yellow marbles with replacement and without replacement?
Click here to see answer by stanbon(75887) |
Question 1062197: A bag contains 7 blue marbles, 3 green marbles and 5 yellow marbles. Suppose you draw two marbles at random. What is the probability that you draw:
a. a blue marble, then a green marble? With replacement and without replacement
B.) two yellow marbles With replacement and without replacement
Click here to see answer by stanbon(75887) |
Question 1062257: A box contains six red pens and three blue pens. (a) A pen is selected at random, the colour is noted and the pen is not returned to the box. This procedure is performed a second, then a third time.(a) Find the probability of obtaining (i) three red pens, (ii) two red pens and one blue pen, in any order, (iii) more than one blue pen.
Click here to see answer by Fombitz(32388)  |
Question 1062273: A quality control inspector is always on the lookout for substandard parts and components provided to her manufacturing company by outside suppliers. Because most shipments contain some defective items, each must be subjected to inspection. Naturally, some shipments contain more defectives than others, and it is the job of the inspector to identify the most defective-laden shipments so they can be returned to the supplier. Suppose the inspector selects a sample of 100 items from a given shipment for testing. Unbeknownst to the inspector, this particular shipment includes nine percent defective components. If the policy is to return any shipment with at least five percent defectives, what is the probability that this particular shipment (with nine percent defectives) will be accepted as good anyway
Click here to see answer by Sanakhan6(1) |
Question 1062249: A survey indicated that 78% of secondary students graduate within five years of entering grade 9. This result is considered accurate with plus/minus 3%, 19 of 20 times. Estimate the sample size of this survey.
Click here to see answer by Boreal(15235)  |
Question 1061848: A certain virus infects one in every 500 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus.
What is the probability that a person has the virus given that they have tested positive.
What is the probability that a person does not have the virus given that they have tested negative.
Click here to see answer by Boreal(15235)  |
Question 1061917: _ Nursing_majors Non-nursing_majors Total
Males 96 1013 1109
Females 700 1724 2424
Total 796 2737 3533
(a) Find the probability that the student is male or a nursing major.
P(being male or being nursing major)= __
(Round to the nearest thousandth as needed.)
(b) Find the probability that the student is female or not a nursing major.
P(being female or not being a nursing major)=__
(Round to the nearest thousandth as needed.)
(c) Find the probability that the student is not female or a nursing major.
P(not being female or being a nursing major)=__
(Round to the nearest thousandth as needed.)
(d) Are the events "being male" and "being a nursing major" mutually exclusive? Explain.
A.
No, because one can't be male and a nursing major at the same time.
B.
Yes, because one can't be male and a nursing major at the same time.
C.
No, because there are 96 males majoring in nursing.
D.
Yes, because there are 96 males majoring in nursing.
Click here to see answer by Boreal(15235)  |
Question 1061917: _ Nursing_majors Non-nursing_majors Total
Males 96 1013 1109
Females 700 1724 2424
Total 796 2737 3533
(a) Find the probability that the student is male or a nursing major.
P(being male or being nursing major)= __
(Round to the nearest thousandth as needed.)
(b) Find the probability that the student is female or not a nursing major.
P(being female or not being a nursing major)=__
(Round to the nearest thousandth as needed.)
(c) Find the probability that the student is not female or a nursing major.
P(not being female or being a nursing major)=__
(Round to the nearest thousandth as needed.)
(d) Are the events "being male" and "being a nursing major" mutually exclusive? Explain.
A.
No, because one can't be male and a nursing major at the same time.
B.
Yes, because one can't be male and a nursing major at the same time.
C.
No, because there are 96 males majoring in nursing.
D.
Yes, because there are 96 males majoring in nursing.
Click here to see answer by MathTherapy(10551)  |
Question 1061776: According to a 2010 Business Week article, the average 401(k) account balance for individuals nearing
retirement was $60,000. To test if this average has recently changed, suppose a sample of 30 people
starting retirement was selected and it found that the average 401(k) balance was $67,000. Assume the
population standard deviation was $21,000. Using an α = .05, answer the following:
a. State the null and alternative hypotheses.
b. What conclusions can be made about the current average balance of 401(k) accounts for
people nearing retirement?
c. Determine the p-value for this test and interpret its meaning.
d. Repeat the preceding hypothesis test using the critical value approach.
Click here to see answer by Boreal(15235)  |
Question 1061636: The estimate of the population proportion is to be within plus or minus 0.06, with a 95% level of confidence. The best estimate of the population proportion is 0.17. How large a sample is required? (Use z Distribution Table.) (Round the z-values to 2 decimal places. Round up your answer to the next whole number.)
Click here to see answer by Boreal(15235)  |
Question 1061642: ARE MY ANSWER CORRECT?
A certain virus infects one in every 600 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. Let A be the event "the person is infected" and B be the event "the person tests positive."
(a) Find the probability that a person has the virus given that they have tested positive.
0.1013
(b) Find the probability that a person does not have the virus given that they have tested negative.
-53.82
Click here to see answer by Boreal(15235)  |
Question 1061750: Generation Y has been defined as those individuals who were born between 1981 and
1991. According to the Project on Student Debt, Generation Y students graduating from
college averaged $23,200 in debt in 2009. Assume the standard deviation for debt is
$7,500 per student. A random sample of 30 service stations were selected.
a. Calculate the standard error of the mean.
b. What is the probability that the sample mean will be less than $24,000.
c. What is the probability that the sample mean will be more than $21,725.
d. What is the probability that the sample mean will be between $21,000 and $26,000?
Click here to see answer by Boreal(15235)  |
Question 1061625: IQs are calibrated so that they have a mean of 100 and a standard deviation of 15.
a) Find the probability that a randomly selected person has an IQ between 106 and 116. Be sure to draw a sketch.
b) A person with an IQ at or below the 5th percentile is considered “developmentally disabled”. What IQ corresponds to the cutoff for this designation?
Click here to see answer by Theo(13342)  |
Question 1061673: A population consists of the following five values: 9, 11, 14, 15, and 19.
a.
List all samples of size 3, and compute the mean of each sample. (Round your mean value to 2 decimal places.)
Sample Values Sum Mean
1 (Click to select)9, 11, 149, 14, 159, 14, 199, 15, 19
2 (Click to select)9, 11, 159, 11, 149, 11, 199, 14, 15
3 (Click to select)9, 11, 199, 11, 149, 11, 159, 14, 15
4 (Click to select)9, 14, 1511, 14, 159, 11, 1511, 15, 19
5 (Click to select)9, 14, 199, 11, 149, 11, 159, 11, 19
6 (Click to select)9, 15, 199, 11, 149, 11, 159, 11, 19
7 (Click to select)11, 14, 159, 11, 1411, 9, 159, 11, 19
8 (Click to select)11, 14, 1911, 14, 1511, 14, 911, 9, 14
9 (Click to select)11, 15, 1911, 15, 1411, 9, 1511, 9, 14
10 (Click to select)14, 15, 1914, 15, 914, 15, 1114, 9, 15
b.
Compute the mean of the distribution of sample means and the population mean. (Round your answers to 2 decimal places.)
Sample means
Population mean
Click here to see answer by ikleyn(52777)  |
Question 1062482: Some psychologists believe that a genius should be defined as anyone having an IQ over 140. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 17 and if the population of the world is 6,575,000,000, how may geniuses are there in the world today? A.24,985,000 B.61,805,000 C.123,000 D.115,000 D.6,575,000
Click here to see answer by Boreal(15235)  |
Question 1062407: A shipment of 8 similar computers to a retail outlet contains 3 that are defective. A school makes a random purchase of 2 of these computers. Let X denotes the number of defective in the sample.
Find the probability distribution of the number of defective.
Click here to see answer by addingup(3677)  |
Question 1062668: The following sample observations were randomly selected. (Round your answers to 2 decimal places.)
X:
4
5
3
6
10
Y:
8.8
13.6
6
15.4
18.6
a. The regression equation is Y^ = ___+____ X
b. When X is 7.5 this gives Y^ =
Click here to see answer by Fombitz(32388)  |
Question 1062667: Two Population Means
A tomato farmer with a very large farm of approximately 2200 acres had heard about a new type of rather expensive fertilizer which would supposedly significantly increase his production. The frugal farmer wanted to test the new fertilizer before committing the large investment required to fertilize a farm of his size. He therefore selected 15 parcels of land on his property and divided them each into two portions. He bought just enough of the new fertilizer to spread over one half of each parcel and then spread the old fertilizer over the other half of each parcel. His yields in pounds per tomato plant were as follows:
Parcel New Fertilizer Old Fertilizer
1 14.2 14.0
2 14.1 13.9
3 14.5 14.4
4 15.0 14.8
5 13.9 13.6
6 14.5 14.1
7 14.7 14.0
8 13.7 13.7
9 14.0 13.3
10 13.8 13.7
11 14.2 14.1
12 15.4 14.9
13 13.2 12.8
14 13.8 13.8
15 14.3 14.0
The farmer had taken statistics many years ago when in college and consequently made a couple of mistakes when testing to find if the new fertilizer was more effective: (1) He tested the data as two independent samples, and (2) He performed a two-tailed test. He decided that he was unable to conclude that there was a difference between the two fertilizers.
What if you were the fertilizer sales representative and your job was to prove the superiority of the new product to the farmer?
(1) You should start by running the same test he did in which he came to the decision that he could not conclude a difference.
(2) Perform the test as it should have been done and find if you come to a different conclusion.
(3) Explain why the results were different and why your test was a stronger and more reliable test.
Click here to see answer by Boreal(15235)  |
Question 1062680: Can you please help me solve this question and explain how to solve it shortly?
y=3x-5 E(x)=4 Var(x)=2 are given.
E(4)=? Var(4)=?
[y=3x-5 E(x)=4 Var(x)=2 are given. E(4)=? Var(4)=? This is all that is given in the homework. I couldn't figure out the question too. Didn't see this kind of question before. There is a function y=3x-5 with x and y variables. Expected value E(x)=4 is given and Variation Var(x)=2. What is asked is Expected value at 4, E(x) and Variation at 4, Var(x).]
Click here to see answer by Alan3354(69443)  |
Question 1062680: Can you please help me solve this question and explain how to solve it shortly?
y=3x-5 E(x)=4 Var(x)=2 are given.
E(4)=? Var(4)=?
[y=3x-5 E(x)=4 Var(x)=2 are given. E(4)=? Var(4)=? This is all that is given in the homework. I couldn't figure out the question too. Didn't see this kind of question before. There is a function y=3x-5 with x and y variables. Expected value E(x)=4 is given and Variation Var(x)=2. What is asked is Expected value at 4, E(x) and Variation at 4, Var(x).]
Click here to see answer by Caner1994(1) |
Question 1062780: Suppose there are eight different books on algebra, four different books on discrete mathematics, and five different books on history.
(a) In how many ways can these books be arranged on a shelf?
I came up with multiple answers
answer 1= total number of book is 17 then answer = 17!
answer 2= 8!*4!*5!
answer 3= 8*4*5
answer 4= P(17,8)*P(9,4)*5!
i don't know if any of them is correct or all of them are wrong
Click here to see answer by Alan3354(69443)  |
Question 1062655: Consider the following events for a family with children:
A = {children of both sexes}, B = {at most one boy}.
(i) Show that A and B are independent events if a family has three children.
(ii) Show that A and B are dependent events if a family has only two children.
Click here to see answer by Boreal(15235)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 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11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 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17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 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