Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1047106: Statistics show that only 40% of South African women are overweight. Consider a randomly selected group of twenty South African women. Calculate the probability that three are overweight and none are overweight
Click here to see answer by stanbon(75887)  |
Question 1046864: 53% of the students on campus are men, 30% of the students are majoring in business, and 11% of the students on campus are men and are majoring in business. What is the probability that if you randomly select a student on campus, this is student is male OR majoring in business?
Click here to see answer by ewatrrr(24785)  |
Question 1047072: A biased tetrahedral die with faces labelled 1,2,3 and 4 is rolled once. The chance of getting a '3' is twice that of getting a '1' . The chance of getting a '2' is thrice that of getting a '3' . There is an equal chance of getting a'2' and a '4' . Find the probability of getting a prime number.
Click here to see answer by ewatrrr(24785) |
Question 1047073: A biased tetrahedral die with faces labelled 1,2,3 and 4 is rolled once. The chance of getting a '3' is twice that of getting a '1' . The chance of getting a '2' is thrice that of getting a '3' . There is an equal chance of getting a'2' and a '4' . Find the probability of getting a prime number.
Click here to see answer by ewatrrr(24785) |
Question 1047119: In the parking lot there are 76 cars that are 2 years old, 68 cars that are 3 years old, 89 cars that are 4 years old and 98 cars that are 5 years old. What is the mean age of the cars. Type your answer as a decimal rounded to the nearest hundrdth.
I would simply love to know how to find the answer.
Click here to see answer by ewatrrr(24785) |
Question 1047078: 1. Customers are asked to take a survey. Out of a random sample of 340 customers, 290 said their experience was “satisfactory.” Let p represent the proportion of all customers who would say their experience was “satisfactory.”
a. What is the point estimate for p?
b. Construct a 99% confidence interval for p.
c. Give a brief interpretation of this interval.
Click here to see answer by ewatrrr(24785) |
Question 1047107: Ten candidates apply for a job and are separately interviewed. Based on past experience, any candidate has a 65% chance of passing to a second interview. What is the probability that: [17]
At least eight candidates pass to a second interview
More than two but less than six candidates pass to a second interview
At most three candidates do not pass to a second interview
If 540 candidates applied for the job and were interviewed, what is the variance and the expected number of candidates that will pass to a second interview?
Click here to see answer by Timnewman(323)  |
Question 1047126: Can someone please check to see if this is done correctly?
1. A random sample of size 64 has sample mean 24 and sample standard deviation 4.
a. Is it appropriate to use the t distribution to compute a confidence interval for the population mean? Why or why not? No, because our sample size is more than 30.
b. Construct a 95% confidence interval for the population mean.
22.1 < µ < 25.9
2. You are trying to estimate the average miles per gallon for a new brand of car. A random sample of 40 cars, and, for this sample, the average miles per gallon is 32 and the standard deviation is 2.2.
a. Suppose you would like to construct a 90 percent confidence interval. What would be the margin of error for this interval?
1.645(2.2 / √40) ≈ 0.57
b.What would be the lower and upper limits for this 90 percent confidence interval?
31.43 < µ < 32.57
Click here to see answer by stanbon(75887) |
Question 1047124: A random sample has 42 values. The sample mean is 9.5 and the sample standard deviation is 1.5. Use a level of significance of 0.02 to conduct a left-tailed test of the claim that the population mean is 10.0.
a. Are the requirements met to run a test like this?
b. What are the hypotheses for this test?
c. Compute the test statistic and the p-value for this test.
d. What is your conclusion at the 0.02 level of significance?
Click here to see answer by ewatrrr(24785) |
Question 1047218: Please help on this probability question. I got 1/16 as an answer by multiplying (1/2)*(1/2)*(1/2)*(1/2) = 1/16 I am not sure if I am right.
A couple decides to have 4 children. If they succeed in having4 children and each child is equally likely to be a boy or a girl, what is the probability that they will have exactly 2 girls and 2 boys?
Click here to see answer by KMST(5328)  |
Question 1047244: Please help me solve for an inequality problem. Thirty-five more than the weight limit, w, in an elevator is greater than 1,050 pounds. A. asks me to model I have 35 + w > 1,050. B. says solve inequality. I would like to know if I am attempting this correctly.
Thank you,
JW
rush.carlene@yahoo.com
Click here to see answer by KMST(5328) |
Question 1047237: Hi Can someone please check my work? I am having trouble understanding confidence intervals and I am not sure if I am on the right track.
4. How much do adult male lions weigh? Six adult males were captured, tagged and here are their weights:
480, 580, 470, 510, 390, 550
a. What is the point estimate for the population mean? 2980/6 ----> µ = 496.7
b. Construct at 90% confidence interval for the population average weight of all adult male grizzly bears in the wild.
S x-bar = 27.2709
Df 6-1=5
t=2.0150
= x-bar ± (t * Standard error)
Click here to see answer by ewatrrr(24785) |
Question 1047248: True or False. Suppose the minimum for a data set is 12. A careless assistant records it as 1.2, which is the only mistake in the record keeping. The mistake will change the mean as well as the median of the data set.
I feel this is true since the number is way off from what it is supposed to be.
Click here to see answer by ewatrrr(24785) |
Question 1047173: Please assist me in solving the following question? I do not know where to begin in solving this equation. Thank you for assisting.
Listed below is the number of movie tickets sold at the Library Cinema-Complex, in thousands, for the period from 2001 to 2013. Compute a five-year weighted moving average using weights of 0.2, 0.15, 0.25, 0.12, and 0.28, respectively. Describe the trend in yield. (Round your answers to 3 decimal places.)
2001 8.71
2002 8.24
2003 7.57
2004 6.69
2005 7.37
2006 6.88
2007 6.81
2008 6.41
2009 5.38
2010 5.67
2011 5.84
2012 5.59
2013 5.33
The weighted moving averages are:
Click here to see answer by Theo(13342)  |
Question 1047225: Widgets coming off an assembly line have a 10% defective rate. Five widgets are selected at random and tested.
1.What is the probability that all five of them are defective?
2. What is the probability that the first two are defective and the other three are not?
3. What is the probability that the second and fifth ones are defective and the other three are not?
4. How many different outcomes result in exactly two of the five being defective?
5. What is the probability that exactly two of the five are defective?
Click here to see answer by Boreal(15235)  |
Question 1047222: A certain brand of tyre manufactured by Run Wild Inc. has a lifetime that is normally distributed with a mean of 81,200 miles and a standard deviation of 4,300 miles. For how many miles should they warranty their tyres if they want 95% of them to last longer than the warranty?
Click here to see answer by Boreal(15235) |
Question 1047389: 10. Suppose that a certain brand of light bulbs has a mean life of 600 hours and a standard deviation of 53 hours.
According to the Empirical Rule, 99.7% of light bulbs have a lifetimes between ________ and ___________.
11. Using information from #10, what percentage of light bulbs will last between 547 and 706 hours?
Click here to see answer by ewatrrr(24785) |
Question 1047380: How would I know if the assumptions for this test have been met?
A new brand of car gets 35 miles per gallon on average. Suppose a consumer group claims that these cars get less than 35 miles per gallon. A sample of 40 cars is selected, and the sample mean for the 40 cars is 33 miles per gallon while the sample standard deviation is 3.8
Click here to see answer by ewatrrr(24785) |
Question 1047426: When plotted on the same graph, a distribution with a mean of 60 and a standard deviation of 5 will look more spread out than a distribution with a mean of 40 and standard deviation of 8.
I believe the distribution with a mean of 40 will look more spread out since the standard deviation is a larger number than the first distribution.
Click here to see answer by ewatrrr(24785) |
Question 1047436: A statistics instructor is interested in the average weekly study time for his students. He teaches two sections in Spring and randomly chooses 15 students from the first section and 18 students from the second section. This sampling method is called
cluster
convenience
stratified or
systematic
I feel the answer is convenience since it is using students that are readily available. Stratified uses a proportionate number of students, systematic uses an nth piece of data, although I feel it could also be cluster. Please help clarify!
Click here to see answer by ewatrrr(24785) |
Question 1047438: Mimi is doing a research about driving time. She plans on collecting information from her classmates. This sampling method is called...
systematic
stratified
convenience
cluster
I feel this is an example of convenience since Mimi is using her classmates as sampling rather than using a random method. Could you please offer some insight and clarification to be sure I'm on the right track? Thank you!
Click here to see answer by ewatrrr(24785) |
Question 1047496: To qualify for a mortgage, an applicant needs to have a good FICO credit score. We chose a random sample of 5 applicants from a local bank, and their FICO scores are 760, 700, 820, 580 and 620.
What is the standard deviation of the FICO scores in the sample? S
FICO Scorex x^2 x-mean (x-mean)2
760
700
820
580
620
I really appreciate any help that can be offered. Thank you!
Click here to see answer by stanbon(75887) |
Question 1047439: Identify the scale of measurement for the following military hierarchy: Lieutenant, Captain, Major
a. Interval
b. Nominal
c. Ratio
d. Ordinal
I feel that ordinal is the correct answer since ordinal data can be ranked. Could you please clarify for me if I am incorrect in my thinking? Thank you!
Click here to see answer by robertb(5830)  |
Question 1047448: An instructor is interested in the average weekly study time for his students. He teaches two sections in Spring and randomly chooses 15 students from the first section and 18 students from the second section. This sampling method is called
cluster
convenience
stratified
systematic
I'm leaning towards this being a cluster because the other methods don't seem to fit in. Any clarification on this would be greatly appreciated! Thank you!
Click here to see answer by robertb(5830) |
Question 1047447: To qualify for a mortgage, an applicant needs to have a good FICO credit score. We chose a random sample of 5 applicants from a local bank, and their FICO scores are 760, 700, 820, 580 and 620.
What is the standard deviation of the FICO scores in the sample? Please show your intermediate calculation
FICO Score x x^2 x-mean (x-mean)^2
760
700
820
580
620
I'm a little lost on this any help would be greatly appreciated, thank you!
Click here to see answer by ewatrrr(24785) |
Question 1047567: Suppose that HIV test gives a positive result with probability 96% when the patient is indeed affected by HIV, while it gives a negative result with 97% probability when the patient is not affected by HIV. If a patient is drawn at random from a population in which 12% of individuals are affected by HIV and s/he is found negative, what is the probability that s/he is indeed not affected by HIV?
Click here to see answer by Boreal(15235) |
Question 1047561: Can someone check my answers to these questions to tell me if I did the correctly. If not, please show me how.
Answer questions 1-5 based on the probability distribution table below:
x 0 1 2 3
p(x) .1 .2 .3 .4
1. List the values that x may assume.
{(0, 0.1, 0.2, 0.3, 0.4, 0.2, 0.4, 0.6, 0.8, 0.3, 0.6, 0.9, 1.2)}
2. What value of x will occur most often?
0.2, 0.3, 0.4, 0.6
3. What is the probability that x will be greater than zero?
.3 + .4 = .7
.7/2 = .35
4. Calculate the expected value for the data set.
EX = 0 * .1 + 1 * .2 + 2 * .3 + 3 * .4
0 * 1 = 0
0 + 1 * .2 = 0.2
0.2 + 2 *.3 = 0.8
0.8 + 3 *.4 = 2
The expected value for the data set is 2.
5. Calculate the variance for the data set.
V = (X - E(X))^2
V = (0 - 2)^2 * .1 + (1 - 2)^2 * .2 + (2 - 2)^2 * .3 + (3 - 2)^2 * .4
V = (-2)^2 * (.1) + (-1)^2 * (.2) + (0)^2 * (.3) + (1)^2 * (.4)
V = (4) * (.1) + (1) * (.2) + (0) * (.3) + (1) * (.4)
V = 0.4 + 0.2 + 0 + 0.4
V = 1
A discrete random variable x can assume five possible values: 5, 10, 15, 20, and 25. Answer questions 4-8 based on the probability distribution shown here:
x 5 10 15 20 25
p(x) .15 .10 ? .25 .25
6. What is the probability that x = 15?
.15 + .10 + .25 + .25 = 0.75
0.75/5
0.15
7. What is the probability of x ≥20?
.25 + .25 = .5
8. If we constructed a histogram would the data be skewed or symmetric?
If we constructed a histogram, the data be skewed.
9. Calculate the expected value (mean) given the probability distribution above.
EV = 5 * .15 + 10 * .10 + 15 *.15 + 20 * .25 + 25 * .25
EV = .75 + 1 + 2.25 + 5 + 6.25
EV = 15.25
10. Calculate the variance given the probability distribution above.
v =5 * .15 + 10 * .10 + 15 * .15 + 20 * .25 + 25 * .25
v = (5 - 15.25)^2 * .15 + (10 – 15.25)^2* .10 + (15 – 15.25 * .15 + (20 – 15.25 * .25 + (25 – 15.25)^2 * .25
v = (-10.25)^2 *.15 + (-5.25)^2* .10 + (-.25)^2 * .15 + (4.75)^2 * .25 + (9.75)^2 * .25
v = 105.0625 *.15 + 27.5625 * .10 + 0.0625 * .15 + 22.5625 * .25 + 95.0625 * .25
v = 15.759375 + 2.75625 + 0.009375 + 5.640625 + 23.765625
v = 18.515625 + 0.009375 + 29.40625
v = 18.525 + 29.40625
v = 47.93125
v = 47.93
Click here to see answer by Boreal(15235) |
Question 1047554: "A doctor assumes that a patient has one of three diseases d1, d2, or d3. Before any test, he assumes an equal probability for each disease. He carries out a test that will be positive with probability 0.8 if the patient has d1, 0.6 if he has d2, and 0.4 if he has d3. Given that the outcome of the test was positive, what probabilities should the doctor now assign to the three possible diseases?"
My try on the question: I assumed that an equal probability meant 1/3. There are three diseases, so if the patient has one disease, the others are excluded: does this mean there is another factor in the calculation?
Otherwise, I concluded that 0.8*(1/3) for d1, 0.6*(1/3) for d2, and 0.4*(1/3) for d3.
But it seems to be too easy among the questions I have been solving.
Thank you in advance.
Click here to see answer by ewatrrr(24785) |
Question 1047544: In a sample of 2016 U.S. adults, 242 said Richard Nixon was the worst president since World War II. Three U.S. adults are selected at random without replacement.
(a) Find the probability that all three adults say Richard Nixon was the worst president since World War II.
(b) Find the probability that none of the three adults say Richard Nixon was the worst president since World War II.
(c) Find the probability that at most two of the three adults say Richard Nixon was the worst president since World War II.
(d) Which of the events can be considered unusual? Explain.
Click here to see answer by ewatrrr(24785) |
Question 1047566: Research has shown that, for a certain company, 7% of plant A products are defective, 92% of plant B products are non-defective, 10% of plant C products are defective, and 95% of plant D products are non-defective. Of all the products manufactured by this company, 15% come from plant A, 25% from plant B, and 48% from plant C. An inspector has just randomly selected one product from the warehouse of this company.
(a) What is the probability that it is defective? [10]
(b) If it is defective, what is the probability that it came from plant B? [5]
(c) If it is non-defective, what is the probability that it came from plant D? [10]
Click here to see answer by Boreal(15235) |
Question 1047566: Research has shown that, for a certain company, 7% of plant A products are defective, 92% of plant B products are non-defective, 10% of plant C products are defective, and 95% of plant D products are non-defective. Of all the products manufactured by this company, 15% come from plant A, 25% from plant B, and 48% from plant C. An inspector has just randomly selected one product from the warehouse of this company.
(a) What is the probability that it is defective? [10]
(b) If it is defective, what is the probability that it came from plant B? [5]
(c) If it is non-defective, what is the probability that it came from plant D? [10]
Click here to see answer by ewatrrr(24785) |
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7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 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