Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1030443: Ineed ur help with the following problem:
We have created a 90% confidence interval for µ with the result (9, 14). What
conclusion will we make if we test H0 : µ = 19 verses Ha : µ 6= 19 at α = 0.10?
alpha = 0.1
alpha/2 = 0.05 there fore 1.645 or -1.645 and 9,14 falls in the rejection region there for Reject the Null hypothesis
Click here to see answer by stanbon(75887)  |
Question 1030448: I need your help with the following problem :
Sales of a new line of athletic footwear are crucial to the success of a company. The company wishes to estimate the average weekly sales of the new footwear to within $300 with 99% reliability. The initial sales indicate that the standard deviation of the weekly sales figures is approximately $1100. How many weeks of data must be sampled for the company to get the information it desires?
Margin of error: 2.575 x 1100/Square root of n < 300
(2.575 x 1100/300) ^2 = 89.14
therefore n has to be either bigger or equal to 89.14
Click here to see answer by Boreal(15235)  |
Question 1030508: An organization is trying to determine the mean IQ of professional pilots. How large a sample is required if they want to be 98% confident that the sample mean is within 4 IQ pts. of the population mean. Suppose you can assume that the standard deviation of pilot IQs is the same as the standard deviation of IQs for all adults, which is 15.
Click here to see answer by stanbon(75887) |
Question 1030528: After finding a correlation between birth-weight (the dependent variable) and gestational age ( the independent variable). How birth-weight depends on gestational age. Which test should you use?
a) One-Way ANOVA
b) Pearson Correlation
c) Spearman Correlation
d) Kruskal-Wallis
e) Simple Linear Regression
f) Multiple Logistic Regression
Click here to see answer by Boreal(15235) |
Question 1030568: how do i work out this problem and may i ask for a step by step process
Mario has 3 brown socks and 5 white socks
in his sock drawer. What is the least
number of socks he should take out of his
drawer without looking if he wants to get
at least one matched pair?
Click here to see answer by Theo(13342)  |
Question 1030568: how do i work out this problem and may i ask for a step by step process
Mario has 3 brown socks and 5 white socks
in his sock drawer. What is the least
number of socks he should take out of his
drawer without looking if he wants to get
at least one matched pair?
Click here to see answer by josmiceli(19441)  |
Question 1030575: There are 20 students in a class. Six of them have blue eyes and nine have brown eyes. You were asked to choose 2 students without replacement. What is the probability of choosing an student with blue eyes followed by a student with brown eyes?
Click here to see answer by stanbon(75887) |
Question 1030586: The singular form of the word “dice” is “die”. Tom was throwing a six-sided die. The first time he threw, he got a three; the second time he threw, he got a three again. What’s the probability of getting a three at the third time?
Click here to see answer by rothauserc(4718)  |
Question 1030627: We would like to perform a two-tailed hypothesis test about mean at significance level of 0.05. The test statistic is already calculated for us, and the value is 2.1. We know that there are 25 observations in the random sample. The population is normally distributed, but the population standard deviation is unknown. What is the P-value? Do we have sufficient evidence to reject the null hypothesis? Why? Please show work.
Click here to see answer by rothauserc(4718) |
Question 1030830: Suppose a student is taking a 5-response multiple choice exam; that is, the choices are A, B, C, D, and E, with only one of the responses correct. Describe the complement method for determining the probability of getting at least one of the questions correct on the 15-question exam . Why would the complement method be the method of choice for this problem?
Click here to see answer by richard1234(7193)  |
Question 1030955: An art gallery has a total of 11 paintings by a particular artist; of these, 5 are oil paintings and 6 are water colour paintings. The art gallery is asked to provide a special exhibition of this artist’s work but is restricted to showing only five of the paintings. Calculate the number ways in which the five paintings can be selected for the exhibition if :
a.there are no restrictions
b.one particular painting must be included
c.there must be exactly three watercolour paintings
d.there must be more watercolour paintings than oil paintings
Click here to see answer by stanbon(75887) |
Question 1030964: The depot is using a standard of 650 hours for a particular modification effort. You are to review the standard and determine whether it should be revised. After sampling 20 of these modifications you calculate a mean of 665 hours and a standard deviation of 45 hours. We are concerned that the hours might be higher or lower than the 650 hour standard. Test the standard at the .05 level of significance. Select the correct answer out of each pair of choices. (Carry intermediate calculations to three decimal places.)
The tp is 2.093
The tp is 1.729
The tc is 1.491
The tc is 2.981
We would fail to reject the null hypothesis
We would reject the null hypothesis
We would recommend using the existing standard.
We would recommend revising the standard.
Click here to see answer by rothauserc(4718) |
Question 1030969: the age of a machine X in years is, is related to the probability of breakdown, y by the formula x=3+Ln(y/1-y)
Determine the probability of a breakdown for 1 3 and 10 years.
x = 3 + l n ( y 1 − y )
x=3+ln(y1−y)
3 + l n ( y 1 − y )
= 1 3+ln(y1−y)
=1 3 + l n ( y 1 − y )
= 3 3+ln(y1−y)=3
3 + l n ( y 1 − y ) = 10
I'm lost, lost lost!
Click here to see answer by Alan3354(69443)  |
Question 1030980: The average attrition rate of a customer based company is 20% with a standard deviation of 7% (based on the past data). To test this a sample of 100 was taken and 23% average attrition rate was found. What can be concluded from about the attrition rate at 10% significance level?
The attrition rate is 23% now
The attrition rate is more than 20% now
The attrition rate is same as 20%
The attrition rate is less than 20% now
I tried this and got the below answer.Can you please check if this is correct.
H0-No diff in attrition rate
H1:Increase in attrinium rate
x>=23=1-(x<=23)
==1-NORM.DIST(23,20,7/(100)^0.5,TRUE)
=9.10765E-06 <0.1
reject null hypothesis
Is option (a) the correct answer that the attrition rate is 23% now.
Thanks
Click here to see answer by ewatrrr(24785)  |
Question 1030892: The probability that a person owns an iPhone is 0.68, that a person owns an iPad is 0.32,
and that a person owns both an iPhone and an iPad is 0.14. Find the probability that a person owns
either an iPhone or an iPad, but not both
Click here to see answer by ewatrrr(24785) |
Question 1031087: I've had a go at this sequence of questions and come up with some answers, the thing is, I'm not sure that it's correct, please have a look and advise me if you have the time.
Problem(s);
i Determine the remainder when 9 x^5-4 x^4 is divided by 3 x-1
ii Show using the factor theorem the 2x -1 is a factor of 2x^4- x3 -6x^2 + 5x -1 and hence express
2x^4- x3 -6x^2 + 5x -1 as a product of a linear and cubic factor.
this is my go at the first bit:
9 x^5-4 x^4 = (3 x^4-x^3/3-x^2/9-x/27-1/81) × (3 x-1)+-1/81
Click here to see answer by josgarithmetic(39613) |
Question 1030691:
Suppose we want to be able to predict final exam grades using students' grades from Exam #1 from the beginning of the semester. See the table below.
We obtain the following regression equation: y=0.1309+74.3538x
The slope, β, can be interpreted as which of the following?
1) For every 1 point increase in the final exam grade, Exam #1 grade will increase by 74.3538 points.
2) For every 1 point increase in Exam #1 grade, the final exam grade will increase by 74.3538 points.
3) For every 1 point increase in Exam #1 grade, the final exam grade will increase by 0.1309 points.
4) For every 1 point increase in the final exam grade, Exam #1 grade will increase by 0.1309 points.
Click here to see answer by robertb(5830)  |
Question 1030692: Which of the following correctly describes the null and alternative hypotheses for an analysis of variance between three treatment groups (µ1 µ2 µ3)?
3) Ho: µ1 = µ2 = µ3, Ha: At least 2 means differ
4) Ho: µ1 = µ2 = µ3, Ha: All means differ
Click here to see answer by robertb(5830) |
Question 1031090: According to the data published by the U.S. Dept. of Agriculture, the average annual amount of chicken eaten by American adults (excluding vegetarians) is normally distributed with a mean of 55 pounds and a standard deviation of 9.2 pounds.
Suppose a trade organization randomly samples 50 American adults (excluding vegetarians) and records the annual chicken consumption of each. What is the probability that the sample mean is less than 52 pounds per year?
A.51
B.49
C.37
D.10
E.01
Click here to see answer by rothauserc(4718) |
Question 1031114: Out of 2000 students who attend a certain high school, 1400 students own cell phones, 1000 own a tablet, and 800 have both. Suppose a student is randomly selected. Create a Venn diagram model. I already tried it but I can't figure this out because the addend of the three numbers is more than 2000 and my teacher didn't explain it thoroughly. Please help me, thank you.
Click here to see answer by stanbon(75887) |
Question 1031114: Out of 2000 students who attend a certain high school, 1400 students own cell phones, 1000 own a tablet, and 800 have both. Suppose a student is randomly selected. Create a Venn diagram model. I already tried it but I can't figure this out because the addend of the three numbers is more than 2000 and my teacher didn't explain it thoroughly. Please help me, thank you.
Click here to see answer by ikleyn(52752)  |
Question 1031214: Please find the solution for this question:
*Shabeen has a biased coin. the probability that the coin will land on heads is 0.6.
Shabeen is going to throw the coin 3 TIMES.
She says the probability that the coin will land on tails 3 times is less than 0.1
Is Shabeen correct? You must show all your working.
Click here to see answer by Boreal(15235) |
Question 1031204: The statistical report shows that the average amount of time spent by each customer per week on online shopping is 1 hour 20 minutes with a variance of 1225 minutes. Assume that the data are normally distributed.
b. Calculate the probability that 9 randomly chosen customers will have a mean amount of time spend on on-line shopping between 35 minutes and 65 minutes in the second week of December.
The answer is 0.0992, but I'm not sure how to solve it. The 9 randomly chosen part is stumping me.
EDIT: I've already tried using NormalCD for probability of spending between 35 and 65 minutes online which is 0.2348. Am I supposed to use Binomial and Normal Distribution to solve the problem?
Click here to see answer by stanbon(75887) |
Question 1031227: At a fast Food restaurant, the expected number of customers who will spend at least $10 during the lunchtime period from 12:00 noon to 2:00 P.M is 221 and the variance is 33.15. Assume this is a binomial model. Determine the number of customers will be in this fast food restaurant on this Friday during the lunch time period from 12:00 noon to 2:00P.M.
I am completely lost here, is there enough info to solve the problem?
Click here to see answer by jim_thompson5910(35256) |
Question 1030764: In a class of 125 students, 1/5 th like only biology,2/5th like biology as well as maths.1/5th like physics as well as maths. and remaining like all the three subjects.total how many students in the class like biology?
Click here to see answer by LinnW(1048)  |
Question 1031436: It is given that population mean is 200 with a standard deviation of 40. A sample of size 50 is taken with mean 60 then what is the probability of observing a mean value of upto 60(assume that the underlying population is not normal).
Norm.dist(60,200,40/sqrt(50), true)
1-Norm.dist(60,200,40,true)
Norm.dist(60,200,40,true)
None of these
I think the answer is (C). IS that correct?
Click here to see answer by ewatrrr(24785) |
Question 1031434: The average commission charged by a brokerage companies on a sale is $186. However it is seen in the random sample of 133 trades that the average amount of commission paid is $179 with a standard deviation of $61. At 10% significance level can we conclude that the average commission is lower than the industry average?
The average commission is not same as $186
The average commission is same $186
The average commission is lower than $186
The average commission is now $179
Am I correct in assuming that this is an example of T distribution as population standard deviation is not given. Or do we have to you normal distribution.
Thanks.
Click here to see answer by Boreal(15235) |
Question 1031283: The cumulative distribution function of the random variable X is given by:
Find the probability density function for the random variable X.
compute p(X≤ 5) and p( 8< X )
Find the expected value for the random variable X.
Click here to see answer by Fombitz(32388)  |
Question 1031500: The mean starting salary for nurses is $67,694 nationally ("Staff nurse -," 2013).
The standard deviation is approximately $10,333. Assume that the starting salary
is normally distributed.
e.) If a nurse made less than $50,000, would you think the nurse was under paid?
Why or why not?
f.) What salary do 30% of all nurses make more than?
(if you can provide explanation too it would be great)
Click here to see answer by stanbon(75887) |
Question 1031505: A box has 10marbles in it, 7red and 3white. Suppose we draw a marble from the box, replace it, and then draw another. Find the probability that:
(a) Both marbles are red.
(b) Just one of the two marbles is red.
Click here to see answer by stanbon(75887) |
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7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560, 16561..16605, 16606..16650, 16651..16695, 16696..16740, 16741..16785, 16786..16830, 16831..16875, 16876..16920, 16921..16965, 16966..17010, 17011..17055, 17056..17100, 17101..17145, 17146..17190, 17191..17235, 17236..17280, 17281..17325, 17326..17370, 17371..17415, 17416..17460, 17461..17505, 17506..17550, 17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 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23941..23985, 23986..24030, 24031..24075, 24076..24120, 24121..24165, 24166..24210, 24211..24255, 24256..24300, 24301..24345, 24346..24390, 24391..24435, 24436..24480, 24481..24525, 24526..24570, 24571..24615, 24616..24660, 24661..24705, 24706..24750, 24751..24795, 24796..24840, 24841..24885, 24886..24930, 24931..24975, 24976..25020, 25021..25065, 25066..25110, 25111..25155, 25156..25200, 25201..25245, 25246..25290, 25291..25335, 25336..25380, 25381..25425, 25426..25470, 25471..25515, 25516..25560, 25561..25605, 25606..25650, 25651..25695, 25696..25740, 25741..25785, 25786..25830, 25831..25875, 25876..25920, 25921..25965, 25966..26010, 26011..26055, 26056..26100, 26101..26145, 26146..26190, 26191..26235, 26236..26280, 26281..26325, 26326..26370, 26371..26415, 26416..26460, 26461..26505, 26506..26550, 26551..26595, 26596..26640, 26641..26685, 26686..26730, 26731..26775, 26776..26820, 26821..26865, 26866..26910, 26911..26955, 26956..27000, 27001..27045, 27046..27090, 27091..27135, 27136..27180, 27181..27225, 27226..27270, 27271..27315, 27316..27360, 27361..27405, 27406..27450, 27451..27495, 27496..27540, 27541..27585, 27586..27630, 27631..27675, 27676..27720, 27721..27765, 27766..27810, 27811..27855, 27856..27900, 27901..27945, 27946..27990, 27991..28035, 28036..28080, 28081..28125, 28126..28170, 28171..28215, 28216..28260, 28261..28305, 28306..28350, 28351..28395, 28396..28440, 28441..28485, 28486..28530, 28531..28575, 28576..28620, 28621..28665, 28666..28710, 28711..28755, 28756..28800, 28801..28845, 28846..28890, 28891..28935, 28936..28980, 28981..29025, 29026..29070, 29071..29115, 29116..29160, 29161..29205, 29206..29250, 29251..29295, 29296..29340, 29341..29385, 29386..29430, 29431..29475, 29476..29520, 29521..29565, 29566..29610, 29611..29655, 29656..29700, 29701..29745, 29746..29790, 29791..29835, 29836..29880, 29881..29925, 29926..29970, 29971..30015, 30016..30060, 30061..30105, 30106..30150, 30151..30195, 30196..30240, 30241..30285, 30286..30330, 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