Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 771484: A bag contains four red balls numbered 1,2,3,4 and five white balls numbered 5,6,7,8 and 9. A ball is drawn what is the probability that the ball
a Is red and an even numbered ball?
Is red or an even number?
Is white or and odd number
Click here to see answer by ramkikk66(644)  |
Question 771754: suppose IQ scores were obtained from randomly selected siblings.For 20 such pairs of people,the linear correlation coefficient is 0.892 and the equation of regression line is y^ = -6.63 + 1.06x, where x represents IQ score of older child.Also, the 20 y values have a mean of 99.2 and 20 x values have mean of 99.55. What is the best predicted IQ of the younger child, given that the older child has an IQ of 99 ? Use a significance level of 0.05. I have tried this by substituting x = 99 in regression equation but the answer is coming out to be wrong.
Click here to see answer by oscargut(2103)  |
Question 771732: Consider a sample of 10 marbles drawn from a bin that has red and green marbles.
The probability that any marble we draw is red is u = 0.55 (independently, with
replacement). We address the probability of getting no red marbles ( v = 0) in the
following cases:
4. We draw only one such sample. Compute the probability that v = 0. The
closest answer is (closest is the answer that makes the expression [your answer - given option] closest to 0):
[a] 7.331 X 10^-6
[b] 3.405 X 10^-4
[c] 0.289
[d] 0.450
[e] 0.550
Click here to see answer by oscargut(2103) |
Question 771811: Find the median of each of the 9 samples then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct median values
2,2 2,4 2,9 4,2 4,4 4,9 9,2 9,4 9,9
The table only has 6 slots and it asks to use the ascending order of the sample medians...I apparently am not understanding this part because I've missed it twice and only have one more attempt...please help me! I've tried arranging the sample medians in order but that didn't work either
Click here to see answer by oscargut(2103) |
Question 771861: There are four routes (call them P, Q, R and S) between Amy’s home and her place of work. Route Q is one-way so that she cannot take it on the way to work. Route R is one-way so that she cannot take it on the way home.
4) In how many ways can Amy go to and from work?
A. 7
B. 9
C. 8
D. 6
E. 16
5) In how many ways can Amy go to and from work without taking the same
route both ways?
A. 3
B. 5
C. 7
D. 9
E. 6
Click here to see answer by oscargut(2103) |
Question 771834: Assume that women's heights are normally distributed with a given by u=64.6 inches and a standard deviation given by a= 2.2 inches.
a. If 1 woman is randomly selected, find the probability that her height is less than 65 inches
b. If 44 women are randomly selected, find the probability that they have a mean height less than 65 inches
Any help would be greatly appreciated...Thanks :)
Click here to see answer by oscargut(2103) |
Question 771919: Question 1:
From past record, 75% of the retirees stated that they preferred living in an apartment to living in a one-family home. A random sample of 30 retirees was taken, and they are asked whether they prefer living in an apartment. 21 of these retirees are responded yes. Construct a 99% confidence interval for the proportion of all retirees who prefer living in an apartment.
Question 2:
A survey is being planned to determine the mean amount of time corporation executives watch TV. A survey indicated that the mean time per week is 12 hours with a standard deviation of 3 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 95% level of confidence is to be used. How many executives should be surveyed?
Question 3:
A population is estimated to have a standard deviation of 10. We want to estimate the population mean within 2, with a 95% level of confidence. How large a sample is required?
Click here to see answer by oscargut(2103) |
Question 772066: The Anxiety General Stress Test (ANGST) has been designed to gauge the level of psychological stress management trainees experience when they are under pressure.
For a random sample of trainees the scores are as follows: 47, 49, 53, 53, 54, 58, 61, 64, 75, 81.
Complete the calculations below using this data. Show all of your work and clearly label each of your calculations.
a.What is the z score equivalent of ANGST = 81?
b.What is the probability that someone selected at random will score 81 or lower?
c.What percentage of all trainees will score between 60 and 75?
OK for answer (a) I have:
z = (81 - 59.5)/11.098
z = 21.5/11.098
z = 1.937 or 1.94 (rounded up)
is that correct?
Click here to see answer by John10(297)  |
Question 772060: Cans of a certain beverage are labeled to indicate they contain 12 oz. The amounts in a sample of cans are measured and the sample statistics are n=37 and x=12.01 oz. If the beverage cans are filled so that u=12.00 oz (as labeled) and the population standard deviation is a=0.095 oz (based on sample results) find the probability that a sample of 37 cans will have a mean of 12.01 oz or greater.
Any help would be greatly appreciated. Taking stats online and my book or teacher is absolutely no help. If you could show how to solve that would be even better. Thanks :)
Click here to see answer by John10(297) |
Question 772204: 9. Customers arrive at a particular ATM at the rate of 30 customers per hour.
a. What is the probability of three customers arriving in a five minute-time interval?
Since it’s for a 5 minute interval: 30/60=0.5/min
0.5*5 mins=2.5 customers for 5 mins
f(3)=2.53e-2.5/3!
=0.21376
b. What is the probability of at least three customers arriving in a five-minute interval? NEED HELP WITH THIS PART
F(≥3)= 1-F(≤2)
=1-2.52e-2.5/2!
c. What is the probability of no customers arriving in a five-minute interval?
F(0)= 2.50e-2.5/0!
=0.08208
Click here to see answer by solver91311(24713)  |
Question 772189: Professor,
Not sure as to if this is the right section because I am in my 60s and haven't had anyone ask me a question like this:
How many integers from 1 to 1000 (exclusive) are divisible by the cube of an integer larger than or equal to 2
If you are as wise as an owl and can help me solve this for a friend please send me the solution as to how you came up with this answer and answer.
Regards,
snowhawk@mia.net
Click here to see answer by solver91311(24713) |
Question 772413: the monthly charge for local telephone calls is as following :
$ 80.00 FOR UP TO 100 Calls
plus 6 cent(c) per call for any of the next 100 calls
plus 4 cent(c) per call for any calls beyond 200
Draw a flowchart that inputs the number of local calls and output charge.
Click here to see answer by solver91311(24713) |
Question 772416: When this assignment is completed please send it to my graduate assistant (email address in Syllabus) via an email attachment. It will only be accepted in Word 2003 (.doc) format. That means if you do an assignment using Excel, you must copy and paste the Excel results into Word and save it as .doc (NOT .docx and NOT .xls or .xlsx).
Simulation assignments and random numbers
Throughout the term you will be asked to do several simulation assignments. To do those assignments you must generate random numbers in Excel. For example, using the Randbetween function.
Each time Excel calculates the spreadsheet the random numbers change, so it may be frustrating to generate statistics based on those numbers. For example if you calculate the mean of the numbers you get a slightly different result each time you try it.
To avoid this problem I suggest that after you generate the random numbers the first time, copy them (i.e., highlight them, right click and choose copy) and then paste them to another part of the spreadsheet by using the PASTE SPECIAL option. In that option, choose “values” and then “ok.”
If anyone has a better way of doing this please let me know (for extra credit, of course).
I made a video demonstrating this. It can be found in YouTube.
There are 7 parts to this assignment. Please label them in your WORD DOC report (NOT EXCEL file) to me as Part 1, Part 2, etc.
As before send them to my Graduate Assistant.
Part 1:
Using Excel’s Randbetween(0,9) function, generate 200 samples of five random numbers between 0 and 9, calculate the mean of each sample. Show me the list of the 200 means. Typically, they should look like: 4.8, 3.6, 4.4, 6.0, etc.
Part 2:
Using Excel, calculate the overall mean of the 200 sample means (the average of the averages). This should be around 4.5.
Part 3:
Using Excel, calculate the standard error of the mean (SEM) (i.e. the standard deviation of the 200 sample means). We established in the previous simulation that the population average is 4.5 and the standard deviation of the population is 2.87.
Since the SEM= σ = σ/√n. and n=5, the SEM therefore is 1.28. Thus, the standard deviation of the 200 sample means should be approximately 1.28.
Part 4:
Using Excel, make the histogram of the 200 sample means (sampling distribution of the mean) (use interval size 1, i.e., 0-1, 1-2, 2-3, …8-9). According to the Central Limit Theorem a bell shaped curve should appear. Show me this graph.
Part 5:
Discuss the intuitive logic of the Central Limit Theorem. Discuss the implications of part 4 in this context. (My videos might help here.)
Part 6:
Use 2 methods to find P ( >6.3), (with n=5 as in Parts 1-4): First the z-method of chapter 7 and then by simply counting how many of your 200 were above 6.3.
Part 7:
Discuss the standard error of the mean. (Explain clearly the reasons why there is an “n” in the bottom of the formula; my video might help here as well.)
Make sure to label each section Part 1, Part 2 …, Part 7 and send it to my graduate assistant in word.DOC format.
Click here to see answer by solver91311(24713) |
Question 772414: All assignments will only be accepted in Word 2003 (.doc) format. That means if you do an assignment using Excel, you must copy and paste the Excel results into Word and save it as .doc (NOT .docx and NOT .xls or .xlsx). Send it to my graduate assistant (email address in the Syllabus) as an email attachment.
Simulation assignments and random numbers
You will be asked to do several simulation assignments. To do those assignments you must generate random numbers in Excel. For example, using the Rand between(0,9) function.
Because each time Excel calculates the spreadsheet the numbers change, it may be frustrating to generate statistics based on those numbers. For example if you calculate the mean of the numbers you get a slightly different result each time you try it.
To avoid this problem I suggest that after you generate the random numbers the first time, copy them (i.e., highlight them, right click and choose copy) and then paste them to another part of the spreadsheet by using the PASTE SPECIAL option. In that option choose “values” and then “ok.”
If anyone has a better way of doing this please let me know (for extra credit, of course).
There are 8 parts to this assignment. Please label them in your report to me as Part 1, Part 2, etc.
In chapter 5 you will learn about the binomial random variable. Among other applications, this predicts the probability of flipping four fair coins and getting 0, 1, 2, 3 or 4 heads. In the terminology of Chapter 5, P(X=0), P(=1), etc.
Part 1:
After learning the binomial probability formula I want you to calculate these 5 probabilities. Make sure they add up to 1.00 as all possibilities are represented in 0, 1, 2, 3 and 4. Express the results as a probability distribution.
Part 2:
After learning the other main formula of chapter 5, E(X), calculate the Expected value of this random variable. Common sense dictates that the answer is 2 because when you flip 4 coins you ‘expect’ to get 2 heads and 2 tails on the average. Verify it by the E(X) formula AND by the ‘shortcut’ E(X)=np formula.
Part 3:
Calculate the standard deviation of the theoretical distribution, σ = Σ(x-u)2 P(X). Also do this by the ‘shortcut’ binomial formula for σ = √np(1-p). The answer in both cases should be exactly 1.
Part 4:
Then simulate flipping 4 fair coins 100 times. You can do this by physically flipping the coins or, as I want you to do it, by using Excel.
In Excel there is a function which generates random integers between any two points. If you type into the A1 cell the Excel formula (by using “=”) Randbetween(0,1) the computer will fill that cell with a 0 or 1 with 50/50 probability. By copying that formula into the cells A1, B1, C1 and D1 you should see: 0 0 1 0, for example, or 0 1 0 1.
If you interpret a 0=tails and 1=heads the computer can do the dirty work of flipping 4 coins. Then put in the E1 cell the sum of A1, B1, C1 and D1. This represents how many heads were observed. In the first example you would see a “1” and in the second example a “2.” If 1 1 1 1 were seen that represents getting 4 heads.
Copy (by dragging the corner of the cells) the first row 100 times. When you are finished the E column should contain the numbers 0 or 1 or 2 or 3 or 4 representing the number of heads flipped by the computer in that row.
Show me the results of this 100x5 table
Part 5:
Since the probability of getting all 4 heads, according to the binomial formula, is 1/16 or 6.25%, approximately 6 out of 100 rows should contain a “4.” Create a brief table that compares the theoretical binomial probability to what was actually ‘flipped’ by the computer for 0 heads, 1 head, 2 heads, 3 heads and 4 heads.
Part 6:
Calculate the actual mean or average of column E and compare this number to the theoretical E(X).
Part 7: Calculate the actual standard deviation of column E and compare this number to the theoretical σ.
Part 8:
Finally, explain any discrepancy between the theoretical and actual results for the probabilities and E(X) and tell me how you would modify the assignment so that the discrepancy is smaller.
Click here to see answer by solver91311(24713) |
Question 772898: Let A be the event that a student is enrolled in an accounting course, and let S be the event that a student is enrolled in a statistics course. It is known that 30% of all students are enrolled in an accounting course and 40% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and accounting. Find the probability that a student is in accounting and is also in statistics.
Click here to see answer by oscargut(2103) |
Question 773043: Suppose it is 11 to 5 against a person who is now 38 years of age living till he is 73 and 5 against 3 against B now 43 living till he is 78.Find the chance that at least one of these persons will be alive 35 years hence.
Click here to see answer by oscargut(2103) |
Question 773061: Suppose the following table represents the probability distribution for the number of days that an employee is absent from work during a week selected at random.
X = number of days absent
X 0 1 2
probability .80 .15 .05
a.) what is the probability that an employee could be absent for more than 2 days?
B.) what is the expected value for the number of days absent?
c.)what is the variance for the number of days absent
d.) what is the standard deviation fro the number of days absent?
Click here to see answer by oscargut(2103) |
Question 773074: a reasearcher wishes to estimate with 95% confidence the proportion of adults whohave high speed internet access. her estimate must be accurate within 2% of the true proportion. find the minimum sample size needed using a prior study that fouhd that 46% of the respondents said they have high speed internet access. no preliminary estimate is available. find the minimum sample size needed
Click here to see answer by oscargut(2103) |
Question 773417: Hi, I'm a little confused on this question. Can you help?
A random sample of 400 college students was selected and 120 of them had at least one motor vehicle accident in the previous two years. A random sample of 600 young adults not enrolled in college was selected and 150 of them had at least one motor vehicle accident in the previous two years. At the .05 level, you are testing whether there is a significant difference in the proportions of college students and similar aged non college students having accidents during the two year period. Is this a
1 or 2 tail test?
Is this a one sample or two sample test?
Is this a test of sample means or sample proportions?
What are your critical values?
What is the value of your pooled proportion?
What is the value of your test statistic?
What is your decision?
If you determine not to reject the null hypothesis what is your conclusion?
Click here to see answer by stanbon(75887) |
Question 773407: A recruiter estimates that if you are hired to work for her company and you put in a full week at the commissioned sales representative position she is offering, you will make “$525 plus or minus $250, 80% of the time.” She adds, “It all depends on you!” If the $525 is the mean, state what the following figures stand for in terms of the confidence interval around this mean.
- What does the “$525 plus or minus $250” mean?
- What does the “80% of the time” mean?
Any help would be greatly appreciated :)
Click here to see answer by stanbon(75887) |
Question 773397: The average refund amount was 748 with a standard deviation of 124. Standard normal distribution
1. Calculate the percentage of refunds expected to exceed 1000 under the current witholding guidelines.
2. Calculate the percentage increase in the refunds exceeding 1000 if the average refunds invreases by 150. assume that the degree of variability in refunds remain unchanged when the average refund increases by 150.
3. What would be the effect on the percentage of refunds over 1000 if the average refund amount actually drops by 75.
4. What change in the current average refund over 1000 will produce a 7% increase in the current percentage of refunds over 1000. Assume no change in the
degree of variability in refund amounts.
please show all workings.
Thanks
Click here to see answer by stanbon(75887) |
Question 773457: Think about all the four - digit numbers you could make with the digits 1-4. What is the probabilty that the first digit will be a 3? Please help. Explain fully. Make me understand so I can explain to others.
Click here to see answer by mananth(16946)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560, 16561..16605, 16606..16650, 16651..16695, 16696..16740, 16741..16785, 16786..16830, 16831..16875, 16876..16920, 16921..16965, 16966..17010, 17011..17055, 17056..17100, 17101..17145, 17146..17190, 17191..17235, 17236..17280, 17281..17325, 17326..17370, 17371..17415, 17416..17460, 17461..17505, 17506..17550, 17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 20746..20790, 20791..20835, 20836..20880, 20881..20925, 20926..20970, 20971..21015, 21016..21060, 21061..21105, 21106..21150, 21151..21195, 21196..21240, 21241..21285, 21286..21330, 21331..21375, 21376..21420, 21421..21465, 21466..21510, 21511..21555, 21556..21600, 21601..21645, 21646..21690, 21691..21735, 21736..21780, 21781..21825, 21826..21870, 21871..21915, 21916..21960, 21961..22005, 22006..22050, 22051..22095, 22096..22140, 22141..22185, 22186..22230, 22231..22275, 22276..22320, 22321..22365, 22366..22410, 22411..22455, 22456..22500, 22501..22545, 22546..22590, 22591..22635, 22636..22680, 22681..22725, 22726..22770, 22771..22815, 22816..22860, 22861..22905, 22906..22950, 22951..22995, 22996..23040, 23041..23085, 23086..23130, 23131..23175, 23176..23220, 23221..23265, 23266..23310, 23311..23355, 23356..23400, 23401..23445, 23446..23490, 23491..23535, 23536..23580, 23581..23625, 23626..23670, 23671..23715, 23716..23760, 23761..23805, 23806..23850, 23851..23895, 23896..23940, 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