Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 715549: In an article appearing in Today’s Health, a writer states that a single serving of popcorn has on average 75 calories. To determine if the average number of calories in a single serving of popcorn is different from 75, a nutritionist selects a random sample of 20 servings of popcorn and computes the sample mean number of calories to be 78 with a sample standard deviation of 7. Assume the caloric content of popcorn is normally distributed.
I need to compute the test value. I have looked in my book and can't find a similar problem to help me. Any help or show how to get it is greatly appreciated.
Click here to see answer by stanbon(75887)  |
Question 715509: 19. Give an example of something having these distribution shapes: (a) bimodal, (b) approximately rectangular, and (c) positively skewed. Do not use an example given in this book or in class.
20. Find an example in a newspaper or magazine of a graph that misleads by failing to use equal interval sizes or by exaggerating proportions.
21. Nownes (2000) surveyed representatives of interest groups who were registered as lobbyists of three U.S. state legislatures. One of the issues he studied was whether interest groups are in competition with each other. Table 1–10 shows the results for one such question. (a) Using this table as an example, explain the idea of a frequency table to a person who has never had a course in statistics. (b) Explain the general meaning of the pattern of results.
22. Mouradian (2001) surveyed college students selected from a screening session to include two groups: (a) “Perpetrators”—students who reported at least one violent act (hitting, shoving, etc.) against their partner in their current or most recent relationship—and (b) “Comparisons”—students who did not report any such uses of violence in any of their last three relationships. At the actual testing session, the students first read a description of an aggressive behavior such as, “Throw something at his or her partner” or “Say something to upset his or her partner.” They then were asked to write “as many examples of circumstances of situations as [they could] in which a person might engage in behaviors or acts of this sort with or towards their significant other.” Table 1–11 shows the “Dominant Category of Explanation” (the category a participant used most) for females and males, broken down by comparisons and perpetrators. (a) Using this table as an example, explain the idea of a frequency table to a person who has never had a course in statistics. (b) Explain the general meaning of the pattern of results.
Click here to see answer by Positive_EV(69)  |
Question 715533: Twenty-six tiles with each of the 26 letters of the alphabet printed on them are placed in a box. If three tiles are selected from the box, with replacement, what is the probability that the tiles selected will spell the word ADD? The letters must be selected in the correct order.
Click here to see answer by Positive_EV(69) |
Question 715561: A bag contains seven batteries, all of which are the same size and are equally likely to be selected. Each battery is different brand. If you select five batteries at random, use the counting principle to determine how many points will be in the sample space if the batteries are selected.
A) with replacement
b) without replacement
Click here to see answer by stanbon(75887) |
Question 715815: A distribution has a standard deviation population deviation = 12 find the z-score of the following location; above the mean by 3 points
I need help with this question, at least the steps to solve this question please.
Click here to see answer by stanbon(75887) |
Question 715968: For sample mean x = 150, sample size n = 36 and sample standard deviation s = 40 find 80% confidence interval for population mean. Population standard deviation is not known, you should use formula on page 328 with t-value from Appendix Table IV (use column t0.10).
Click here to see answer by stanbon(75887) |
Question 715944: The ages od a group of 50 women are approximately normally disributed with a mean of 50 years and a standard deviation of 6 years. One woman is randomly selected from the group, and her age is observed. Find the probability that her age will fall between 56 and 61 years. I don't understand this and I am having trouble.
Click here to see answer by stanbon(75887) |
Question 715973: please help me solve this problem of probability and statistics on fundamental counting principle :In how many ways can 4 of 7 different kinds of bushes be planted along one side of a house? i'll be waiting for your help thanks!
Click here to see answer by stanbon(75887) |
Question 715927: The help desk for a software company logs the lengths of times of each call that technicians have with customers. Historical records based on the past 3 years indicate that call length (L) is a normally distributed variable with an average (μ) of 9.00 minutes and a standard deviation (σ) of 0.95 min. For each of the problems below, find the appropriate probability.
A) P(L ≤ 10.22)
B) P(L > 10.74)
C) P(7.67 ≤ L < 11.02)
D) The call times that enclose the central 81% of the distribution are:
Note: Round your answers to two decimal places for this problem.
I really need step by step help. Im not coming up with the correct answers..
Low: to High:
Click here to see answer by stanbon(75887) |
Question 716435: 7. A SC Tourist Bureau survey showed that 75% of those who seek information about the state actually come to visit. The office received 12 requests for information. Find:
a. The probability that more than five of the people will visit SC? ______
b. The probability that at least 3 of the people will not visit SC? ______
c. The probability that 4 to 8, inclusive, of the people will visit SC? _______
d. What is the expected number of visitors from this group? __________
e. Make the histogram of the binomial distribution for this situation.
Click here to see answer by stanbon(75887) |
Question 716456: Sample with size n = 100 has mean = 30. Assuming the population standard deviation is 8, construct 95% confidence interval for population mean. Use formula zα/2 = 1.96
Answer ? Help?
between 28.4 and 31.6
between 27.0 and 33.0
between 26.1 and 34.2
between 24.1 and 35.9
Click here to see answer by jim_thompson5910(35256) |
Question 716979: A package contains 37 fuses, of which 6 are defective. A sample of 5 fuses is selected at random.
(b) How many of the samples contain exactly 2 defective fuses?
(c) How many of the samples contain at least 1 defective fuse?
Click here to see answer by stanbon(75887) |
Question 717080: Please could you kindly help me solve this question.Kindly show me all the working stages. Thank you very very much for your help.
The question: A company suuplies pins to a customer. It uses an automatic lathe to produce the pins. Due to factors such as vibration, temperature and wear and tear, the lengths of the pins are normally distributed with a mean of 25.30 mm and a standard deviation of 0.45 mm. The customer will only buy those pins with lengths in the intervals of 25.00 +/- 0.50mm.
a. What percentage of the pins will be acceptable to the customer?
My final answer is:
Therefore 0.1700 + 0.4616 = 0.6316
= 63.16% of the pins will be acceptable.
Is this correct?
b. In order to improve the percentage accepted, management considers adjusting the population mean and standard deviation of the length of the pins. If the lathe can be adjusted to have any desired mean of the lenghts, what should it be adjusted to? Why?
My answer
To improve the acceptance probability of pins, the required mean should be in
the middle of 24.50 and 25.50 so as to cover maximum area.
Thus the mean should be adjusted to the value 25.00 mm.
Is this correct?
c. Suppose that the mean cannot be adjusted but the standard deviation can be reduced. Calculate the maximum reduction in the standard deviation that would make 85% of the pins acceptable? (Assume the mean to be 25.30mm).
I have no idea!!! Please help
d. The production manager the considers the costs involved. The cost of resetting the machine to adjust the population mean involves engineering costs and the cost of production time lost. The cost of reducing the population standard deviation involves, in addition to these costs, the cost of overhauling the machine and reengineering the process. Assume it costs $150 Xsquared to decrease the standard deviation by (x/40)mm. Find the cost of reducing the standard deviation to the values found in C.
I have no idea!! Please help
Click here to see answer by lynnlo(4176) |
Question 717083: Please help with this calculation, please show full workings. Many thanks.
The president of a company that manufactures air conditioners is considering switching his supplier of condensers. Supplier A, the current producer of condensers for the manufacturer, prices its product 5% (percent) higher than supplier B does. Because the president wants to maintain his company's reputation for quality, he wants to be sure that Supplier's B condensers last as least as long as Supplier A's condensers. After a careful analysis, the president decided to retain supplier A if there is sufficient statistical evidence that supplier A's condensers last longer, on average than Supplier B's condensers. In an expirement, 15 randomly-selected midsize cars were equipped using type-A condensers while another 15 randomly-selected midsize cars were equipped with type-B condensers. The number of kilometers (in thousands) driven by each car before the condenser broke down is displayed in the table below.
Carry out a hypothesis test, at 5% (percent) significance level, to determine whether the president should retain supplier A.
The numbers below from Supplier A and Supplier B are corresponding. I cant do them next to each other then it squashes them all together. Not sure why.
Supplier A
156
146
93
152
80
111
107
118
115
125
108
97
142
160
102
Supplier B
109
75
131
131
129
147
78
124
86
127
111
146
114
136
98
Click here to see answer by lynnlo(4176) |
Question 717065: from the following data find the missing frequency when mean is 15.38.
______________________________________________________
MARKS: 10 12 14 16 18 20
FREQUENCY: 3 7 12 20 ? 5
________________________________________________________
Click here to see answer by jsmallt9(3758) |
Question 717102: The probability that a particular machine breaks down on any day is 0.2 and is independent of the breakdowns on any other day. The machine can break down only once per day. Calculate the probability that the machine breaks down two or more times in ten days.
(A) 0.0175 (B) 0.0400 (C) 0.2684 (D) 0.6242 (E) 0.9596
Click here to see answer by htmentor(1343)  |
Question 717217: At a HOA meeting, a board member can vote ye, no, or abstain on a motion. There are two motions on which each board member must vote.
Determine the number of piint in this sample space
Determine th probability that a board member votes yes on both of the motions
Deetermin e the probabilty that board member votes yea on at least one motion.
Click here to see answer by solver91311(24713)  |
Question 717642: Suppose an exam has 34 questions on it and students need to answer 22 of the questions. In how many ways
can this be done if the first 4 and exactly 5 of the last 8 questions must be answered and question #13 must not
be answered because of a typo?
Pilion Pizza makes a specialty pizza with 4 layers of toppings alternating with layers of cheese and
advertises that it offers 36 different toppings.
a) How many different pizzas can be made if none of the toppings can be duplicated and the
order of the toppings matters?
b) How many different pizzas can be made if none of the toppings can be duplicated and the
order of the toppings doesn’t matter?
Click here to see answer by stanbon(75887) |
Question 717749: One professor grades homework by randomly choosing 3 out of 15 homework problems to grade How many different groups of 3 problems can be chosen from the 15 problems?
Probability extension: Jerry did only 3 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?
Click here to see answer by stanbon(75887) |
Question 717548: Please help me solve this statistics problem
Four students drive to school in the same car. The students claim they were late to school and missed a test because of a flat tire. On the makeup test, the instructor asks the students to identify the tire that went flat;
front driverʼs side, front passengerʼs side, rear driverʼs side, or rear passengerʼs side. If the students didnʼt really have a flat tire and each randomly selects a tire, what is the probability
that all four students select the
same tire?
Click here to see answer by lynnlo(4176) |
Question 717765: In a lottery 4 cards are drawn from 5000. 2 out of 5000 cards are yours.
P(at least one of your cards are drawn)
Please, note, this number is very low. Enter at least 6 digits after zero.
i got .003998 originally but i guess its wrong
Click here to see answer by DrBeeee(684) |
Question 717692: A grab bag contains 12 packages worth 80 cents apiece, 15 packages worth 40 cents apiece, and 25 packages worth 30 cents apiece. Is it worthwhile to pay 50 cents for the priviledge of picking one of the packages at random? Why or why not?
Click here to see answer by DrBeeee(684) |
Question 717976: We have a binomial experiment with p = 0.4 and n = 2.
(1) Set up the probability distribution by showing all x values and their associated probabilities.
(2) Compute the mean, variance, and standard deviation.
Click here to see answer by oscargut(2103)  |
Question 717928: Please need help don't quite understand probabilities, please show all work.
A kindergarten class consists of 14 boys and 11 girls. If the teacher selects children from the class using random sampling,
a. what is the probability that the child selected will be a girl?
b If the teacher selects a random sample of n = 3 children and the first two are both boys, what is the probability that the third child selected will be a girl?
Click here to see answer by oscargut(2103) |
Question 718006: an airline estimates that 98% of people booked on their flight actually showed up. if airline books 76 people on a flight for which the maximun number is 74, what is the probability that the number of people who showed up will exceed the capacity of the plane
Click here to see answer by stanbon(75887) |
Question 718018: thank you for looking at this: You flip a coin three times. (a) What is the probability of getting heads on only one of your flips? (b) What is the probability of getting heads on at least one flip?
my answer to the first one was (a) is .875 or 1/8
i didn't understand the question being asked twice since they both are 7/8
i don't understand "on only one of your flips" being different from "at least one flip"
also how i found my answer was by taking the probability of not getting a head
(1/2)(1/2)(1/2) =.125 or 1/8 so 7/8 is my final answer
Click here to see answer by lynnlo(4176) |
Question 717910: Team A and Team B are playing in the World Series (7 games). So far Team B has won 2 games and Team A has won 1 game. If the odds for either team to win any game are even and the series ends when one team wins four games, what is the probability that the Team B will win the series?
Click here to see answer by lynnlo(4176) |
Question 718059: ok it says: of the water lilies in the pond 43% are yellow. The others are white. A frog randomly jumps on to a lily. Describe the complement of the frog landing on a yellow lily and find it propability. PLEASE PEASE PLEASE HELP ME!!!
Click here to see answer by josmiceli(19441)  |
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11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 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23941..23985, 23986..24030, 24031..24075, 24076..24120, 24121..24165, 24166..24210, 24211..24255, 24256..24300, 24301..24345, 24346..24390, 24391..24435, 24436..24480, 24481..24525, 24526..24570, 24571..24615, 24616..24660, 24661..24705, 24706..24750, 24751..24795, 24796..24840, 24841..24885, 24886..24930, 24931..24975, 24976..25020, 25021..25065, 25066..25110, 25111..25155, 25156..25200, 25201..25245, 25246..25290, 25291..25335, 25336..25380, 25381..25425, 25426..25470, 25471..25515, 25516..25560, 25561..25605, 25606..25650, 25651..25695, 25696..25740, 25741..25785, 25786..25830, 25831..25875, 25876..25920, 25921..25965, 25966..26010, 26011..26055, 26056..26100, 26101..26145, 26146..26190, 26191..26235, 26236..26280, 26281..26325, 26326..26370, 26371..26415, 26416..26460, 26461..26505, 26506..26550, 26551..26595, 26596..26640, 26641..26685, 26686..26730, 26731..26775, 26776..26820, 26821..26865, 26866..26910, 26911..26955, 26956..27000, 27001..27045, 27046..27090, 27091..27135, 27136..27180, 27181..27225, 27226..27270, 27271..27315, 27316..27360, 27361..27405, 27406..27450, 27451..27495, 27496..27540, 27541..27585, 27586..27630, 27631..27675, 27676..27720, 27721..27765, 27766..27810, 27811..27855, 27856..27900, 27901..27945, 27946..27990, 27991..28035, 28036..28080, 28081..28125, 28126..28170, 28171..28215, 28216..28260, 28261..28305, 28306..28350, 28351..28395, 28396..28440, 28441..28485, 28486..28530, 28531..28575, 28576..28620, 28621..28665, 28666..28710, 28711..28755, 28756..28800, 28801..28845, 28846..28890, 28891..28935, 28936..28980, 28981..29025, 29026..29070, 29071..29115, 29116..29160, 29161..29205, 29206..29250, 29251..29295, 29296..29340, 29341..29385, 29386..29430, 29431..29475, 29476..29520, 29521..29565, 29566..29610, 29611..29655, 29656..29700, 29701..29745, 29746..29790, 29791..29835, 29836..29880, 29881..29925, 29926..29970, 29971..30015, 30016..30060, 30061..30105, 30106..30150, 30151..30195, 30196..30240, 30241..30285, 30286..30330, 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