Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 133129: If $9,000 is invested for t years at 8% interest compounded continuously, the future value is given by s = 9,000e^0.08t dollars.
a) graph this function for 0 ≤ t ≤ 15
b) use the graph to estimate when the future will be $16,000
Thank you for your help!
Click here to see answer by stanbon(75887)  |
Question 133353: An auto repair shop takes an average of 45 minutes to complete a repair job. The owner of the shop has determined the repair time has a standard deviation of 8 minutes. A customer comes into the shop and states that she will return in 35 minutes -- at which time she must have the car ready to drive off. Using the normal probability distribution, what is the probability the car will be repaired in 35 minutes or less?
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Question 133335: The engineer in a widget factory wants to test out a new form of raw materials. So a batch of widgets are made in the old manner as a control group and then a batch are made with the new materials as a comparison. If the widget weight is statistically the same on both sets, the new materials will be used. The weights of the 10 old process widgets and the 10 new process widgets are seen below.
Old New
36.19 36.20
35.80 36.62
36.00 36.03
36.19 36.40
36.18 36.44
36.11 36.02
36.13 36.12
36.48 36.56
35.98 36.05
36.40 36.44
1. Define this situation as either a 2 sample test or a paired test. Why?
2. Calculate a test statistic
3. Calculate a p-value
4. Give an accurate statement as to whether or not the new widget material should be used. Use a significance level of 0.05.
Click here to see answer by stanbon(75887) |
Question 133400: Does lovastatin (a cholesterol-lowering drug) reduce the risk of heart attack? In a Texas study,
researchers gave lovastatin to 2,325 people and an inactive substitute to 2,081 people (average age
58). After 5 years, 57 of the lovastatin group had suffered a heart attack, compared with 97 for the
inactive pill. (a) State the appropriate hypotheses. (b) Obtain a test statistic and p-value. Interpret the results at α = .01. (c) Is normality assured? (d) Is the difference large enough to be important?
(e) What else would medical researchers need to know before prescribing this drug widely?
Click here to see answer by stanbon(75887) |
Question 133415: Hi, I'm at a lost and need some help. Could you please help me with chapter 8 problems 8.46 and 8.62 from the chapter exercise section. Also can you please help me with these problems. 1)The score on the entrance test for a well known law school has a mean score of 200 points and a standard deviation of 50 points. At value should the lowest passing score be set if the school wishes only 2.5% of those taking the entrance test to pass? and ....2)A tire manufacturer wishes to investigate the thread life of its tires. A sample of 10 tires driven 50,000 miles revealed a sample mean of 0.32 inches of thread remaining with a standard deviation of 0.09 inches. Construct a 95% confidence interval for the population mean. Would it be reasonable for the manufacturer to conclude that after 50,000 miles the population mean amount of thread remaining is 0.30 inches? I'm really confussed and is in great need of help.
Click here to see answer by stanbon(75887) |
Question 133389: The Web-based company Oh Baby! Gifts has a goal of processing 95 percent of its orders on the
same day they are received. If 485 out of the next 500 orders are processed on the same day, would
this prove that they are exceeding their goal, using α = .025?
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Question 133328: I can't seem to find a right solution for this problem:
If you are dealt an Ace and King of Clubs in Texas Hold'em poker, what is the probability of not hitting any of the nine poker hands. (see this link for poker hands) http://en.wikipedia.org/wiki/Rank_of_hands_(poker)
Please note that since you are dealt two cards there are now only fifty cards in the deck. And this problem does not account for any "Burn" cards, so it is such that you are just flipping over five cards. In other words, do not include burn cards.
I hope that you can answer my question and it probably helps if you know a small amount about Texas Hold'em...
Click here to see answer by stanbon(75887) |
Question 133481: 4. Consider the following contingency table:
Under 20 21-30 31-40
Male 12 12 17
Female 13 16 21
a. If one person is selected at random, what is the probability that person is Female? ______
b. If one person is selected at random, what is the probability that person is either under 20 or over 30? _______
c. If one person is selected at random, what is the probability that person is either male or in the age group 21-30? _____
d. If two people are selected at random, what is the probability they are both female? ______
Click here to see answer by oscargut(2103)  |
Question 133478: A normal distribution with a mean of 55 and a standard deviation of 6 is evaluated to solve a business problem. What is the probability that any value in the population is between 55 and 65? ___________. What is the probability that any value in the population is between 45 and 65? ____________.
Click here to see answer by stanbon(75887) |
Question 133479: A business owner decides to use a binomial distribution to solve one of his problems. He knows there is a 60 percent probability that he will sell one of his Red Oak floors to any customer who comes into his shop and views the wood. Out of the next 7 people who come into his shop, what is the probability that 3 people will buy a Red Oak floor? ___________ What is the probability that more than four people will buy the Red oak floor? ___________
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Question 133509: Question, please help! On line course, No ISBN provided.
High level of cockpit noise in an aircraft can damage hearing of pilots who are exposed to this hazard for many hours. A Beoing 727 co-pilot collected 61 noise observations using a handled sound meter. Noise level is defined as "low (under 88 decibles), Medium (88 to 91), high (92 or more). There are three flight phases (Climb,Cruise,Descent). At alph=.05, is the cockpit noise level independent of flight phase? State hypothesis, show degrees of freedom, find critical value of chisquare, and interpret p=value.
Noise Level,Climb,Cruise,Descent,Row Total
Low,6,2,6,14
Medium,18,3,8,29
High,1,3,14,18
Col total,25,8,28,61
Thank you!
Click here to see answer by stanbon(75887) |
Question 133505: Please help, I don't have an ISBN number because its an online course.
A student team examined parked cars in four different suburban shopping malls. One hundred vehicles were examined in each location. At alph=.05, does vehicle type vary by mall location? State hypothesis, show degree of freedom, find critical value of chisquare and interpret p-value.
Vehicle type,Somerset,Oakland,Greatlakes,Jamestown,Row Total
Car,44,49,36,64,193
Minivan,21,15,18,13,67
Full-sizedVan,2,3,3,2,10
SUV,19,27,26,12,84
Truck,14,6,17,9,45
Col Total,100,100,100,100,400
Thank you in advance.
Click here to see answer by stanbon(75887) |
Question 133654: Note: Use the five-step hypothesis testing procedure to solve the following exercise.
[show the answer for each of the five steps]
As part of a study of corporate employees, the Director of Human Resources for PNC, Inc. wants to compare the distance traveled to work by employees at their office in downtown Cincinnati with the distance for those in downtown Pittsburgh.
A sample of 35 Cincinnati employees showed they travel a mean of 370 miles per month, with a standard deviation of 30 miles per month.
A sample of 40 Pittsburgh employees showed they travel a mean of 380 miles per month, with a standard deviation of 26 miles per month.
At the .05 significance level, is there a difference in the mean number of miles traveled per month between Cincinnati and Pittsburgh employees?
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Question 133690: Using data from any year in the last 10 years, estimate the probability a newborn baby will be female.
The total population os 2001 is 281,421,906
total numbers of females born in 2001 is 143,368,343
143,368,343,/ 281,421,906 = 0.509
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Question 133663: Estimate the probabiltiy that a randomly selected person in the U.S. will be afflicted with asthma. Use this probability to estimate the number of Americans afflicted in 2000.
22.2 million in america with asthma
281 is the total population in 2000
22.2/281 = 0.079
0.079 * 281,000,000 = 2.219,900 probablility
Click here to see answer by edjones(8007)  |
Question 133760: Hi, Can someone help me with these 2 questions, I'm a little confused as to what I am suppose to be doing.
1. You are the incoming inspector for potato chips – you are to ensure that each bag has 16 ounces or more in it. You want your testing to be at the level of significance of 0.05. You pull a sample of 49 bags of chips from a recent truckload. Your sample statistics are:
x-bar (the sample mean) = 15.9 ounces
s ( the sample standard deviation) = 0.35 ounces
(a) what is the null and alternative hypothesis
(b) one or two tailed test ??
(c) what is the critical z value for your test at the 0.05 level of significance??
(d) what is the calculated z value ??
(e) what is your decision about the load of potato chips ??
-- reject ?? -- not-reject ??
(a) Ho : μ <= 16 Vs H1 : μ < 16 (Left tailed test)
(b) One tailed test
(c) Critical z = 1.645
(d) Test Statistics:
z = follows N(0,1)
= -2
where
x bar=15.9 n=49 s=0.35 μ= 16
(e) Rejection Rule
Critical Value = -1.645
Thus we reject H0 if z < -1.645
As z = -2 < -1.645 we reject H0.
At the 5% level of significance, the data provides enough evidence to reject the null hypothesis. Thus we conclude that each bag has less than 16 ounces.
2. An owner of a fast food restaurant reported to corporate headquarters that the average bill paid by his customers in the last quarter was $6.20 and that the standard deviation was $1.90. Not knowing exactly what the effect would be, headquarters suddenly launched a nationwide promotional campaign featuring a large quantity discount for a multi-sandwich purchase. The stubs from the next 81 purchases at the owner’s franchise after the campaign was launched averaged $6.65.
Conduct the 5 step hypothesis test at a level of significance of 0.05 to determine if the promotion increased the average bill amount
Ans.
• To Test
Ho : μ= 6.20 Vs H1 : μ > 6.20 (Right tailed test)
• Level of significance = 0.05
• Test Statistics:
z = xbar-μ/SE follows N(0,1)
= 2.13
where
xbar =6.65 n=81 sd=1.9 μ= 6.2
• P-value = P(z > 2.13) = 0.0165
Since P-value of 0.0165 < 0.05 we reject H0.
It is statistically significant
• Rejection Rule
Critical Value = 1.645
Thus we reject H0 if z > 1.645
As z = 2.13 > 1.645 we reject H0.
• Conclusion
At the 5% level of significance, the data provides enough evidence to reject the null hypothesis. Thus we conclude that the promotion increased the average bill amount.
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Question 134271: Answer the following questions, inserting values from the ANOVA table below.
A. What is the Sum of Squares of Treatment?
B. What is the Total Sum of Squares?
C. What is the Mean Square Error (MSE) ?
D. What is the Test Statistic?
E. What is the P-value?
F. How many treatments (groupings) are being compared?
G. How many total observations are in this analysis?
H. What is the null hypothesis tested here?
Click here to see answer by stanbon(75887) |
Question 134229: An auditor reviewed 25 oral surgery insurance claims from a particular surgical office, determining that the mean out-of-pocket patient billing above the remibursed amount was $275.66 with a standard deviation of $78.11. (a) At the 5% level of significance, does this sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket? State your hypotheses and decision rule. (b) Is this a close decision?
Thanks for your help.
Applied Statistics in Business and Economics
David P. Doane, Lori E. Seward
Publisher: Boston : McGraw-Hill/Irwin, c2007.
ISBN: 0072966939 DDC: 519.5 LCC: HF1017 Edition: (student ed.)
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Question 134174: According to a study, brain weight of men in country A are normally distributed with mean 1.40 kg and standard deviation 0.13kg. Apply the 68.26-95.44-99.74 to fill in the blanks
99.74 of men in country A have weights btw _&_
99.74 % of men in country A have brain weights btw __kg&__kg
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Question 134144: 60. Owens Orchards sells apples in a large bag by weight. A sample of seven bags contained the following numbers of apples: 23, 19, 26, 17, 21, 24, 22.
a. Compute the mean number and median number of apples in a bag.
_
b. Verify that (X – X) = 0.
The mean (average) of 17,19,21,22,23,24, and 26 is: 21.714285.
The median of this set is: 22.
This set has no mode.
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Question 133947: An owner of a fast food restaurant reported to corporate headquarters that the average bill paid by his customers in the last quarter was $6.20 and that the standard deviation was $1.90. Not knowing exactly what the effect would be, headquarters suddenly launched a nationwide promotional campaign featuring a large quantity discount for a multi-sandwich purchase. The stubs from the next 81 purchases at the owner’s franchise after the campaign was launched averaged $6.65.
Conduct the 5 step hypothesis test at a level of significance of 0.05 to determine if the promotion increased the average bill amount.
Click here to see answer by stanbon(75887) |
Question 134313: Source-------DF----Sum of Squares--Mean Squares---F Ratio----Prob>F
Treatment----2------100.5571-------50.2786--------1.7222-----0.1847
Error--------87----2539.9445-------29.1948
C.Total------89----2640.5017
A. What is the Sum of Squares of Treatment?
B. What is the Total Sum of Squares?
C. What is the Mean Square Error (MSE) ?
D. What is the Test Statistic?
E. What is the P-value?
F. How many treatments (groupings) are being compared?
G. How many total observations are in this analysis?
H. What is the null hypothesis tested here?
Click here to see answer by stanbon(75887) |
Question 134350: bag #1 has 2 marbles, 1 black and 1 red
bag #2 has 5 marbles, 2 black and 3 red
Without seeing into the bag, you may select one marble from either bag. If it is black, you win a prize. Would it be better to select one marble from bag #1, bag 2 or does it make no difference?
Click here to see answer by oscargut(2103) |
Question 134267: Please assist, No ISBN number due to being an online course.
An expert in a case alleged racial discrimination in a state university school of nursing introduced a regression of the determination of Salary of each professor for each year during an 8-year period (n=423) with the following results, with dependent variable Year (year in which the salary was observed) and predictors YearHire (year when the individual was hired), Race (1 if individual is black, 0 otherwise), and Rank (1 if individual is an assistant professor, 0 otherwise).
Interpret these results
Variable=Intercept, Coefficient= -3,816,521, t= -29.4, p= .000
Variable=Year, Coefficient= 1,948, t= 29.8, p= .000
Variable=Year/Hire, Coefficient= -826, t= -5.5, p= .000
Variable=Race, Coefficient= -2,093, t= -4.3, p= .000
Variable=Rank, Coefficient= -6,438, t= -22.3, p= .000
R2=0.811, R2adj=0.809, s=3,318
Thank you
Click here to see answer by stanbon(75887) |
Question 134149: 38. The accounting department at Weston Materials, Inc., a national manufacturer of unattached garages, reports that it takes two construction workers a mean of 32 hours and a standard deviation of 2 hours to erect the Red Barn model. Assume the assembly times follow the normal distribution.
a. Determine the z values for 29 and 34 hours. What percent of the garages take between 32 hours and 34 hours to erect?
b. What percent of the garages take between 29 hours and 34 hours to erect?
c. What percent of the garages take 28.7 hours or less to erect?
d. Of the garages, 5 percent take how many hours or more to erect?
44. The number of passengers on the Carnival Sensation during one-week cruises in the Caribbean follows the normal distribution. The mean number of passengers per cruise is 1,820 and the standard deviation is 120.
a. What percent of the cruises will have between 1,820 and 1,970 passengers?
b. What percent of the cruises will have 1,970 passengers or more?
c. What percent of the cruises will have 1,600 or fewer passengers?
d. How many passengers are on the cruises with the fewest 25 percent of passengers?
Click here to see answer by stanbon(75887) |
Question 133946: You are the incoming inspector for potato chips – you are to ensure that each bag has 16 ounces or more in it. You want your testing to be at the level of significance of 0.05. You pull a sample of 49 bags of chips from a recent truckload. Your sample statistics are:
x-bar (the sample mean) = 15.9 ounces
s ( the sample standard deviation) = 0.35 ounces
(a) what is the null and alternative hypothesis
(b) one or two tailed test ??
(c) what is the critical z value for your test at the 0.05 level of significance??
(d) what is the calculated z value ??
(e) what is your decision about the load of potato chips ??
-- reject ?? -- not-reject ??
Click here to see answer by stanbon(75887) |
Question 133927: A coin was flipped 60 times and came up heads 38 times. (a) At the .10 level of significance, is the coin biased toward heads? Show your decision rule and calculations. (b) Calculate a p-value and interpret it.
Click here to see answer by stanbon(75887) |
Question 134510: Please can someone help me? My homework is due soon and I am not sure what to do. These are my last two questions.
1) The probability that federal income tax returns will have 0,1, or two errors is 0.53,0.15, and 0.3 respectively. If 10 randomly selected returns are audited, what is the probablity that six will have no errors, three will have one error, and one will have two errors?
A)0.184
B) 0.127
C) 0.020
D) 0.035
2) The probability that a person will have 0,1,or two dental checkups per year is 0.2,0.5, and 0.3 respectively. If seven people are picked at random, what is the probablity that two will have no checkup, four willl have one checkup and one will have two checkups in the next year?
A) 0.079
B) 0.013
C) 0.008
D) 0.043
Any and all help will be greatly appreciated. I am not sure at all how to approach these questions and to be honest, I really don't understand them.
Click here to see answer by stanbon(75887) |
Question 134429: You are the Vice President for Human Resources at XYZ Investment Management, Inc. Your employees have recently complained about their long working hours. You collected a sample of 25 weekly timesheets and calculated an average of 41.5 hours with a standard deviation of 2.5 hours.
Over lunch, you discuss this problem with your long-time college friend working for Bayview Financial. She points out that in her company, the employees work an average of 42 hours. The data that she recently collected included timesheets for 35 employees. She calculated a standard deviation of 3.
1. Which test do you have to use in order to answer the question: “Do the employees at XYZ Investment Management on average work fewer hours than the employees at Bayview Financial?”
Please circle the correct answer:
A. Two-sample test of means (large sample)
B. Two-sample test of means (small sample)
C. T-test of one mean
D. Two sample test of proportions
2. Please state your hypotheses, H0 and Ha, and perform the hypothesis test using the 5-step testing procedure [alpha = 0.05].
Click here to see answer by stanbon(75887) |
Question 134428: 15.28 Can people really identify their favorite brand of cola? Volunteers tasted Coca-Cola Classic, Pepsi, Diet Coke, and Diet Pepsi, with the results shown below. Research question: At a = .05, is the correctness of the prediction different for the two types of cola drinkers? Since it is a 2 x 2 table, try also a two-tailed two-sample z test for π1 = π2 and verify that z˛ is the same as your chi-square statistic.
Correct? Regular Diet Row Total
Yes 7 7 14
No 12 20 32
Total 19 27 46
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Question 134515: In a bumper test, three types of autos were deliberately crashed into a barrier at 5 mph, and the resulting damage (in dollars) was estimated.Five test vehicles of each type were crashed, with the results shown below. Research question: Are the mean crash damages the same for these three vehicles? Crash1
Crash Damage ($)
Goliath Varmint Weasel
1,600 1,290 1,090
760 1,400 2,100
880 1,390 1,830
1,950 1,850 1,250
1,220 950 1,920
Click here to see answer by stanbon(75887) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 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