Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 480257: A bag contains 6 red, 4 white and 8 blue balls. If 3 balls are drawn at random, determine the probability p that at least 1 is red.
Here is how I did it:
P(at least 1 Red) = ?
3 drawings
Probability that 1 is Red in any trial = (1/18)X6 = 1/3
Probability that 1 is NOT Red in any trial = q = 1 - p = 1 - 1/3 = 2/3
Probability that 1 is NOT Red in 3 drawings = (2/3)X(2/3)X(2/3) = 8/27.
Hence the probability of getting at least 1 Red in 3 drawings = 1-(8/27)= 19/27 = 0.70
However, the textbook's answer and the solving method are different:
Probability that none is Red = [(4+8)C3]/18C3 = 55/204
Hence the probability that at least 1 is Red = 1-(55/204) = 149/204 = 0.73
Could you tell me why is my method wrong? I used the method because a similar problem in my textbook was solved using it. If you like here is the problem I am referring to:
What is the probability of getting at least 1 ace in 2 throws of a die?
The probability of getting an ance in any single throw = 1/6.
The probability of NOT getting an ace in any single throw = 1-(1/6)=5/6.
The probability of not getting an ace in 2 throws = (5/6)X(5/6)=25/36.
Hence the probability of getting at least 1 ace in 2 throws = 1-(25/36)=11/36.
What is the difference between the two types of problems and why my method did not work?
Thank you so much.
Have a nice evening.
Respectfully,
Ivanka
Click here to see answer by solver91311(24713)   |
Question 480583: 1. Find the five number summary of the following set of numbers:
12,4,11,17,5,13,5,3,9,5,
2. Complete the statement using < or > 7/16 of 0.438
Click here to see answer by solver91311(24713) |
Question 480594: Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, separated by a comma. A standard deck of cards has 12 face cards and four Aces (Aces are not face cards)
A. rolling a sum of 4 on two fair six sided dice
B. drawing a black seven out of a standard 52 card deck given it's not a face card of an Ace.
C. rolling a sum of 11 on two fair six sided dice.
D. rolling a sum of 7 on two fair six sided dice.
E. drawing a three out of a standard 52 card deck given it's not a face card or an Ace.
Click here to see answer by ewatrrr(24785)  |
Question 480777: You are given the sample mean and the sample standard deviation. Use this information to sonstruct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
A random sample of 40 eight- ounce servings of different juice drinks has a mean of 99.1 calories and a
Atandard deviation of 48.5 calories.
The 90% confidence interval is (__,__). (round to one decimal place as needed.)
Click here to see answer by stanbon(75887) |
Question 480841: A restaurant has 10 choices for appetizers, 20 choices for the main course, and 12 choices for the dessert. Of the 12 desserts half of them are sugar-free.
What is the probability that a person chooses 3 appetizers, 2 main course items, and 2 desserts in such a way that exactly both are sugar-free?
Click here to see answer by Theo(13342)  |
Question 480981: Seriously need help with this question ASAP!!!! Find the probabilit that a data value picked at random from a normally distributed population will have a standard score that corresponds to the following: Less than 3.00
Click here to see answer by stanbon(75887) |
Question 480952: A manufacturer of window frames knows from long experience that 5 percent of the production will have some type of minor defect that will require and adjustment. What is the probability that in a sample of 20 window frames:
a. None will need adjustment?
b. At least one will need adjustment?
c. More than two will need adjustment?
I know this is binomial but I am still having trouble solving the problem. Could some please help me and Thank you very much.
Click here to see answer by stanbon(75887) |
Question 481037: Find the minimum sample size n needed to estimate µ for the given values of c,s, and E.
C=0.90, s=5.7, and E=2
Asume that a preliminary sample has at least 30 members.
N=__(round up to the nearest whole number.)
Click here to see answer by stanbon(75887) |
Question 481041: People were polled on how many book they read the previous year. How many subjects are needed to estimate the number of books read the previous year within one book with 99% confidence? Initial survey results indicate that σ=1 books.
A 99% confidence level requires ___subjects.
(round up to the nearest whole number as needed.)
Click here to see answer by stanbon(75887) |
Question 481042: A doctor wants to estimate the HDL cholesterol of all 20-to 29- year-old females. How many sunjects are needed to estimate the HDL cholesterol within 3 point with 99% confidence assumming σ=15.4?
Suppose the doctor would be content with 95% confidence. How does thedecrease in confidence affect the sample size required?
A 99% confidences level level requires ___subjects.
(Round up to the nearest whole number as needed.)
Click here to see answer by stanbon(75887) |
Question 481040: You are given the sample mean and the sample standard deviation. Use this information to sonstruct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
A random sample of 40 eight- ounce servings of different juice drinks has a mean of 99.1 calories and a
Atandard deviation of 48.5 calories.
The 90% confidence interval is (__,__). (round to one decimal place as needed.)
Click here to see answer by stanbon(75887) |
Question 481053: I have no idea where to start with problem. I appreciate any guidance on this problem.
The probability that a randomly selected person has type A blood is 42%
Find the probability that in a sample of 10 blood donors, the number of type A donors is within one standard deviation of the expected value. Please show work.
a. 66.1%
b. 68.3%
c. 79.8%
d. 88.2%
Click here to see answer by stanbon(75887) |
Question 481028: Following are the American College Test (ACT) scores attained by the 25 members of a local high school graduating class:
21 24 23 17 31 19 19 20 19 25 17 23 16
21 20 28 25 25 21 14 19 17 18 28 20
Find P5, P10, and P20 for the ACT scores.
Click here to see answer by stanbon(75887) |
Question 480975: 2. Please show all of your work when answering the following:
I. Use Chebyshev’s theorem to find what percent of the values will fall between 252 and 336 for a data set with a mean of 294 and standard deviation of 14.
II. Use the Empirical Rule to find what two values 95% of the data will fall between for a data set with a mean of 223 and standard deviation of 11
Click here to see answer by stanbon(75887) |
Question 481075: ANOVA and Post Hoc Tests
Conduct an ANOVA comparing the anxiety levels (at posttest only) of participants across all three treatment conditions: CBT, psychodynamic, and supportive therapy.
Conduct post hoc tests, if needed. Report your analyses
Time
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Pre
Post
Follow-up
Treatment
CBT
CBT
CBT
PSY
PSY
PSY
SUPP
SUPP
SUPP
CBT
CBT
CBT
PSY
PSY
PSY
SUPP
SUPP
SUPP
CBT
CBT
CBT
PSY
PSY
PSY
SUPP
SUPP
SUPP
Please help me with this assignment.
Click here to see answer by stanbon(75887) |
Question 481058: Consider a large population with a mean of 100 and a standard deviation of 21. A random sample of size 36 is taken from this population. The standard error of the sampling distribution of sample means is equal to:
A) 16.67
B) 12.25
C) 3.50
D) 1.71
Click here to see answer by robertb(5830)  |
Question 481060: A certain population has a mean of 500 and a standard deviation of 30. Many samples of size 36 are randomly selected and the means are calculated.
What value would you expect to find for the mean of all these samples means? (round to the nearest integer)
What value would you expect to find for the standard deviation of all these sample means? (round to the nearest integer)
True of False, you would expect the shape of the sampling distribution to be approximately normal
Click here to see answer by stanbon(75887) |
Question 481082: In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
a. All nine have color TVs?
b. Less than five have color TVs?
c. More than five have color TVs?
d. At least seven homes have color TVs?
I am confused I was told this problem is Binomial but I can't seem to solve it can someone please help me out please. Thank you very much.
Click here to see answer by stanbon(75887) |
Question 481091: The probability that event A will occur is 40%, while the probability that event B will occur is 60%.
What is the probability that event A or event B will occur, if the events are indendent?
a. 20%
b. 24%
c. 76%
d. 100%
Thank you .
Click here to see answer by stanbon(75887) |
Question 481091: The probability that event A will occur is 40%, while the probability that event B will occur is 60%.
What is the probability that event A or event B will occur, if the events are indendent?
a. 20%
b. 24%
c. 76%
d. 100%
Thank you .
Click here to see answer by robertb(5830) |
Question 481093: Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9.
What is the probability that Person B hit the target given that both of them fired and exactly one shot hit the target?
a. 0.18
b. 0.30
c. 0.69
d. 0.90
I came up with .50*.80 =.40 and .50*.90=.45 thus .40*.45=0.18 Is this correct?
Thank you
Click here to see answer by stanbon(75887) |
Question 481093: Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9.
What is the probability that Person B hit the target given that both of them fired and exactly one shot hit the target?
a. 0.18
b. 0.30
c. 0.69
d. 0.90
I came up with .50*.80 =.40 and .50*.90=.45 thus .40*.45=0.18 Is this correct?
Thank you
Click here to see answer by robertb(5830) |
Question 481108: A survey of 750 workers were asked how much they use the internet at work. 456 said they used it within limits, and 166 said they did not use the Internet at work.
a. Construct a 95% confidence interval estimate for the proportion of all workers who use it within limits.
b. Construct the same for those who did not use the internet.
Click here to see answer by stanbon(75887) |
Question 481101: Please help me solve:
A stationery store wants to estimate the mean retail value of greeting cards that it has in its inventory. A random sample of 121 greeting cards indicates a mean value of $3.92 and a standard deviation of $0.45.
a. Assuming a normal distribution, construct a 90% confidence interval estimate of the mean value of all greeting cards in the store's inventory.
b. Suppose there were 3,000 greeting cards in the inventory. How are the results useful in assisting the owner to estimate the total value of her inventory.
Click here to see answer by stanbon(75887) |
Question 481140: If you want to be 95% confident of estimating the population mean to within a sampling error of + or - 2, the standard deviation is assumed to be 13, what is the required sample size?
Round to the nearest integer.
Click here to see answer by ewatrrr(24785) |
Question 481170: An executive committee consists of 15 members, 7 men and 8 women. 4 members are selected at random to attend a meeting in Hawaii. The names are drawn from a hat. What is the probability that all 4 selected are women.
Thank you
Click here to see answer by ewatrrr(24785) |
Question 481265: An automobile assembly line operation has a scheduled mean completion time of 14.7 minutes. The standard deviation of completion times is 1.7 minutes. It is claimed that, under new management, the mean completion time has decreased. To test this claim, a random sample of 80 completion times under new management was taken. The sample had a mean of 14.2 minutes. Can we support, at the 0.01 level of significance, the claim that the mean completion time has decreased under new management? Assume that the standard deviation of completion times has not changed. The value of the test statistic (round to at least 3 decicmal places)? The p-value(round to at least 3 decimal places)?
Click here to see answer by stanbon(75887) |
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33526..33570, 33571..33615, 33616..33660, 33661..33705, 33706..33750, 33751..33795, 33796..33840, 33841..33885, 33886..33930, 33931..33975, 33976..34020, 34021..34065, 34066..34110, 34111..34155, 34156..34200, 34201..34245, 34246..34290, 34291..34335, 34336..34380, 34381..34425, 34426..34470, 34471..34515, 34516..34560, 34561..34605, 34606..34650, 34651..34695, 34696..34740, 34741..34785, 34786..34830, 34831..34875, 34876..34920, 34921..34965, 34966..35010, 35011..35055, 35056..35100, 35101..35145, 35146..35190, 35191..35235, 35236..35280, 35281..35325, 35326..35370, 35371..35415, 35416..35460, 35461..35505, 35506..35550, 35551..35595, 35596..35640, 35641..35685, 35686..35730, 35731..35775, 35776..35820, 35821..35865, 35866..35910, 35911..35955, 35956..36000, 36001..36045, 36046..36090, 36091..36135, 36136..36180, 36181..36225, 36226..36270, 36271..36315, 36316..36360, 36361..36405, 36406..36450, 36451..36495, 36496..36540, 36541..36585, 36586..36630, 36631..36675, 36676..36720, 36721..36765, 36766..36810, 36811..36855, 36856..36900, 36901..36945, 36946..36990, 36991..37035, 37036..37080, 37081..37125, 37126..37170, 37171..37215, 37216..37260, 37261..37305, 37306..37350, 37351..37395, 37396..37440, 37441..37485, 37486..37530, 37531..37575, 37576..37620, 37621..37665, 37666..37710, 37711..37755, 37756..37800, 37801..37845, 37846..37890, 37891..37935, 37936..37980, 37981..38025, 38026..38070, 38071..38115, 38116..38160, 38161..38205, 38206..38250, 38251..38295, 38296..38340, 38341..38385, 38386..38430, 38431..38475, 38476..38520, 38521..38565, 38566..38610, 38611..38655, 38656..38700, 38701..38745, 38746..38790, 38791..38835, 38836..38880, 38881..38925, 38926..38970, 38971..39015, 39016..39060, 39061..39105, 39106..39150, 39151..39195, 39196..39240, 39241..39285, 39286..39330, 39331..39375, 39376..39420, 39421..39465, 39466..39510, 39511..39555, 39556..39600, 39601..39645, 39646..39690, 39691..39735, 39736..39780, 39781..39825, 39826..39870, 39871..39915, 39916..39960, 39961..40005, 40006..40050, 40051..40095, 40096..40140, 40141..40185, 40186..40230, 40231..40275, 40276..40320, 40321..40365, 40366..40410, 40411..40455, 40456..40500, 40501..40545, 40546..40590, 40591..40635, 40636..40680, 40681..40725, 40726..40770, 40771..40815, 40816..40860, 40861..40905, 40906..40950, 40951..40995, 40996..41040, 41041..41085, 41086..41130, 41131..41175, 41176..41220, 41221..41265, 41266..41310, 41311..41355, 41356..41400, 41401..41445, 41446..41490, 41491..41535, 41536..41580, 41581..41625, 41626..41670, 41671..41715, 41716..41760, 41761..41805, 41806..41850, 41851..41895, 41896..41940, 41941..41985, 41986..42030, 42031..42075, 42076..42120, 42121..42165, 42166..42210, 42211..42255, 42256..42300, 42301..42345, 42346..42390, 42391..42435, 42436..42480, 42481..42525, 42526..42570, 42571..42615, 42616..42660, 42661..42705, 42706..42750, 42751..42795, 42796..42840, 42841..42885, 42886..42930, 42931..42975, 42976..43020, 43021..43065, 43066..43110, 43111..43155, 43156..43200, 43201..43245, 43246..43290, 43291..43335, 43336..43380, 43381..43425, 43426..43470, 43471..43515, 43516..43560, 43561..43605, 43606..43650, 43651..43695, 43696..43740, 43741..43785, 43786..43830, 43831..43875, 43876..43920, 43921..43965, 43966..44010, 44011..44055, 44056..44100, 44101..44145, 44146..44190, 44191..44235, 44236..44280, 44281..44325, 44326..44370, 44371..44415, 44416..44460, 44461..44505, 44506..44550, 44551..44595, 44596..44640, 44641..44685, 44686..44730, 44731..44775, 44776..44820, 44821..44865, 44866..44910, 44911..44955, 44956..45000, 45001..45045, 45046..45090, 45091..45135, 45136..45180, 45181..45225, 45226..45270, 45271..45315, 45316..45360, 45361..45405, 45406..45450, 45451..45495, 45496..45540, 45541..45585, 45586..45630, 45631..45675, 45676..45720, 45721..45765, 45766..45810, 45811..45855, 45856..45900, 45901..45945, 45946..45990, 45991..46035, 46036..46080, 46081..46125, 46126..46170, 46171..46215, 46216..46260, 46261..46305, 46306..46350, 46351..46395, 46396..46440, 46441..46485, 46486..46530, 46531..46575, 46576..46620, 46621..46665, 46666..46710, 46711..46755, 46756..46800, 46801..46845, 46846..46890, 46891..46935, 46936..46980, 46981..47025, 47026..47070, 47071..47115, 47116..47160, 47161..47205, 47206..47250, 47251..47295, 47296..47340, 47341..47385, 47386..47430, 47431..47475, 47476..47520, 47521..47565, 47566..47610, 47611..47655, 47656..47700, 47701..47745, 47746..47790, 47791..47835, 47836..47880, 47881..47925, 47926..47970, 47971..48015, 48016..48060, 48061..48105, 48106..48150, 48151..48195, 48196..48240, 48241..48285, 48286..48330, 48331..48375, 48376..48420, 48421..48465, 48466..48510, 48511..48555, 48556..48600, 48601..48645, 48646..48690, 48691..48735, 48736..48780, 48781..48825, 48826..48870, 48871..48915, 48916..48960, 48961..49005, 49006..49050, 49051..49095, 49096..49140, 49141..49185, 49186..49230, 49231..49275, 49276..49320, 49321..49365, 49366..49410, 49411..49455, 49456..49500, 49501..49545, 49546..49590, 49591..49635, 49636..49680, 49681..49725, 49726..49770, 49771..49815, 49816..49860, 49861..49905, 49906..49950, 49951..49995, 49996..50040, 50041..50085, 50086..50130, 50131..50175, 50176..50220, 50221..50265, 50266..50310, 50311..50355, 50356..50400, 50401..50445, 50446..50490, 50491..50535, 50536..50580, 50581..50625, 50626..50670, 50671..50715, 50716..50760, 50761..50805, 50806..50850, 50851..50895, 50896..50940, 50941..50985, 50986..51030, 51031..51075, 51076..51120, 51121..51165, 51166..51210, 51211..51255, 51256..51300, 51301..51345
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