SOLUTION: 12,500 | 17,700 | 22,300 14,800 | 19,400 | 24,800 15,200 | 20,200 | 27,600 15,300 | 21,200 | 28,200 15,900 | 22,100 | 35,200 If the average and standard deviatio

Algebra ->  Probability-and-statistics -> SOLUTION: 12,500 | 17,700 | 22,300 14,800 | 19,400 | 24,800 15,200 | 20,200 | 27,600 15,300 | 21,200 | 28,200 15,900 | 22,100 | 35,200 If the average and standard deviatio      Log On


   



Question 1167732: 12,500 | 17,700 | 22,300
14,800 | 19,400 | 24,800
15,200 | 20,200 | 27,600
15,300 | 21,200 | 28,200
15,900 | 22,100 | 35,200
If the average and standard deviation of their components are 20,860 and 6, 168 respectively, determine the corresponding for the (use chebyshev theorem)
a.) 2nd standard deviation at the left side of the mean

Answer by CPhill(1959) About Me  (Show Source):
You can put this solution on YOUR website!
To determine the value corresponding to the 2nd standard deviation at the left side of the mean, we will use the given average (mean) and standard deviation.
**Given:**
* Average (Mean, $\mu$) = 20,860
* Standard Deviation ($\sigma$) = 6,168
We need to find the value that is 2 standard deviations to the left (below) the mean.
**Calculation:**
Value = $\mu - 2\sigma$
Value = $20,860 - 2 \times 6,168$
Value = $20,860 - 12,336$
Value = $8,524$
The value corresponding to the 2nd standard deviation at the left side of the mean is 8,524.