SOLUTION: The police notice 5 drunken drivers daily in average with the variance 4, independently everyday. What is the probability that they catch over 1900 drunken drivers yearly?
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-> SOLUTION: The police notice 5 drunken drivers daily in average with the variance 4, independently everyday. What is the probability that they catch over 1900 drunken drivers yearly?
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Question 1105746: The police notice 5 drunken drivers daily in average with the variance 4, independently everyday. What is the probability that they catch over 1900 drunken drivers yearly?
You can put this solution on YOUR website! 1900/365 = 5.2 daily
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assume a normal distribution
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z-score = (5.2 - 5) / 4 = 0.05
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checking table of z-scores, we find
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Probability (P) ( X < 5.2 ) = 0.5199
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P ( X > 5.2 ) = 1 - 0.5199 = 0.4801 approximately 0.48
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