SOLUTION: Given the following hypotheses: H0 : μ = 400 H1 : μ ≠ 400 A random sample of 12 observations is selected from a normal population. The

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Question 997662: Given the following hypotheses:

H0 : μ = 400

H1 : μ ≠ 400


A random sample of 12 observations is selected from a normal population. The sample mean was 407 and the sample standard deviation 6. Using the .01 significance level:


a.
State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.)


Reject H0 when the test statistic is (Click to select)insideoutside the interval (, ).

b. Compute the value of the test statistic. (Round your answer to 3 decimal places.)

Value of the test statistic

c. What is your decision regarding the null hypothesis?


Do not reject
Reject

So far I have t=xbar-mean/s squareroot6
Having trouble understanding how to find all of it, im so lost... :.(

Answer by MathTherapy(10552) About Me  (Show Source):
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Given the following hypotheses: 

H0 : μ = 400 

H1 : μ ≠ 400 

A random sample of 12 observations is selected from a normal population. The sample mean was 407 and the sample standard deviation 6. Using the .01 significance level:

a. 
State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.)
 
Reject H0 when the test statistic is (Click to select)insideoutside the interval (,  ). 

b. Compute the value of the test statistic. (Round your answer to 3 decimal places.) 

Value of the test statistic    

c. What is your decision regarding the null hypothesis? 
    
Do not reject 
Reject 
 
So far I have t=xbar-mean/s squareroot6

Having trouble understanding how to find all of it, im so lost... :.(

a.
Decision rule: Reject null or H%5Bo%5D if the test statistic is OUTSIDE the interval: - 3.106 to 3.106
b.
t%5Bstat%5D+=++%28XBbar+-+mu%29%2F%28s%2Fsqrt%28n%29%29
t%5Bstat%5D+=+%28407+-+400%29%2F%286%2Fsqrt%2812%29%29
t%5Bstat%5D+=+7%2F%286%2F3.464102%29
t%5Bstat%5D+=+7%2F1.732051
highlight_green%28t%5Bstat%5D+=+4.041%29
c.
With significance level (α) of .01, and degree of freedom of 11 (12 – 1), the t-critical values are: - 3.106 and 3.106.
The test statistic: 4.041 is greater than the right t-critical value: 3.106, and therefore falls in the reject region
Decision: Reject null or Reject H%5Bo%5D: μ = 400.
There is sufficient evidence to warrant the rejection of the null hypothesis that: H%5Bo%5D+=+400