SOLUTION: Here are the numbers of days that each car in a select group spent in an airport parking lot. 3, 2, 4, 3, 4, 2, 3, 4, 5, 3, 4, 2, 6, 8, 11, 12, 3, 2, 1, 3, 4, 4, 5, 9, 10, 11, 4

Algebra ->  Probability-and-statistics -> SOLUTION: Here are the numbers of days that each car in a select group spent in an airport parking lot. 3, 2, 4, 3, 4, 2, 3, 4, 5, 3, 4, 2, 6, 8, 11, 12, 3, 2, 1, 3, 4, 4, 5, 9, 10, 11, 4       Log On


   



Question 988398: Here are the numbers of days that each car in a select group spent in an airport parking lot. 3, 2, 4, 3, 4, 2, 3, 4, 5, 3, 4, 2, 6, 8, 11, 12, 3, 2, 1, 3, 4, 4, 5, 9, 10, 11, 4
(a) are the data normally distributed? Explain.
(b) The mean of the data is 4.9 days with a standard deviation of 3.1 days. The parking lot manager said that 68% of the cars park between 1/8 and 8 days. "Evaluate the manager's statement.
Answer:

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
1
2222
333333
4444444
55
6
8
9
10
11/11
12
;
This is a stem and leaf plot, and if you look at it at a 90 degree angle, this is not normally distributed. It is skewed right.
The manager's statement works only if the data are normally distributed. We can say that no more than 1/k^2 of the cars will be more than k standard deviations away, Chebyshev's inequality. That means that conceivably a quarter of the cars could be more than 2 standard deviations away, but no more.