SOLUTION: How many different 9 player baseball teams can be formed from 15 players if 3 only pitch while the remaining 12 can play any of the 8 remaining positions?
I really do not have a
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I really do not have a
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Question 98082: How many different 9 player baseball teams can be formed from 15 players if 3 only pitch while the remaining 12 can play any of the 8 remaining positions?
I really do not have a clue how to solve. I tried to use different types of combination things that i had learned in class, but it has too many variables for it.
You can put this solution on YOUR website! How many different 9 player baseball teams can be formed from 15 players if 3 only pitch while the remaining 12 can play any of the 8 remaining positions?
I really do not have a clue how to solve.
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Pick a pitcher in 3 ways
Pick the remaining 8 players: 12C8 = 12C4 = 495 ways
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# of teams = 3*495 = 1485
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Cheers,
Stan H.
You can put this solution on YOUR website! you can select a pitcher among the three available in
3C1 way. the remaining 8 have to be selected from 12 players
number of ways of selecting the remaining 8 players is 12C8
total combination of teams possible = 3C1 * 12C8
= 3 * (12*11*10*9)/(4*3*2*1)
=1350
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