Question 957636: solve using the standard normal distribution as an approximation to the binomial distribution. salesperson s. is successful, that is makes a sale, in an average of 35% of their calls. to win a special award, s. must average 50% sales for the next week. if they make 50 calls next week, what is the probability that they will make fewer than 25 sales and fail to win the award? draw a picture to start out with!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve using the standard normal distribution as an approximation to the binomial distribution. salesperson s. is successful, that is makes a sale, in an average of 35% of their calls. to win a special award, s. must average 50% sales for the next week. if they make 50 calls next week, what is the probability that they will make fewer than 25 sales and fail to win the award? draw a picture to start out with!!
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u = np = 50*0.35 = 17.5
s = sqrt(17.5*0.65) = 3.3726
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z(24.5) = (24.5-17.5)/3.3726) = 2.0755
P(x < 25) = P(z < 2.0755) = normalcdf(-100,2.0755) = 0.9810
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Cheers,
Stan H.
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