SOLUTION: Two out of three mothers choose peanut butter. If a dozen mothers are selected at random what is the probability that at least one chooses peanut butter. PLEASE ANSWER THIS - I

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Question 953050: Two out of three mothers choose peanut butter. If a dozen mothers are selected at random what is the probability that at least one chooses peanut butter.
PLEASE ANSWER THIS - I have tried several times to get this answered to no avail - PLEASE< PLEASE HELP!!!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Ask yourself:
What is the probability that NONE of the mothers
will choose peanut butter? Call this
probability P(0)
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The probability that AT LEAST ONE mother chooses
peanut butter is whatever probability is left over, or
+1+-+P%280%29+
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I say that
+P%280%29+ = ( not PB ) x ( not PB ) x ( not PB ) . . . for all 12 mothers
+P%280%29+=+%281%2F3%29%5E12+
+P%280%29+=+.000001881+
+1+-+.000001881+=+.999998118+
So, the probability is:
.999998118
Definitely get another opinion on this
but I think I'm right