SOLUTION: four mints, six caramels, and two orange creams. If two are chosen in succession, what is the probability that the first one is caramel and the second is mint?
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Question 948374: four mints, six caramels, and two orange creams. If two are chosen in succession, what is the probability that the first one is caramel and the second is mint? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! four mints, six caramels, and two orange creams. If two are chosen in succession, what is the probability that the first one is caramel and the second is mint?
Ans: (6/12)(4/11) = 6/33 = 2/11
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Cheers,
Stan H.
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