SOLUTION: Suppose that an unfair coin comes up heads 53.7% of the time. The coin is flipped a total of 17 times. a.) What is the probability that you get exactly 10 tails? b.) What is the

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose that an unfair coin comes up heads 53.7% of the time. The coin is flipped a total of 17 times. a.) What is the probability that you get exactly 10 tails? b.) What is the       Log On


   



Question 947926: Suppose that an unfair coin comes up heads 53.7% of the time. The coin is flipped a total of 17 times.
a.) What is the probability that you get exactly 10 tails?
b.) What is the probability that you get at most 15 heads?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that an unfair coin comes up heads 53.7% of the time. The coin is flipped a total of 17 times.
Binomial Problem with n = 17 and p(heads) = 0.537
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a.) What is the probability that you get exactly 10 tails?
Ans: P(x = 10) = 17C10*0.537^10*0.463^7 = binompdf(17,0.537,10) = 0.1770
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b.) What is the probability that you get at most 15 heads?
Ans: P(0<= x <= 15) = binomcdf(17,0.537,15) = 0.9996
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Cheers,
Stan H.
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