Question 94739This question is from textbook Introductory algebra
: A triangular region has a perimeter of 66 meters. The first side is two-thirds of the second side. The third side is 14 meters shorter than the second side. What are the lengths of the three sides of the triangular region?
This question is from textbook Introductory algebra
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Let x = length of the 2nd side
:
It says," The first side is two-thirds of the second side." Therefore:
1st side = 2x/3
:
It also says,"The third side is 14 meters shorter than the second side." Therefore:
3rd side = (x-14)
:
What are the lengths of the three sides of the triangular region?
It says "A triangular region has a perimeter of 66 meters." Therefore:
:
side 1 + side 2 + side 3 = 66
(2x/3) + x + (x-14) = 66
:
Multiply equation by 3 to get rid of the denominator:
2x + 3x + 3(x-14) = 3(66)
2x + 3x + 3x - 42 = 198
8x = 198 + 42
8x = 240
x = 240/8
x = 30 m, the length of side 2
:
2/3(30) = 20 m, the length of side 1
:
30 - 14 = 16m, the length of side 3
:
:
Check solution, using the perimeter:
20 + 16 + 30 = 66
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