SOLUTION: assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. if P(-a<z<a)=0.4314, find a.
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-> SOLUTION: assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. if P(-a<z<a)=0.4314, find a.
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You can put this solution on YOUR website! assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. if P(-a
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Note: 0.4314 is area under the normal curve centered on z = 0.
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(.4314)/2 = 0.2157 is area to the right of the mean
and 0.2157 is area to the left of the mean.
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That leaves a left tail of 0.5-0.2157 = 0.2843
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-a = invNorm(0.2843) = -0.5701
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Ans: a = 0.5701
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Cheers,
Stan H.
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