SOLUTION: According to the data published by the U.S. Dept. of Agriculture, the average annual amount of chicken eaten by American adults (excluding vegetarians) is normally distributed with

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Question 929439: According to the data published by the U.S. Dept. of Agriculture, the average annual amount of chicken eaten by American adults (excluding vegetarians) is normally distributed with a mean of 55 pounds and a standard deviation of 9.2 pounds.

If a randomly selected American adult (excluding vegetarians) is selected, what is the probability that this adult eats at least 52 pounds of chicken per year.

A .13
B .26
C .37
D .63
E .73
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
mean= 55lb, SD = 9.2 pounds. z+=+blue%28x+-+55%29%2Fblue%289.2%29
P(x ≥ 52) = P(z > -3/9.2) = normalcdf(-3/9.2, 100) = .6278 0r 62.78%
D