Question 925783: A previous finding states that thirty-five percent of adults Americans are regular voters. A new survey was conducted. A random sample of 250 adults in a medium size college town were surveyed , and it was found that 110 were regular voters. Estimate the true proportion of regular voters with 90% confidence
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! Ho: p = .35 (claim)
Ha: p ≠ .35
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re TY, No, do a z-stat... .44 did not happen by accident...claim is rejected
sample: phat = 110/250 = .44
z(.44) = ( .44-.35)/sqrt[0.35*.65/250] = .09/.03 = 3 (Off the charts)
p(z > 3) = .001 < .10 Reject Ho
.....
Estimate the true proportion of regular voters with 90% confidence
ME = 1.645 sqrt[0.35*.65/250] = .049 (Used the old .35 here to calculate ME)
CI: .44 - .05 < u < .44 + .05 (Used the .44 here)
CI: (.39, .49)
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