SOLUTION: Two marbles are drawn from a box containing 3 yellow, 4 white and 8 blue marbles without replacement. Find the probability of drawing 1. at least one yellow marble 2.at most one

Algebra ->  Probability-and-statistics -> SOLUTION: Two marbles are drawn from a box containing 3 yellow, 4 white and 8 blue marbles without replacement. Find the probability of drawing 1. at least one yellow marble 2.at most one       Log On


   

Question 924352: Two marbles are drawn from a box containing 3 yellow, 4 white and 8 blue marbles without replacement. Find the probability of drawing
1. at least one yellow marble
2.at most one yellow marble?
3.both marbles are the same color?
4. one of the marbles is blue and the other is white?
5. the marbles are of two different colors?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
15 marbles: 3Y, 4W, 8B
Two marbles are drawn w/o replacement
...
P(at least one yellow marble) = 1 - P(no yellow) = 1 - %2812%2F15%29%2811%2F14%29
...
P(at most one yellow marble) = Y1st + Y2nd = +%283%2F15%29%2812%2F14%29+%2B+%2812%2F15%29%283%2F14%29=+72%2F%2814%2A15%29%29++
...
P(both marbles are the same color) = 2Y+2W+2R =
...
P(B and W) = +%288%2F15%29%284%2F14%29+%2B+%284%2F15%29%288%2F14%29=+64%2F%2814%2A15%29%29++
...
P(marbles are of two different colors) = 1 - P(same color) = 1 - 74%2F%2814%2A15%29