SOLUTION: 1(b) The average number of mosquitoes in a stagnant pond is 70 per square meter with a standard deviation of 8. If 36 square meters are chosen at random for a mosquito count, find

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Question 923903: 1(b) The average number of mosquitoes in a stagnant pond is 70 per square meter with a standard deviation of 8. If 36 square meters are chosen at random for a mosquito count, find the probability that the average of those counts is more than 70.9 mosquitoes per square meter. Assume that the variable is normally distributed, and place your final answer in decimal form.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
mean = 70 with a standard deviation of 8
sample: n = 36
z+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29
z(70.9) = .9%2F%288%2Fsqrt%2836%29%29 = .675
P(avg > 70.9) = P(z > .675) = normalcdf(.675, 100) = .2498
Using TI 0r similarly a Casio fx-115 ES plus