SOLUTION: A box has ten dollars, one of five dollars and four of one dollars. If two bills are chosen at random without replacement, find probability of getting Part A amount of valued of fi

Algebra ->  Probability-and-statistics -> SOLUTION: A box has ten dollars, one of five dollars and four of one dollars. If two bills are chosen at random without replacement, find probability of getting Part A amount of valued of fi      Log On


   



Question 923567: A box has ten dollars, one of five dollars and four of one dollars. If two bills are chosen at random without replacement, find probability of getting Part A amount of valued of fifteen dollars Part B amount valued of twelve dollars. Which two amounts more likely to be picked, you must compare your result to justify
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
6 Bills in a Box: $10(1), $5(1), $1(4)
two bills are chosen at random
A. P(sum = $15) = 2%281%2F6%29%281%2F5%29 = 1/15 ***possible to have sum = $15
B. P(sum = $12) = 0 (Picking 2 bills...not possible for sum = $12)