SOLUTION: The number of peanuts in bags is normally distributed with a mean of 184.7 peanuts and a standard deviation of 3.3 peanuts. What is the z-score of a bag containing 178 peanuts?

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Question 915019: The number of peanuts in bags is normally distributed with a mean of 184.7 peanuts and a standard deviation of 3.3 peanuts. What is the z-score of a bag containing 178 peanuts?
a.-1.42
b.-1.65
c.-2.03
d.-2.49
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
z = (178-184.7)/3.3 = -2.03