SOLUTION: men: A students: 11 B students:15 C students: 6 D students: 1 women : A students: 12 B students:10 C students:6 D students:3 A )Randomly choose 1 student from

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Question 912017: men:
A students: 11
B students:15
C students: 6
D students: 1

women :
A students: 12
B students:10
C students:6
D students:3

A )Randomly choose 1 student from the class. What is the probability that the student is an A student or a woman? Write your answer as a decimal rounded to 3 decimal places.
b) Randomly choose 1 student from the class. What is the probability that the student is an A student or a B student? Write your answer as a decimal.
c).Randomly choose 1 student from the class. What is the probability that the student is a male A student? Write your answer as a decimal rounded to 3 decimal places.
D).Randomly choose 1 student from the class. What is the probability that the student is a man? Write your answer as a decimal rounded to 3 decimal places
E).Randomly choose 1 student from the class. What is the probability that the student is not a B student? Write your answer as a decimal rounded to 3 decimal places.
F).Randomly choose 1 student from the class. What is the probability that the student is a B student given that they are a woman? Write your answer as a decimal rounded to 3 decimal places.
G).Randomly choose 2 students from the class (without replacement). What is the probability that the first student is a woman and the second is a man? Write your answer as a decimal rounded to 3 decimal places.

H).Randomly choose 2 students from the class (without replacement). What is the probability that the first student is an A student and the second student is a woman? Write your answer as a decimal rounded to 3 decimal places.
J).Randomly choose 2 students from the class (without replacement). What is the probability that both students are women? Write your answer as a decimal rounded to 3 decimal places
Please I'm not really looking for answers. I just want to know how to do this I've tried and I am soo fed up. Thank you
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

HIGHLY Recommend Chart with Totals: For ex: 64 total students

Re TY: Let the C hart talk to You and apply basic rules if necessary

	MEN	WOMAN	Tot

A	11	12	23

B	15	10	25

C	6	6	12

D	1	3	4

Tot	33	31	64

Choose 1

a)P(A student 0r a woman) = 23/64 + 31/64 - 12/64 = 42/64   P(A or B) = P(A) + P(B) - P(A and B)

b)P(A student 0r B student)= 23/64 + 25/64 P(A or B) = P(A) + P(B) (can't be both an A & a B student))

c)P(male A student )= 11/64

d)P( student is a man)= 33/64

e)P(student is not a B student )= 1 - P(B student)= 1- 25/64

f)P(B student | a woman )= %2810%2F64%29%2F%2831%2F64%29+=+10%2F34 P(A|B) = P(A and B)/P(B)

Choose 2 w/o replacement

g)P(first student is a woman AND the second is a man)= %2831%2F64%29%2833%2F63%29P(A and B) = P(A)•P(B) (WATCH TOTAL LEFT TO CHOOSE FROM)

h)P(first student is an A student AND the second student is a woman)= %2823%2F64%29%2830%2F63%29

i)P(both students are women(WOMAN and WOMAN)= %2831%2F64%29%2830%2F63%29

Inspect carefully...Let You finish Up...reducing fractions etc