Question 911875: Determine the probabilities for the following values assuming they
are normally distributed with μ=100 and σ2=36:
X ≤ 72
93 ≤ X ≤ 130
X ≥ 81
X ≥ 87
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! m = 100, sd = 6
Using TI Calculator
P(X ≤ 72 ) = normalcdf(-999, 72,100,6)
P(93 ≤ X ≤ 130 ) = normalcdf(93,130,100,6)
P(X ≥ 81 ) = normalcdf(81,999,100,4)
P(X ≥ 87 ) = normalcdf(87,999,100,4)
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