Question 901341: question - 1 A large insurance company has discovered
that 0.2% of the Delhi population is injured as a
result of particular type of accident. The company
has 15,000 policy holders carrying coverage
against such accident. What is the probability that
three or less claims will be filed against those
policy holders in the next year? Five or more
claim?
Question 2 - Suppose that the number of accidents
working on high explosive shells over a period of
time (say five) weeks is taken to follow a poisson
distribution with parameter X = 2. Find the
probability of 1, 2, 3, 4, or 5 accidents
Answer by ewatrrr(24785)   (Show Source):
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1 P(x≤3) = binomcdf(15000, .002, 3)
P(x≥ 5) = 1- P(x≤4) = 1 - binomcdf(15000, .002, 4)
Find the probability of 1, 2, 3, 4, or 5 accidents
over the same period of time (say five) weeks
2) P(x =1 ) = poissonpdf(2,1)
P(x =1 ) = poissonpdf(2,2)
etc
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