SOLUTION: The distribution of weekly salaries at a large company is reverse J-shaped with a mean of $1000 and a standard deviation of $370. What is the probability that the sampling error ma
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Question 892777: The distribution of weekly salaries at a large company is reverse J-shaped with a mean of $1000 and a standard deviation of $370. What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The distribution of weekly salaries at a large company is reverse J-shaped with a mean of $1000 and a standard deviation of $370. What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75?
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n = [z*s/E]^2
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80 = [z*370/75]^2
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sqrt(80) = 4.93z
z = 1.81
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P(z > 1.81) = 0.035
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Ans:: P(condition described) = 2*0.035) = 7%
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Cheers,
Stan H.
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