Question 891260: A Barrel has 20 $1, 10 $2, 5 $5, 3 $10, 1 $20 and 1 $100 dollar bill. What should we charge to make the game profitable for those in charge of the game?
Answer by Edwin McCravy(20054) (Show Source):
You can put this solution on YOUR website!
I will assume that a player gets to reach in the barrel and blindly
select 1 bill that he is allowed to keep.
There are 20+10+5+3+1+1 = 40 bills
Value Probability Expectation
of of = Value ×
Bill drawing Probability
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$1 20/40 = 1/2 $1×(1/2) = $0.50
$2 10/40 = 1/4 $2×(1/4) = $0.50
$5 5/40 = 1/8 $5×(1/8) = $0.625
$10 3/40 $10×(3/40) = $0.75
$20 1/40 $20×(1/40) = $0.50
$100 1/40 $100×(1/40) = $2.50
--------------------------------------------
Totals 40/40 = 1 $5.375
If a player plays the game many times, she/he will average
walking away with $5.375 each time. So to make the game
profitable to those in charge, they should charge more than
$5.375 to play. [For instance if they charge $10 to play,
they will average profiting $10.00 - $5.375 or $4.625 each
time someone plays.]
Edwin
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