Question 890995: if you have a contingency table x being 1,2,3,4,5,6,7 and probability being 0.25,0.32,0.17,.015,0.07,0.03,0.01 and you want to verify legitimate probablilty distribution, what is p(x=5) how do i write it out.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! if you have a contingency table x being 1,2,3,4,5,6,7 and probability being 0.25,0.32,0.17,0.15,0.07,0.03,0.01 and you want to verify legitimate probablilty distribution, what is p(x=5) how do i write it out.
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P(x = 1) = 0.25
P(x = 2) = 0.32
P(x = 3) = 0.17
P(x = 4) = 0.15
P(x = 5) = 0.07
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Cheers,
Stan H.
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