SOLUTION: I need help with part 2 of this question: A box contains 10 items, of which 3 are defective and 7 are non-defective. Two items are randomly selected, one at a time, with replace

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Question 889355: I need help with part 2 of this question:
A box contains 10 items, of which 3 are defective and 7 are non-defective. Two items are randomly selected, one at a time, with replacement, and x is the number of defectives in the sample of two. Explain why x is a binomial random variable.
For the first question about the box containing 10 items of which 3 are defective, what is the probability of any one selected item being non-defective?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A box contains 10 items, of which 3 are defective and 7 are non-defective. Two items are randomly selected, one at a time, with replacement, and x is the number of defectives in the sample of two. Explain why x is a binomial random variable.
For the first question about the box containing 10 items of which 3 are defective, what is the probability of any one selected item being non-defective?
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Ans:: Since the selections are replaced, p(non-defect) = 7/10
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Cheers,
Stan H.
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